This equation relates the luminosity of a star to various vectors and physical Moduli.

It’s concepts are taught in basic astrophysics classes –usually in grade 6 or 7, depending on which school you attend.

5^(X- 8)=15     take the log of both sides

log 5^(x - 8)  = log 15       and by a log property, we can write

(x - 8) log 5 = log 15        divide both sides by log 5

x - 8 =  log 15 / log 15     add 8 to both sides

x = log 15/log5 + 8  ≈  9.68

Yay chris!!! ya did it!

love the colors. lol

u gotta add the pink, dont ya? :)

$$\textcolor[rgb]{1,0,1}{K.E. = \frac {1}{2}\ m\ v^2}$$

I assume this might be

[ log₃ (2 + 1) ] / 2 =

log₃ (3)  / 2  =

1 / 2

no prob. LOL

Sorry 'bout the garish color! A finger fumble on my tablet brought on that, and then

I just couldn't get the red background to cancel. Fortunately, they were at least different shades!

good job, Badinage!!! :D

btw. my eyes are still blind after looking at the highlighted question at the bottom LOL

Absolutely, melody! I understand it. and yes, I would let you guys know if I didn't understand it. Thanks for checking tho... :)

3^x * 9^x

= 3^x * (3^2)^x

= 3^x * 3^(2x)

= 3^(x+2x)

= 3^(3x)

= 3^3^x

= 27^x

Let's do an easy check. Does 3^5 * 9^5 = 27^5 on your calculator?  yes

(3^x)*(9*x)

=(3^x)*((3^2)^x)

=(3^x)*(3^2x)

=3^(x+2x)

=3^(3x)

Remember the minus sign.

-14/8=-1.75

-1.75*1.25=-2.1875

Actually, the volume of a sphere is $$(4/3)pi*r^3$$ not $$(4/3)*pi*r^2$$. So $$(4/3)*pi*(1475/314)^3$$ is about 434 cubic inches.

14/8 = 1.75

to add 25% to your answer you multiply your answer by 1.25

1.75 * 1.25 = 2.1875

.............................................

"2 dice" doesn't make sense unless we're adding them, that is, a 1 and a 3, or two 2s.  The probability of that is 3 out of 36 (1-3, 2-2, 3-1) which equals 1 out of 12. The probability of NOT totalling 4 is 11 out of 12. So the probability of not totalling 4, 7 times is (11/12)^7. The probability of at least one 4 is the opposite, 1 - (11/12)^7 which is 0.4561488217396119.

That colon : is unexpected. 

🚲  🚲  🚲

THANKYOU!!!!!!!! 

both of the 35's are in the numerator, despite what some teachers are teaching these days.  😁

😁

Well it would be, except it's not. The asker didn't give accurate values for either atom.

He's either a dumbshit or a troll.

We have.....

side^2 = Area    .....  so.....

(2x)^2  = 40  simplify

4x^2 = 40     divide by 4 on each side

x^2 = 10     take the square root of both sides

x = √10 in.

..................................................................

This is given by " 7 choose 3"    which is equal to  C(7,3)  = 35 different committees.......