All Answers 358087 Answers

Didn't CPhill answer this question for you yesterday Kiran?

I think circles have curves. Maybe that is the same as an angle.  IDK

If you have a circle with no diameter then that is a point. 

What if you had a circle with a infinite diameter, would that make it a strait line? 

Where are the statements?

Are there any perfect circles or are circles just infinite angles getting smaller each time.

Mmm, 

I think circles are pretty perfect but I really do not know what you mean  

"Infinite angles getting smaller each time"  this is an interesting idea but I am having trouble seeing how it relates to a circle.  

[Half] 1/2 (850) divide by 1650 x 100,

be the same as

425 divide by 1650 x 100?

$$\\\frac{1}{2}*850\div 1650*100\\\\
=\frac{850}{2}\div 1650*100\\\\
=425\div 1650*100\\\\
$so yes they are the same$\\\\
=\frac{425}{1650}*100\\\\
=\frac{425}{165}*10\\\\
=\frac{425}{33}*2\\\\
=\frac{850}{33}\\\\$$

If the average lap speed of a car is 144 mph how long would it take to complete a 2.5 mile lap?

Since the average speed of the car 144 mph, then 144/60=2.4 Miles per minute.

Since one lap is 2.5 miles, then 2.5/2.4=1 1/24 minutes, or 1 1/24 x 60=62.5 seconds to comlete one lap.

whats 5/7 of 4. Just multiply them together: 5/7 x 4=20/7 =2 6/7

what is -8 as a power of the base -2?

If you mean -2^-8, then it=1/256

x  represents the cost of a ticket;  y  represents the cost of a bag of popcorn.

You need to evaluate:  4(7.25) + 2(7.25 + 3.25)  ...

If you increase a number by  1000%,  you are increasing the number by  10  times the orginal number because 10  =  1000%.

The increase is  10 times , but the answer becomes  11  times.

if  x  is the original number, the increase will be  10x,  giving a final amount of  x + 10x  =  11x.

If you multiply the original number by  11  (not 10 and not 20),  you will get the final answer.

2600 / (4.184 x 25.6 )  =  24.27402008 (approximately)

2600 has 2 significant digits (ignore the ending zeros).

4.184 has 4 significant digits.

25.6 has 3 significant digits.

The answer cannot have more significant digits than the least of the numbers in the problem; in this case, two significant digits.

So, keeping only two significant digits, the answer rounds to 24.

Since -2 x -2 x -2  =  -8,   (-2)³  =  -8

Integers consist of all the positive and negative whole numbers, and zero.

 The integers are:         ..., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...

speed = distance / time

144=2.5/t

144t=2.5

t=2.5/144    hours

or

t=2.5/144*60*60   seconds

$$\left({\frac{{\mathtt{2.5}}}{{\mathtt{144}}}}\right){\mathtt{\,\times\,}}{\mathtt{60}}{\mathtt{\,\times\,}}{\mathtt{60}} = {\frac{{\mathtt{125}}}{{\mathtt{2}}}} = {\mathtt{62.5}}$$      seconds

Perhaps this page will help?

No, it is only an online calculator :)

This doesn't really make much sense.

4132.23 x 0.10 : 1 - 1:(1+0.1)²

I suppose it could be simplified to

413.223 : 0 : 1.21

g(x)=-3x+1 and g(10)

$$\small{
\begin{array}{rclcr}
g(\textcolor[rgb]{1,0,0}{x}) &=& -3 &\cdot & \textcolor[rgb]{1,0,0}{x}+1 \\
g(\textcolor[rgb]{1,0,0}{10}) &=& -3 &\cdot & \textcolor[rgb]{1,0,0}{10} + 1\\
g(10) &=& -30 && +1\\
\mathbf{g(10)} & \mathbf{=} & \mathbf{-29}
\end{array}
}$$

2(n-3)=4n+1

Answer

2n-4n = 1+6

-2n = 7

n = -(7/2)

n = -(3 1/7)

It look better using this

$${\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{7}}}}$$

This is better

$${\mathtt{\,-\,}}\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{1}}}{{\mathtt{7}}}}\right)$$

a times b equals -8. a plus b equals 7. what is a and b?

$$\small{
\begin{array}{lrcl}
(1) & a\cdot b&=& -8\\
(2) & a+b &=& 7\\
& \mathbf{b} & \mathbf{=} & \mathbf{7-a}\\
\hline
(2) \text{ in } (1) & a\cdot (7-a) &=& -8 \\
& 7a-a^2 &=& -8 \\
& a^2 - 7a -8 &=& 0\\
& (a-8)(a+1) &=& 0 \\
& \mathbf{a_1} & \mathbf{=} & \mathbf{8} \\
& \mathbf{a_2} & \mathbf{=} & \mathbf{-1} \\
\hline
& b_1 &=& 7-a_1 \\
& b_1 &=& 7 - 8 \\
& \mathbf{b_1} & \mathbf{=} & \mathbf{-1} \\
& b_2 &=& 7 - a_2 \\
& b_2 &=& 7 -(-1) \\
& b_2 &=& 7+1 \\
& \mathbf{b_2} & \mathbf{=} & \mathbf{8}
\end{array}
}$$

$$\small{
\begin{array}{lclccl}
a_1 = 8 \quad &\text{ and } \quad b_1 &=& -1\\
a_2 = -1 \quad &\text{ and } \quad b_2 &=& 8
\end{array}
}$$

12(2w-3)=6w

Solve it like this

24w-36=6w  --- distribute the 12  

24w-6w = 36  --- isolate the varable

18w = 36 --- subtract like terms

w = 18  ---divide by 18

The first term of a geometric series is 2, the nth term is 486 and the sum of the n terms is 728.

Find r and n

$$\small{
\begin{array}{lrcl}
(1) & a_1&=&\mathbf{a=2}\\\\
(2) & a_n &=& a\cdot r^{n-1} \\
& 486 &=& 2 \cdot r^{n-1} \\
& \mathbf{r^{n-1}} &\mathbf{=} & \mathbf{ 243 } \\\\
(3) & s_n - s_{n-1} &=& a_n \\
& 728 - s_{n-1} &=& 486 \\
& s_{n-1} &=& 728-486 \\
& \mathbf{s_{n-1}} & \mathbf{=} & \mathbf{242} \\\\
(4) & s_{n-1} &=& a\cdot \dfrac{ r^{n-1} -1 }{ r-1 } \\\\
& 242 &=& 2 \cdot \dfrac{ 243-1 }{ r-1 } \\\\
& 242 &=& 2 \cdot \dfrac{ 242 }{ r-1 } \\\\
& r-1 &=& 2\\
& \mathbf{r} & \mathbf{=} & \mathbf{3}\\\\
(5) & r^{n-1} & = & 243 \\\\
& 3^{n-1} &=& 3^5 \\
& n-1 &=& 5 \\
& \mathbf{n} &\mathbf{=} & \mathbf{6}
\end{array}
}$$

r = 3 and n = 6

$$\small{
\begin{array}{rclcr}
\text{geometric sequence: }
a_1 &=& 2 \cdot 3^0 &=& 2\\
a_2 &=& 2\cdot 3^1 &=& 6 \\
a_3 &=& 2\cdot 3^2 &=& 18\\
a_4 &=& 2\cdot 3^3 &=& 54\\
a_5 &=& 2\cdot 3^4 &=& 162\\
a_6 &=& 2\cdot 3^5 &=& 486\\
\hline
s_6 &&&= & 728
\end{array}
}$$ 

check:

$$\small{
a_n=a_6 = 2\cdot 3^5 = 486 \quad \text{( okay)}
}$$

Hallo anonymous!

a times b equals -8. a plus b equals 7. what is a and b?

a * b = - 8

a + b = 7

a = - 8 / b

a = 7 - b

- 8 / b = 7 - b

- 8 = 7b - b²

b² - 7b - 8 = 0

b1;2 = - (p/2) ±√((p/2)² -q)

b1;2 = 3,5 ±√ (3,5² + 8)

b1;2 = 3,5 ±√ 20,25 = 3,5 ± 4,5

b1 = 8

b2 = -1

a1;2 = 7 - b

a1 = -1

a2 = 8

test :

a1 * b1 = - 8                 

-1 * 8  = - 8   okey

a1 + b1 = 7

-1 + 8 = 7      okey

a2 * b2 = - 8

8 * (- 1) = - 8 okey

a2 + b2 = 7

8 + (-1) = 7 okey

greetings   :- )

@@ End of Day Wrap   Mon 24/8/15     Sydney, Australia Time   7:37pm       ♪ ♫   

Good day to all our members and guest :)

Our esteemed answerers are:  Asinus, Matsunnymat, Rosala, Dragonlance, CPhill, Badinage, Heureka and Sir-Emo-Chappington.  A very big thingk you to each of you :))