All Answers 358089 Answers

7.3 / (8/9)  = x / 1    cross-multiply

7.3 = (8/9) x     multiply both sides by (9/8)

x = 8.2125 kg / bag

If the average of 8 numbers is 12, their sum must be 96....and if we increase each of them by 2, the new sum must be 16 more = 112

So 112 / 8 = 14     (and that's the new average......as we might have predicted!!!)

Let x be the number of white hydrangeas and let y be the number of pink hydrangeas

So, in the first bed,  x + y = 45

And we want 2 times the number of white hydrangeas in the second bed as the first = 2x and 3 times the number of pink hydrangeas as in the first = 3y   so    2x + 3y = 120

Using the first equation, we can solve for y  by subtracting x from both sides  so   y = 45 - x

And substituting this for y in the second equation, we have

2x + 3(45 - x) = 120    simplify

2x + 135 - 3x = 120

-x + 135 = 120     subtract 135 from each side

-x = -15               multiply both sides by -1

x = 15    and y = 45- 15 = 30

So.....there are 15 white hydrangeas in the first bed and we need twice this number in the second bed = 30....so that's 45 total white hydrangeas

And there are 30 pink hydrangeas in the first bed and we need three times this many in the second bed = 90So that's a total of 120 pink hydranges

Let w be the number of white hydrangeas in the first bed and p be the number of pink ones.

Then

w + p = 45           1st bed       so  p = 45 - w

2w + 3p = 120      2nd bed     or  2w +3(45 - w) = 120   so  -w + 135 = 120  or w = 15

Since p = 45 - w  then p = 30

Total number of whites = 3w = 45

Total number of pinks = 4p = 120

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Nice, saseflower......

I assume that you might want to evaluate this.....

86.010*log(19.5)-70.041*log(75)+36.76  =   about 16.385

We have 12 "face" (picture) cards in a deck

So the total number of sets possible in dealing three cards out of 52 is just C(52, 3)  = 22100

And we are interested in choosing the sets containing any 3 of the 12 face cards = C(12, 3)  = 220

So....the probability is just    220 / 22100  = about .99%

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Uh......it's a little more than 11 minutes ........!!!

Distance / Rate = Time     so

220miles / 40 miles per hr  = 5.5 hrs.

8 as a Fraction answer:16/2

2+2=4

The total area of the board and frame is (40cm+ 8cm + 8cm) = 56cm on a side....so..... 56cm x 56cm = 3136cm^2

There are 32 maple squares on the chessboard and eah is 5cm^2.....so....their total area is 160cm^2

So      160cm^2  / 3136 cm^2 = 5/98 = about 5.1%

Thanks, Melody......

Sum the number of tiles he has to paint and then divide that by 450. If you get a "fractional" amount, round up to the next integer.

You have to find 2 numbers that multiply to 2x-27=-54

And add to -3

Can you think of what they would be?

tell mr and ill show you the next step:)

5-6x>-22+3x

 +6x       +6x

5>-22+9x

+22 +22

27>9x

/9  /9

3>x

To answer this, you will need to use the pythagorean therom, a²+b²=c².  a and b being the two side lengths, c will be your diagonal.

If a=2.1 and b=.8, the equation will be:

$${{\mathtt{2.1}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{0.8}}}^{{\mathtt{2}}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

Then you square 2.1 and 0.8

$${{\mathtt{2.1}}}^{{\mathtt{2}}} = {\frac{{\mathtt{441}}}{{\mathtt{100}}}} = {\mathtt{4.41}}$$

$${{\mathtt{0.8}}}^{{\mathtt{2}}} = {\frac{{\mathtt{16}}}{{\mathtt{25}}}} = {\mathtt{0.64}}$$

These values substituted into the equation give you:

$${\mathtt{4.41}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.64}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

When you add together 4.41 and 0.64, you get:

$${\mathtt{4.41}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.64}} = {\frac{{\mathtt{101}}}{{\mathtt{20}}}} = {\mathtt{5.05}}$$

You can then substitue this value into the equation giving you:

$${\mathtt{5.05}} = {{\mathtt{c}}}^{{\mathtt{2}}}$$

To get the c alone, you can take the square root of both sides, so:

$${{\mathtt{5.05}}}^{{\mathtt{0.5}}} = {\mathtt{2.247\: \!220\: \!505\: \!424\: \!423\: \!2}}$$(x^.5 is the same as taking the sqaure root of x)

The Sqaure root of c² will be c, as the power of 2 will be cancled out by the square root.

So the final result will be 

$${\mathtt{c}} = {\mathtt{2.247\: \!220\: \!505\: \!424\: \!423\: \!2}}$$

So back to your original question.  In context, c is the diagonal of your rectangle.  So when you take the value for c, rounded to the nearest tenth (one decimal place), your answer would be...

$${\mathtt{diagonal}} = {\mathtt{2.2}}$$

Yes Mama that is correct :)

Some careless errors have been fixed - Thanks very much Alan.

It is correct now.

I have been perfecting my trademark here.

 If there is a R E A L L Y  L O N G  W A Y to do something I WILL FIND IT.

In my opinion CPhill's answer is the best one here.

It is really elegant.    Thanks Chris.

Heureka's answer is also much better than mine.    Thanks Heureka   

$$\int \left(\frac{x}{\sqrt{3-4x^2}}\right)dx\\\\
=\int \left(\frac{x}{\sqrt{4*(\frac{3}{4}-x^2)}}\right)dx\\\\
=\int \frac{x}{2\sqrt{(\frac{3}{4}-x^2)}}\;dx\\\\
=\frac{1}{2}\;\int \frac{x}{\sqrt{(\frac{3}{4}-x^2)}}\;dx\\\\
=\frac{1}{2}\;\int \frac{x}{\sqrt{(\frac{\sqrt{3}}{2})^2-x^2}}\;dx\\\\$$

$$\\=\frac{1}{2}\;\int \frac{x}{\sqrt{a^2-x^2}}\;dx\qquad where \quad a=\frac{\sqrt3}{2}\\\\
=\frac{1}{2}\;\int\;vu' \;dx\qquad where \quad v=x\;\;and\;\;u'=\frac{1}{\sqrt{a^2-x^2}}\\\\$$

 Now use integration by parts to solve.

$$\\v=x\;\;and\;\;u'=\frac{1}{\sqrt{a^2-x^2}}\\\\
v'=1\qquad u=sin^{-1}\;\frac{x}{a}\\\\
\;\int\; x*\frac{1}{\sqrt{a^2-x^2}}\;dx\\\\$$

$$\\=\frac{1}{2}(sin^{-1}\;\frac{x}{a}\;*\;x\;\;-\;\;\int\;sin^{-1}\;\frac{x}{a}\;*\;1\;dx)\\\\
=\frac{1}{2}\left(xsin^{-1}\;\frac{x}{a}\;\;-\left[a\sqrt{1-\frac{x^2}{a^2}}\;+\;xsin^{-1}\;\frac{x}{a}\;\;\right]\right)+c\\\\
=\frac{1}{2}\left(\;-\left[a\sqrt{1-\frac{x^2}{a^2}}\;\right]\right)+c\\\\
=\frac{-1}{2}\left(a\;\sqrt{1-\frac{x^2}{a^2}}\;\right)+c\\\\
=\frac{-1}{2}\left(\frac{\sqrt{3}}{2}\;\sqrt{1-\frac{4x^2}{3}}\;\right)+c\\\\
=\frac{-1}{2}\left(\frac{\sqrt{3}}{2}\;\sqrt{\frac{3-4x^2}{3}}\;\right)+c\\\\
=\frac{-1}{2}\left(\frac{1}{2}\;\sqrt{3-4x^2}\;\right)+c\\\\
=\;\frac{-\sqrt{3-4x^2}}{4}\;+c\\\\$$

4 is the answer

Since (0,0) is the intercept between the x and y axis, it would be considered both

on this calc it is labelles asin

arc sine is the same as inverse sine

Bob spent $24.75 to buy 12 flowers. Roses are 2.50 and daisies 1.75 How many of each did bob buy? 

R+D=12 (1)

2.50R+1.75D=24.75  (2)

Now you are told to use elimination, which is not the best way in my oppinion but to do this you must multiply the first one by something either 1.75 or 2.5.

I'll mult it by 2.5

2.5R+2.5D=30  (1b)

2.50R+1.75D=24.75  (2)

No subtract (2) from (1)

2.5D-1.75D=30-24.75

can you finish it?

Baballama is right there are many better options.

Here’s a partial list, alphabetized for your convenience.

The vulgar ones are not included.

airhead, birdbrain, blockhead, bonehead, b**b, bozo, chowderhead, chump, clod, cretin, dimwit, dingbat, dipstick, ditz, dolt, donkey, doofus, dork, dum-dum, dumbass, dumbo, dummy, dunce, dunderhead, fathead, halfwit, ignoramus, imbecile, jackass, jerk, jughead, knuckle-dragger, knucklehead, lamebrain, lummox, meatball, meathead, m***n, mouth-breather, nerd, nitwit, numbnuts, numbskull, peabrain, pinhead, sap, schmuck, simpleton, thickhead, turkey, twerp, twit, wooden-head. . . .

My favorites are the three "I's" Idiot, Ignoramus, Imbecile. They, along with m***n, actually have a formal, legal meaning.

Remember the best way to hide dumbness is to remain silent. You have the right to remain silent. Anything you say will be probably be stupid anyway. 

This is not all inclusive. There are a great many words describing diminished brain/mental function. The reason for this is such defects are common, and by no means represents a minority of any standard population. Even normally functioning high-level intelligence suffers from intervals of CDD.

Hey, BabaLlama, would you like to come to dinner? You will be the guest of honor.