All Answers 358087 Answers

I put the numbers in 'Mach Equation' from WolframAlpha.

What is the function notation of (4,7)?

This point is on an infinite number of functions.   One possiblility is     y=x+3

tan A=2/3, tan B=-3/5 

A=33.69, B=30.96

So the value of cot 2.73 is 20.97158

Number 17910 recorded four times in a row. 

From the resulting number of extracted root of 10. What happened?

I really do not understand you question but here is one interpretation.  I doubt that it is what you want :)

$${\mathtt{17\,910}}{\mathtt{\,\small\textbf+\,}}{\mathtt{17\,910}}{\mathtt{\,\small\textbf+\,}}{\mathtt{17\,910}}{\mathtt{\,\small\textbf+\,}}{\mathtt{17\,910}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{10}}}} = {\mathtt{71\,636.837\: \!722\: \!339\: \!831\: \!620\: \!7}}$$

Where did your answer come from jdh3010?

$${\frac{{\mathtt{6}}}{{\mathtt{48}}}} = {\frac{{\mathtt{1}}}{{\mathtt{8}}}} = {\mathtt{0.125}}$$

Did you check that it is working jdh?    For a while it wasn't but it might be fixed now :/

Thanks Geno,

I do it the same as Geno but for me I must draw a triangle every time.

Then you can read the values of the triangle.  The only other thing you MUST consider is what quadrants it can be in and is the trig ratio going to be positive or negative or either.

If tanΘ=9/5, what is secΘ

tan is poitive so it must be in the 1st or third quadrant.

sec = 1/cos = hyp/adj   

cos and therefore sec will be positive in the 1st quad and negative in the 3rd quad. 

$$sec\theta = \frac{\pm\sqrt{106}}{5}$$

Our answers are different Geno, I think you have made a little mistake :)   $$sec\theta=\frac{1}{cos\theta}$$

The square root of ten is approximately 3.1622776602.

I am going for NeoVoid's answer :)(

$$\\Y=\frac{6}{x}+19\\\\
$X cannot by 0 and Y cannot be 19$\\\\\\
\frac{6}{X}=Y-19\\\\
$ turn both sides upside down$\\\\
\frac{X}{6}=\frac{1}{Y-19}\\\\
$mult both sides by 6$\\\\
X=\frac{6}{Y-19}\\\\$$

6/x=y-19

Add 19 to both sides

y=6/x+19

So the answer is (-6,18), (-3,17), (-2,16), (-1,13), (1,25), (2,22), (3,21), (6,20)

Thanks Alan,

Here is a pic

tan(θ) = width/70 so 

$${\mathtt{width}} = {\mathtt{70}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{54}}^\circ\right)} \Rightarrow {\mathtt{width}} = {\mathtt{96.346\: \!734\: \!432\: \!97}}$$

or width = 96 ft to the nearest foot.

(I've assumed the angle, θ, is between the line of sight to C and the line AB)

.

If x = 33 then 

3y + 4z = 34      (1) and

y + z = 2           (2)

Multiply (2) by 3

3y + 3z = 6       (3)

Subtract (3) from (1)

z = 28

Substitute this into (2)

y = -26

This violates the condition "x,y,z are at least over 1"

.

there are 100cm in a 1 metre

so

there are $${{\mathtt{100}}}^{{\mathtt{2}}}$$  $${{\mathtt{cm}}}^{{\mathtt{2}}}$$    in     $${{\mathtt{1}}}^{{\mathtt{2}}}$$   $${{\mathtt{m}}}^{{\mathtt{2}}}$$

that is

$$10000\;cm^2\;=\;1\;m^2$$

$$\\11000m^2 = 10000\times 11000\;cm^2\\\\
11000m^2 = 110\;000\;000\;cm^2$$

(−1) x  ​494 = -494

jeff is his name

$$\\\frac{(x^2-25)}{(x^2+7x+10)}\\\\
=\frac{(x-5)(x+5)}{(x+5)(x+2)}\\\\
x\ne-2\qquad and \qquad x\ne -5\\\\
=\frac{x-5}{x+2}\\\\$$

$$\\\small{\text{
In mathematics, Euler's identity (also known as Euler's equation) is the equality $e^{i \pi} + 1 = 0$
}}$$

$${\frac{{\mathtt{475}}{\mathtt{\,\times\,}}{\mathtt{0.062\: \!5}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{4}}}} = {\frac{{\mathtt{475}}}{{\mathtt{64}}}} = {\mathtt{7.421\: \!875}}$$

$${\mathtt{475}}{\mathtt{\,\times\,}}{\mathtt{0.062\: \!5}} = {\frac{{\mathtt{475}}}{{\mathtt{16}}}} = {\mathtt{29.687\: \!5}}$$

$${\mathtt{29.687\: \!5}}{\mathtt{\,\times\,}}{\mathtt{1}} = {\frac{{\mathtt{475}}}{{\mathtt{16}}}} = {\mathtt{29.687\: \!5}}$$

$${\frac{{\mathtt{29.687\: \!5}}}{{\mathtt{4}}}} = {\frac{{\mathtt{475}}}{{\mathtt{64}}}} = {\mathtt{7.421\: \!875}}$$

Answer:$${\frac{{\mathtt{475}}{\mathtt{\,\times\,}}{\mathtt{0.062\: \!5}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{4}}}} = {\frac{{\mathtt{475}}}{{\mathtt{64}}}} = {\mathtt{7.421\: \!875}}$$

x-9=-18

$${\mathtt{x}} = -{\mathtt{9}}$$

$${\mathtt{\,-\,}}{\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{9}} = -{\mathtt{18}}$$

the number is -9

The distance formula (actually, the Pythagorean Theorem) that gives the distance between the points  (x₁, y₁)  and  (x₂, y₂)    is:  d  =  √[ (x₂ - x_{1)² +} (y₂ - y₁)² ]

The distance from  x(-1, 3)  and  y(3,0):

call  x₁ = -1,  y₁ = 3,  x₂ = 3,  y₂ = 0:  

       d  =   √[ (3 - -1)_² + (0 - 3)² ]  =  √[ (4)_² + (- 3)² ]  =  √[ 16 + 9 ]  =  √[ 25 ]  =  5

The distance from  y(3,0)  and  z(-1,-2):

call  x₁ = 3,  y₁ = 0,  x₂ = -1,  y₂ = -2:  

       d  =   √[ (-1 - 3)_² + (-2 - 0)² ]  =  √[ (-4)_² + (- 2)² ]  =  √[ 16 + 4 ]  =  √[ 20 ]                  =  2√5

The distance from  x(-1, 3)  and  z(-1,-2):

call  x₁ = -1,  y₁ = 3,  x₂ = -1,  y₂ = -2:  

       d  =   √[ (-1 - -1)_² + (-2 - 3)² ]  =  √[ (0)_² + (- 5)² ]  =  √[ 0 + 5 ]  =  √[ 25 ]  =  5

The total distance will be  5 + 2√5 + 5  =  10 +  2√5

Just use the distance formula 3 times :)