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0.667*10=667*10^(-2)

1. Find a number that you can multiply by the bottom of the fraction to make it into any 1 followed by 0s.

2. Multiply both top and bottom by that number. 

3. Write down just the top number and put the decimal point in the right spot.

eg) $${\frac{{\mathtt{63}}}{{\mathtt{125}}}} = {\frac{\left({\mathtt{63}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)}{\left({\mathtt{125}}{\mathtt{\,\times\,}}{\mathtt{8}}\right)}} = {\frac{{\mathtt{504}}}{{\mathtt{1\,000}}}} = {\mathtt{0.504}}$$

x^2+4x-16=0

The derivation for the quadratic equation is 

Substitute a=1, b=4, c=-16

So, the answer is x=-2(1+sqrt(5)) or 2(sqrt(5)-1).

163 is a prime number.

163=1^2+9^2+9^2

163=2^7+35

$${\mathtt{100}}{\mathtt{\,\small\textbf+\,}}{\mathtt{63}} = {\mathtt{163}}$$

Please? $${\frac{{\frac{{\frac{{\mathtt{3}}}{{\mathtt{4}}}}}{{\mathtt{5}}}}}{{\mathtt{656\,464}}}}{\mathtt{\,\times\,}}{\mathtt{55\,667\,788\,654}}{\mathtt{\,\times\,}}{\mathtt{x}} = {\mathtt{99\,877\,532\,223\,456\,778\,888}} \Rightarrow {\mathtt{x}} = {\frac{{\mathtt{655\,660\,043\,135\,393\,308\,959\,320\,320}}}{{\mathtt{83\,501\,682\,981}}}} \Rightarrow {\mathtt{x}} = {\mathtt{7\,852\,057\,823\,607\,967.370\: \!045\: \!364\: \!235\: \!722\: \!8}}$$

5.97 times 10 to the -6 divided by 10

→$${\frac{{\mathtt{5.97}}}{\left({{\mathtt{10}}}^{{\mathtt{6}}}{\mathtt{\,\times\,}}{\mathtt{10}}\right)}}$$=$${\mathtt{5.97}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left(-{\mathtt{7}}\right)}$$

In decimal form: 0.000000597

it was line saegment 

B. line i think... but im most certain it is

6*5-56=30-56=-26

Its not school that bothers me

just like you, i prefer the forums to be quiet on the holidays 

ok nevermind i wrote it down on my paper thanks geno3141

4x² - 100  =  0

Add 100 to both sides:

4x²  =  100

Divide both sides by 4:

x²  =  25

x  =  ±√25     --->     x = 5     or     x = -5

Turn the percent into a decimal so you can multiply it by 200000.

To turn a percent into a decimal, simpy divide by 100. 

2/100=0.02

Multiply.

0.02 * 200000 = 4000

The third equation has no y-term, so let's eliminate the y-term from the combination of the first two equations.

x + y + 3z  =  10     --->     x -2     --->     -2x - 2y - 6z  =  -20

-4x + 2y + 5z  =  7       --->                      -4x + 2y + 5z  =  7

Add down the columns:                             -6x - z  =  -13   

Since  kx + z  =  3        --->         z  =  3 - kx

Substituting these:        -6x - (3 - kx)  =  -13

                                    -6x - 3 + kx  =  -13

                                      6x + 3 - kx  =  13

                                          6x - kx  =  10

                                          x(6 - k)  =  10

If  6 - k  =  0,  there is no value for x that will result in a product of 10,

so  k = 6  results in no possible solution.

For every other value of k, there will be a value of x that can produce a product of 10.

-6 < 2x - 4 < 12

Get the x alone; add 4 to all three parts:

-2 < 2x < 16

Divide all three parts by 2:

-1 < x < 8

ok i got 35 less than or equal to -5z>-22 now what do i do

No....remember.....it's -5z .....not just -5......  we need to subtract 1 in the middle at the start to get just -5z remaining.....

this whole problem is confusing me

would you not add 5 to cancel the 5out and then add 5 to the -22 to make it -17

I don't understand your question......

ok so when u minus 1 what about the -5 and -22

36 ≤ 1 - 5z > -21     suubtract 1 from everything

35 ≤  -5z  > -22      divide everything by -5 and don't forget that we have to "reverse" the signs when dividing by a negative!!

-7 ≥ z < 22/5

Note that we must use the most restrictive interval, here .....  this is  ...   -7 ≥ z

Call the amoiunt Jenny can eat in one hr, x, the amount Penny can eat in one hour, y and the amount Lenny can eat in one hour = z.....so we have

1x +1 y + 1z  = 1

2x + 2y = 1  →    2y = 1 - 2x  →  y = [1 -2x] / 2     (a)

(5/3)x + (5/3)z = 1    →   (5/3)z = 1 - (5/3)x   →  z  =   (3/5)  - x      (b)

And substituting  (a) and (b) into the first equation, we have       

1x + [1 -2x] /2 +  (3/5) - x  = 1      simplify

{1 - 2x] / 2 +  (3/5) = 1     subtract 3/5 from both sides

[1 - 2x] / 2   = 2/5       multiply both sides by 2

1 - 2x =  4/5 

2x  = 1 - 4/5   

2x = 1/5      divide by 2 on both sides

x = 1/10    [of a gallon]     this is the amount that Jenny eats in one hour

So...just invert this...and it takes Jenny 10 hrs. to eat one gallon by herself......she's a pretty slow eater!!!!