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Thank you CPhill and anonymous for this!

Sunblock spf 50

Partially:

25sinxcosx-5sinx+20cosx=4

5sinx(5cosx-1)=4-20cosx

5sinx= -4(5cosx-1)/ (5cosx-1)

5sinx=-4

sinx=-4/5  which is 306.9 degrees.

I have difficulty with the other values (sleepy).

Aw, thanks Rosala:)

"What's in a name," anyways? :P

Perimeter of rectangle  ... 2(a + b)

Perimeter of square = 4a

Perimeter of triangle = b + 2√[(1/2b)^2 + h^2] = b + 2√[(1/4)b^2 + h^2]

Perimeter of parallelogam = 2[ b  + side length]  ....this is all we can do on this one, rosala

Perimeter of circle 2 * pi * b

P.S. - If the triangle is equilateral.....then Anonymous' answer is correct......we're not told if it is or not.....!!!

Perimeter rectangle 2a +2b

Square 4a

Triangle 3b (assuming equilateral)

Parrallelogram 2a + 2b (same as rectangle); there might be some argument about this since a is not given.

Circle 2pi *b

its funny when the person is mad for help and doesnt tell help for what!lol!

dont worry alani01 ...this is the daily drama!

$${\sqrt{{\mathtt{128}}}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$$

$${\mathtt{8}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{2}}}} = {\mathtt{11.313\: \!708\: \!498\: \!984\: \!760\: \!4}}$$

sqrt(128) is the same as sqrt(64 * 2). Which is the same as sqrt(64) times sqrt(2).

sqrt(64)= 8

result 8 sqrt(2)

7/4(3x-1/2)-4/3<5/3    add 4/3 to both sides

(7/4)[3x -(1/2)] < 9/3

(7/4)[(3x - (1/2)] < 3     multiply both sides by 4

7[3x - (1/2)] < 12          divide through by 7

3x - 1/2  < 12/7             mutiply throgh by 14

42x - 7 < 24                   add 7 to both sides

42x < 31                       divide both sides by 42

x < 31/42

I have difficulty with LaTex but I believe that it reduces to 30y^2 times the cube root of 2y.

Consider:

250 is 2(5^3); the cube root of 5^3 is 5 (moved outside the radical)

y^7 is (y^3)(y^3)(y); the cube root of y^3 is y. twice so resuts in y^2 outside the radical.

6 (5)(y^2) time cube root of 2y.

I get 7/3 or 2.33

ok

-11y-11x

sec^2-1/sec^2=sin^2x

tan^2x / sec^2x =

[sin^2x / cos^2x]  *  1 / sec^2x =

[sin^2x / cos^2x]  *  cos^2x

sin^2x

The circumference U is the distance around a closed curve. See the "Formulary" dropdown menu above.

It depends:

$${\frac{{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{7}}}}\right)}{{\mathtt{2}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{7}}}}$$

$${\mathtt{\,-\,}}{\frac{{\mathtt{2}}}{\left({\frac{{\mathtt{7}}}{{\mathtt{2}}}}\right)}} = {\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$

See where the parenthesis makes a diference?

I wasnt being litteral It was because no one was answering

Thanks Chris :)

For the second one, we have

2. 5x³ + 15x²; x² – 6x + 9; 2x² – 6x

Factor each

5x^2(x + 3), (x -3)^2, 2x(x -3)

And the LCM is

10x^2(x + 3)(x -3)^2 =  {you could expand this...if you want}

10x^2 (x ^2 - 9) ( x- 3) =

10x^2 (x^3 - 3x^2 - 9x + 27) =

10x^5 - 30x^4 - 90x^3 + 270x^2

With what?

You should multiply both sides by -1.

I get -36.157

Sorry I did not see the second question yesterday. 

2.How many ways are there for eight men and five women to stand in a line so that no two women stand next to each other

ok, here is the line

?M?M?M?M?M?M?M?M?

The M represents a man and the ? represents where a woman could stand

there  are 8! permutations for the men (8P8)

Now there are 9 places where the 5 women could stand   so that is  9P5

Put them together and you have  8!*9P5    permutations

$${\mathtt{8}}{!}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{9}}{!}}{({\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{5}}){!}}}\right)} = {\mathtt{609\,638\,400}}$$

I think that is correct.   

Sorry, my first answer was garbage and I have whited it. 

I must have had a brain aneuryism,  or a chronic case of CDD at the very least. 

2m²n; 3mn³; 9n²p  

2m²n; 3mn³; 3²n²p  

The lowest common multiple for the 2'a is 2

The lowest common multiple for the 3's is 3^2=9.     

the lowest common multple for the m pronumeral is m^2

the lowest common multple for the n pronumeral is n^3

the lowest common multiple for the p pronumeral is p

Put it all together and you get  

  $$LCM=18m^2n^3p$$