All Answers 358089 Answers

2x-6/4 =-7

2x-6/4+6/4 =-7+6/4

2x=-7+1+1/2

2x= -(5 and a half)

2x/2= -(5 and a half)/2

x=-(2 and 3/4)

Yes that works Chris - it is quite neat too.   I like it    

It is easier than my solution - I always do things the hard way - It is my trade mark so I can't stop now.

Can I ?  Would anyone like me to do it in LaTex so that it is easier to follow?

3/4 ths

Tap the 2nd key (top left) and this will make the sin^-1 key available.

At least it's not partial derivatives that involve trig and such that each problem takes up half the page. Of course then you just gotta find a calculator or website that can do them and it cuts your time down considerably. Try finding a website that'll do the calculations for you.

First take the log of both sides to bring out the 3x, divide both sides by log(128) then by 3.

log(128^(3x)) = log (8)
3xlog(128) = log(8)
3x = log(8) / log(128)
x = (log(8) / log(128)) / 3
x = 1/7

yeah its totally normal m8

$${\mathtt{22}}$$ is the answer

x - 13 = 9

add 13

x = 22

so -12/1 divided by 5/1?

use recipricle

-12/1 x 1/5

now multiply across

-12/5

simplify

-2 2/5

and there's your answer

2 + 2 = 4!

65 divided by 3 is 21.6666666667 which means there will be 21 pencils in each group but what do we with the decimals??? multiply 21 by 3 to find out how many pencils there are left over. 21 x 3 = 63 which means there will be 21 pencils in each group and 2 pencils left over

Hey, don't call them an idiot :(

11 minutes

the answer is 4 idiot

f must be degree 4.  Since it would contain an x^4 term, when this is multiplied by the x^2 term in the first expression, the result would be a 6th degree polynomial.

In essence, we need to multiply the "9" on the x^4 term in the second expression  by c such that, when this product is added to 5 on the x^4 term in the first expression, we get 0....therefore....

9c + 5 = 0      subtract 5 from both sides

9c = -5          divide both sides by 9

c = -5 / 9

You should get 0......

You should get

6z^5 + 15z^4 -22z^3 -8z^2 + 17z - 6

thank you alan a lot, but i have one more problem with this:

$$$\int \left(\frac{x}{\sqrt{3-4x^2}}\right)dx$$$

can you help me please??

What would be the end product?

OK...just type in 17......I think they only want the coefficient ......not the "whole" term....

Wait! I am so sorry CPhill, I put 17x instead of 17 because it was asking for the coefficient not the full term! So sorry!

It keeps saying that it is wrong...

Here's the result from Wolfram Alpha........

It's known to be pretty reliable............  it has 17x, as wel.....