All Answers 358514 Answers

just enter this in the on-site calculator and hit enter and you'll get your answer!

2^21*28!

ok?

Well I am sure that would be activities happening on the beach and near the shore. Plus you would be listening to the surf all the time.  No I do not think it would be boring.

However, since I am not really a beach person, I would prefer a view of a river or lake where there was lots of activities  (but no water skiing, because it is really noisy)

I would love to live on the edge of a beatiful lake or river or harbour.  :))

Yes my room would not look sterile like that one.  I would have all my things around me. :))

Thanks Alan,

I have altered my answer a little but I still do not understand what is wrong with my logic.

Can you please take a look and talk me through it?     Thank you.   

oh view...yeah view is good....but im not a big fan of views o like some messy rooms....it may be expensive to live in but not too for a holidya becoz one gets bored of these too fast!dont you think?

Hi Rosala,

It was not the formality that I was admiring, it was the view and the big bearuiful verandah !!

And yes it would be far more expensive than what i could afford.  :((

this is good but id have this room only if im on a very strict routine.....i mean formalitis arent my thing a lot...but melody this might too costly, the more formal the more the cost!

@@ End of Day Wrap   Sat 7/3/15   Sydney, Australia    Time 8:30 pm    ♪ ♫

Good evening everyone,

Great answers from Geno 3141, Rosala, Smartcookie, Silver27 and Alan.  Thank you.

Interest posts:

Sun 8/3/15

How about this room Rosala? Only mine would have more of a lived in feel about it. :)

You can write this as

$$\\ \frac{5\times a}{5}+\frac{2\times a}{5}=-21\\\\\frac{7\times a}{5}=-21\\\\7\times a=-21\times 5\\\\a=\frac{-21\times 5}{7}\\\\a=-3\times 5\\\\a=-15$$

.

No, a palindrome reads the same backwards as forwards.  For example, 1991 is a palindrome.

. 

The measured speed would be greater if the radar were measuring the speed of the car head on, so it should be that v*cos(θ) = 95, where v is the car's speed and θ is the angle between the road and the line from the initial position of the car to the police car.

θ = tan^-1(30/120) ≈ 14°, so car speed v ≈ 95/cos(14°) = 97.9 ft/s

.

With this small angle, sines and tans are largely irrelevant!  The diameter is just the angle multiplied by the distance - as long as the angle is expressed in radians.

$${\mathtt{diameter}} = {\frac{{\frac{{\mathtt{34}}}{{\mathtt{60}}}}{\mathtt{\,\times\,}}{\mathtt{\pi}}}{{\mathtt{180}}}}{\mathtt{\,\times\,}}{\mathtt{92\,919\,800}} \Rightarrow {\mathtt{diameter}} = {\mathtt{918\,995.321\: \!833\: \!621\: \!997\: \!390\: \!4}}$$

diameter ≈ 9.19*10⁵ miles

.

Alan, you have divided by cos 14 and I have multiplied by cos14,

could you please explain to me where my logic is faulty?

We have here a right angled triangle with legs 30' and 120'. So they are in the ratio  1:4

For a right triangle with legs 1 and 4, the hypenuse will be  $$\sqrt{17}$$

$$\\\frac{x}{95}=\frac{4}{\sqrt{17}}\\\\
x=\frac{4}{\sqrt{17}}\times 95\\\\$$

$${\frac{{\mathtt{4}}}{{\sqrt{{\mathtt{17}}}}}}{\mathtt{\,\times\,}}{\mathtt{95}} = {\mathtt{92.163\: \!537\: \!513\: \!806\: \!529\: \!9}}$$

so maybe the car is travelling at     $$92\;feet/ sec$$

The distance travelled is less in the same amount of time so that also makes me think the velocity should be less than the clocked 95' /sec

I am really confused 

sub x value of -2.31 into: -1.38x^2 - 2.06x + 2.63

subsitute -2.31 where you see x and solve.

$$\begin{pmatrix}
-{\mathtt{1}}
\\
{\mathtt{38}}
\end{pmatrix}
{\mathtt{\,\times\,}}{\left(-{\mathtt{2.31}}\right)}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{2.06}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.63}}$$

$$\left(-{\mathtt{1.38}}\right){\mathtt{\,\times\,}}{\mathtt{5.336\: \!1}}{\mathtt{\,-\,}}{\mathtt{2.06}}{\mathtt{\,\times\,}}\left(-{\mathtt{2.31}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{2.63}}$$

$${\mathtt{\,-\,}}\left({\mathtt{7.363\: \!818}}\right){\mathtt{\,-\,}}{\mathtt{2.06}}{\mathtt{\,\times\,}}\left(-{\mathtt{2.31}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{2.63}}$$

$${\mathtt{\,-\,}}\left({\mathtt{7.363\: \!818}}\right){\mathtt{\,\small\textbf+\,}}\left({\mathtt{4.758\: \!6}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{2.63}}$$

$${\mathtt{\,-\,}}\left({\mathtt{2.604\: \!58}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{2.63}}$$

$$-{\mathtt{0.244\: \!58}}$$

Yes it is really boring a bit kinda I like lights To live alone that's fun! Which one do you like?

You know if that light one would be my room then I'd just add a dark blue fabric with shiny beads on it like diamonds and make my room glow like a night sky!awesome!

YES TJM  

1/infinty =0

No TJM,

infinity /infinity is  undefined.

The Cardinal number of something is how many individual elements it contains.

so it has to be 0 or a natural number, that is 0,1,2,3 etc

So if you are talking about all the days of the week then the cardinal number is 7

I  am not sure if I am using my parts of speach correctly.  

You usually talk about cardinal numbers in relation to sets. 

The cardinal number of a set is how many elements it contains.    

See TJM i did see your post.  It would be extremely rare for me to not see a post!    

Yes, I would have been surprised if you liked the formal one better - it looks very sterile!   

WOW it is THE answer to the universe.

4500(1+.0060/5)^1+5

I think it was intended as a compound interest question and I think that this is what you want

$${\mathtt{4\,500}}{\mathtt{\,\times\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{0.006}}}{{\mathtt{5}}}}\right)}^{\left({\mathtt{1}}{\mathtt{\,\times\,}}{\mathtt{5}}\right)} = {\mathtt{4\,527.064\: \!877\: \!806\: \!667\: \!197\: \!4}}$$

This would be the answer if you invest $4500 at 0.6% p.a. compounded 5 times a year (that's weird)

It would grow to $4527.06 in one year. 

wow I complete messed up that wording, I meant 5 dollar cents out of each unit and sells/"gets" 1320 units. turns out even a short nap helps a lot.

I am a goose - I used atan instead of tan that is why my answer was so wrong,

I will go back and fix it.     

This looks like you have a simple interest question.

I would recommend that you re-submit your question with some words describing the question. Otherwise there are too many ways your equation can be interpreted.