All Answers 358516 Answers

you cannot divide by zero - it is undefined.      :))

Come on Bertie, you can do better than that.    LOL

I need 400 brackets made that have parts a 57 5/8"  length of 2" x 3" angle,   

$${\mathtt{400}}{\mathtt{\,\times\,}}\left({\mathtt{57}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{5}}}{{\mathtt{8}}}}\right) = {\mathtt{23\,050}}$$   inches           $$23050/12 = 1920' 10"$$

a 96 3/16 piece of 2" x 2" angle

$${\mathtt{400}}{\mathtt{\,\times\,}}\left({\mathtt{96}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{3}}}{{\mathtt{16}}}}\right) = {\mathtt{38\,475}}$$   inches           $$3206/12 = 3206' 3"$$

and a 65 1/4" piece of 1"x 1 angle.

$${\mathtt{400}}{\mathtt{\,\times\,}}{\mathtt{65.25}} = {\mathtt{26\,100}}$$    inches                $$26100/12 = 2175'$$

What is the total lengh to 2"x 3" angle needed?     

How many inches of 2"x2" angle are needed?

How many inches of 1"x1" angle are needed?

If I understand you question properly

so anyone wanna give it a final try....after all the "clarifying"?

What Question

What to the power of 10 equals 149597870700?

$$\small{\text{$
10^{ \log{(149\ 597\ 870\ 700)} } = 10^{11.1749254120}=149\ 597\ 870\ 700.
$
}}$$

This actually factors quite nicely Melody:  x² + 7x - 144 → (x + 16)*(x - 9) so:

(x + 16)*(x - 9) = 0

x = -16 or x = 9

.

I think that you need to describe the shape better than that.

but

you would probably find the volumes seperately and add them together.

What is 5-t equal to that starts with "t"

there are many answers but this is the simplest one :)

$$5-t=t+5-2t$$

or

$$5-t= t/-1+5$$

If you want to show a degrees sign on the forum go to the "insert" drop down list,

choose special character and the degrees sign is 2nd row, 5th from the end.

I am not sure what you mean but there is a degrees button (and a radian button) on the bottom left of the calculator.  :)

144=7x+x^2

$$\\144=7x+x^2\\
x^2+7x-144=0\\
1x^2+7x-144=0\\$$

I'd just use the quadratic formula to solve it

The SI derived unit for force is the newton.
1 newton is equal to 0.224808943871 pounds.

 588 Newtons = 132.187658996148 pounds

6*10^-20

you can put it into the web2 calc :)

290= 290.0

I haven't rounded it but i have written it to the nearest tenth I guess.  

huh?

$$\sqrt[4]{625}$$

input                  sqrt(625,4)

output               $${\sqrt[{{\mathtt{{\mathtt{4}}}}}]{{\mathtt{625}}}} = {\mathtt{5}}$$

or

input                    625^(1/4)

output                  $${{\mathtt{625}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{4}}}}\right)} = {\mathtt{5}}$$

Maybe you forgot to give us some of the information  :/

Square root of minus12 to the third power sigma pi

I really do not know what you are talking about

$$(\sqrt{-12})^{1/3}\; \sigma\; \pi$$

Is that your question?  Means little to me. 

$$\\\frac{(x+1)}{(2-x) }< \frac{x}{(3+x)}\\\\
$I am going to multiply both sides by positive numbers and see if that will help$\\\\
(2-x)^2(3+x)^2*\frac{(x+1)}{(2-x) }<(2-x)^2(3+x)^2 \frac{x}{(3+x)}\\\\
(2-x)(3+x)^2(x+1)<(2-x)^2(3+x) x\\\\
(2-x)(3+x)^2(x+1)-(2-x)^2(3+x) x<0\\\\
(2-x)(3+x)\;[(3+x)(x+1)-(2-x) x]<0\\\\
-(x-2)(x+3)\;[(x+3)(x+1)-x(-x+2)]<0\\\\
-(x-2)(x+3)\;[x^2+x+3x+3+x^2-2x]<0\\\\
-(x-2)(x+3)\;[2x^2+2x+3]<0\\\\$$

consider   

  $$\\2x^2+2x+3=0\\\\
\triangle=4-24<0\\\\
$since the discriminant is 0 there are no roots for this.$\\\\
$the axis of symmetry for $y=2x^2+2x+3\;\;is\;\; \frac{-b}{2a}=\frac{-2}{4}=\frac{-1}{2}$$

the roots are    x=2 AND x=-3       

the polynomial if set to y and graphed will finish in the bottom right corner because of the - out to front.

I can see that the polynomial will be less than 0 when  x>2 and when x<-3

I am sorry i probably have not explained this very well, it was a difficult question for this type.

I did not use the graph but I will draw it now to show you.

Thanks Shaomada, you are ofcourse correct.  The question just confused me.

when I said that    $$|z|\ne z+\bar z$$    I really meant that they are not the same thing.

You are right - they are equal sometimes.

$$\\\sqrt{a^2+b^2}=2a\qquad a \ge 0\\
a^2+b^2=4a^2\\
b^2=3a^2$$

They will be equal whenever this condition is met.

You would still have 10....they would just be in different places, now...

well Billy, you would have seven apples left you special, special boy 

Whoa, dude...are you kidding???....that would take us all night!!!

I'll tell you how to do it.....and then.......good luck...!!!

Percent Increase/ Decrease =

(Subsequent Year - Previous Year) / Previous Year  x 100 %

For instance  from 1980 to 1981 we have

[1454 - 1414]/ 1414  x 100% =

[40 / 1414] x 100% = 

about 2.83%    {rounded to the nearest hundredth }

P.S. - If you know how to use a speadsheet program like Excel...it would be a simple matter to calculate these answers......that's probably what I would suggest......!!!....very lengthy, otherwise......