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Well this is how I would do it.

First i remember that 1cm^3 will hold 1mL

$$\\1mL=1cm^3\\\\
$Now $ 1m=100cm \;\;so \;\;1M^3= 100^3cm^3\;=1\; 000\; 000cm^3\\\\
$so if you have mL you will need to divide it by 1000000 to convert it to $m^3$$

$$\\x^4\div x^6=x^{4-6}=x^{-2}\\\\
$Now I will look at it differently$\\\\
x^4\div x^6=\frac{x^4}{x^6}=\frac{\not{x}\not{x}\not{x}\not{x}^1}{\not{x}\not{x}\not{x}\not{x}xx}=\frac{1}{x^2}\\\\
$so put these together and you get$\\\\
x^{-2}=\frac{1}{x^2}$$

If you want to get rid of a negative indice you put the thing that is raised to the neg power on the other side of the fraction line and change the negative to a positive.  :)

More here:

Thanks Badinage

I have no idea if this is correct but I have given you the points. 

Alan has assumed that your x is a multiply sign.   He is most likely correct.

On a computer we usually use * to mean multiply so that x is kept at as a letter.

This is not a criticism of your question I am just teaching you so that you will know next time.

So your    3xF = 3*F = 3F

In algebra if a number and a letter or two letters are right up against each other then there is an invisable multiply sign between them.  If there is a number then the number MUST come first

so

3*R*y*2 can be written as 6Ry  or   6yR

1. 
   
   In classical geometry, the radius of a circle or sphere is the length of a line segment from its center to its perimeter. The name comes from Latin radius, meaning "ray" but also the spoke of a chariot wheel. The plural of radius can be either radii (from the Latin plural) or the conventional English plural radiuses.
   
   

$${\frac{{\mathtt{27}}}{{\mathtt{7}}}}{\mathtt{\,\times\,}}{\mathtt{28}} = {\mathtt{108}}$$

It would be 2 hours .

3pm . 4pm , 5pm

Unless it was another day so if you could be a bit more precise it would be better.

What do you mean?

Hi Anon,

It actually does : / 

$${\frac{{\mathtt{1}}}{{\mathtt{2}}}}$$ = 1/2

It depends on what info you have but you can use the pythagorean theorem or trigonometry.

I don't know 

Maybe it is magic, you put what you want in and out pops the answer.

It is rather like pulling a rabbit out of a hat.    

Was it on the same day? Otherwise it might be unknown

$$P= \binom{6}{3}\left(\frac{1}{2}\right)^3\left(\frac{1}{2}\right)^3\times \binom{6}{3}\left(\frac{1}{6}\right)^3\left(\frac{5}{6}\right)^3$$

$${\left({\frac{{\mathtt{6}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)}{\mathtt{\,\times\,}}{{\mathtt{0.5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{{\mathtt{0.5}}}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{6}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{6}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{1}}}{{\mathtt{6}}}}\right)}^{{\mathtt{3}}}{\mathtt{\,\times\,}}{\left({\frac{{\mathtt{5}}}{{\mathtt{6}}}}\right)}^{{\mathtt{3}}} = {\mathtt{0.016\: \!744\: \!898\: \!834\: \!019\: \!2}}$$

= 1.7644...%

chance of winning =1.76% to the nearest 100th of a percent.

NOTE:

$$\binom{6}{3}\quad$is the same as $ ^6C_3 \\\\
$Sometimes when I am being a little lazy I may also write it as 6C3.$$$

On a more basic level

the formula of any circle in the x,y plane is     

   $${\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{h}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{k}}\right)}^{{\mathtt{2}}} = {{\mathtt{r}}}^{{\mathtt{2}}}$$

where (h,k) is t he centre and r is the radius :)

Why the time precision - is that when you have to take a test ?

We are not here to do a test for you :/

$$h^2=a^2+b^2$$

2 hours have passed between the crossings. :) Have a goodnight. 

rectangular form:  z = x + iy   where i = √-1

polar form:  z = re^iθ

To convert from rectangular to polar:

r = √(x² + y²)

θ = tan^-1(y/x)

.

Yes.  Add 3xF to both sides

86 -3xF + 3xF = 54 + 2xF + 3xF

86 = 54 + 5xF

Now subtract 54 from both sides

32 = 5xF

Now divide both sides by 5

32/5 = F

(or F = 32/5)

.

The only positive integer that goes exactly into both these numbers is 1.  They are relatively prime.

1943 = 29*67

500 = (2^2)*(5^3)

.

Thanks Geno,

I'm just giving another example.

Say you have 5 b***s that are lettered as A,B,C, D and E

how many ways can you choose 3 or them

Let me see

ABC    ABD    ABE    ACD    ACE    ADE

BCD    BCE    BDE

CDE

that is 10 ways.  (assuming that I didn't double up or miss any)

5C3 is just this.   It is how many ways you can select 3 things out of 5 things so it must equal 10

check  

I'll enter    nCr(5,2)    into the web 2 calc.  :)

$${\left({\frac{{\mathtt{5}}{!}}{{\mathtt{3}}{!}{\mathtt{\,\times\,}}({\mathtt{5}}{\mathtt{\,-\,}}{\mathtt{3}}){!}}}\right)} = {\mathtt{10}}$$

Oh and if you are doing it ny hand the calc just showed  you the formula :)

Nice work Chris, I had to think for a bit about that first integral, it is not one that I have memorized :/

There is no answer because there is no equal sign and you have not asked us to do anything else with it either.

You can use the quadratic formula but the number under the square root is negative (-39) so there will be no real solutions :)

Thanks anon - that is exactly correct :)