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If we know the Volume, we can solve for the radius

V = pi X r^2 * h     divide both sides by pi * h

V /( pi * h) = r^2     take the positive square root of both sides

√[V /( pi * h) ]  = r

If we know the lateral surface area......we can do this

Sa = 2*pi*r * h     divide both sides by 2* pi *h

(Sa) / [ 1 * pi *h]   = r

i dont know but i think its something

Why did someone downvote my answer? It is accurate.

They were asking for radius not volume, so I was confused. If they only have the volume, then the problem can't be answered.

The cube root of x can be written as    x^(1/3)

So, this raised to the 57th power is .... [ x^(1/3)]^57     and by a property of exponents (a^m)ⁿ = a^m*n

So we have   [ x^(1/3)]^57 = x^(1/3)*57  =  x¹⁹

the formula is

radius = the square root of Volume divided by pi x height

i think... sorry if im wrong im only in algebra 1-2

What information do you already have about the cylinder?

x+3=y

3x+4y=7

Note, if y = x + 3, just substitute this to the second equarion........so we have

3x + 4(x + 3) = 7    simplify

3x + 4x + 12 = 7

7x + 12  = 7       subtract 12 from both sides

7x = -5              divide by 7 on both sides

x = -5/7

well first you have to make both of the denominators match. 4 x 5 = 20 right? so now you have to multiply the top by 5 too which would equal 15/20. now add 7/20 and 15/20 which equals 22/20, and to simplify would be 1 2/20 which would simplify again to 1/10! this is just how i do it, i hope this helped

First convert them to common denominators: 3/4 x 5/5 = 15/20

Then you add the numerators of 15/20 + 7/20 and keep the denominators.

ohhhh nvm i get it, thanks for trying to help though

You subtract 103 - 100 = 3 to get the change. Then you put $${\frac{{\mathtt{3}}}{{\mathtt{100}}}}$$ as a fraction. Then you convert that to a decimal, and it would be  0.03. Multiplying that by 100, we get 3%. Of course we could have already figured that out because 3/100 already has a denominater of 100 and was inherently 3.

Could you be more specific with the values? I can't describe the graph unless I have two coordinate points.

10 to the eighth power is just 10 times itself 8 times. It expressed as $${{\mathtt{10}}}^{{\mathtt{8}}}$$, but it is just $${\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{10}}$$.

Greetings to you, Sir CPhill:

I seeth ye have made changes to thy avatar and address. The byway of 666 hath and leadeth to many remarkable wizards and sorcerers. Yea, it passeth by the castle and mansions of Morgan le Fay, who be one with the greats and who resideth near that byway.

The path be potent and hath may powers. The bolder of Sisyphus hath rolled on this path in times of times, and ye may even findeth the Roman ZERO for which ye be searching.

By your leave,

M^-1

Greetings Your Majesty:

Here be a possible reason why the image ye seek come not forthwith.

There be many incantations in the crystal sphere that call forth spirits and graven images made by spirits.

In the beginning, the surf who made the post calleth the images from many domains and the images came forth. Now, it be that one of the domains hath vanished. Some of these domains be temporary and appeareth for a little while then vanishes away.

After the domain vanishes, if wizard’s assistant in the crystal sphere calleth for a graven image the wizard findeth that it does not exist, and never will again in this place, then to saveth time, the incantation be removed, for there now be no reason to use an incantation to call forth a graven image from a domain that exists not.

The graven images for choices of answers be in domains that still exist, and the incantation to call them still exists, so, they display when called.

In Her Majesty’s service,

M^-1

$${\frac{{\frac{{\mathtt{19}}}{{\mathtt{50}}}}}{{\mathtt{4\,200}}}} = {\mathtt{0.000\: \!090\: \!476\: \!190\: \!476\: \!2}}$$ The problem is just one big fraction that a calculator would be most useful in solving for.

To add fractions, we have to convert them to a common denominator. Since $${\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{12}}$$, we can convert 5/6 to a denominator of 12 by multiplying it by 2/2: $${\frac{\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{2}}\right)}{\left({\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{2}}\right)}}$$ = $${\frac{{\mathtt{10}}}{{\mathtt{12}}}}$$. Then we add $${\frac{{\mathtt{5}}}{{\mathtt{12}}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{10}}}{{\mathtt{12}}}}$$ = $${\frac{{\mathtt{15}}}{{\mathtt{12}}}}$$, which simplifies down to $${\frac{{\mathtt{5}}}{{\mathtt{4}}}}$$, and then can be converted to the fraction $${\mathtt{1}}$$$${\frac{{\mathtt{1}}}{{\mathtt{4}}}}$$ or 1.25.

$0.75 is our constant, and $0.50 is our rate of change.

Using slope-intercept form (y = mx + b), we now have y = .5x + .75.

Since we know that you rode the big slide 8 times, x becomes 8: y = .5(8) + .75

Then you multiply .5 * 8 and add .75 to the product.

F(x) is just function of x. So when we replace f(x) with f(3), we just replace the x in -5/4x + 4 with 3, which will be -5/4(3) + 4. Then we multiply -5/4 by 3(/1) and add 4 to that product to get the answer.

the of 9+10 is: 9+10= IIIIIIIII+IIIIIIIIII...as you can see there are 21 bars

so, the answer to 9+10= 21!!!!

First we have to find out how much the car's price increased by. So we subtract the original value from the increased value: 25,920 - 18,000 = 7,920. Next we divide 7,920 by 2, since it's a two year period and the question is asking for one year: 7,920 ÷ 2 = 3,960. Now that we know how much it increased (3,960), we put that in a fraction over our original value (18,000) to find out the actual rate of increase:

$${\frac{{\mathtt{3\,960}}}{{\mathtt{18\,000}}}} = {\frac{{\mathtt{11}}}{{\mathtt{50}}}} = {\mathtt{0.22}}$$   Multiplying 0.22 by one hundred, we get 22%.

30 is the total number of students and 16 is the total number of boys. So 16 of the 30 students are boys.

$${\frac{{\mathtt{16}}}{{\mathtt{30}}}}$$ is the fraction, and now we just have to simplify it: 16/30 ÷ 2/2 = 8/15.

1.25 OR 5/6