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Would you reword this please.

I do not understand. :/

a, b, c, d, e, f, and g are written of seperate bits of paper and put in a cup.

After that I am lost. ://

$40,000/$30,000=1 1/3=33% Increase over 10 years

(1 1/3)^1/10=2.9186% Increase per year in his after-tax nominal income.

CPI Index over 10 years=114/96=1.1875=18.75% Increase in CPI

(1.1875)^1/10=1.7333% Increase in CPI per year.

From the above you should be able to answer the two question posed.

$40,000/$30,000=1 1/3=33% Increase over 10 years

(1 1/3)^1/10=2.9186% Increase per year in his after-tax nominal income.

CPI Index over 10 years=114/96=1.1875=18.75% Increase in CPI

(1.1875)^1/10=1.7333% Increase in CPI per year.

From the above you should be able to answer the two question posed.

The 2 terms of payments are:1.5/15=10%

Since 1 - 10%=90%=n/45, n=90% X 45=40.5 so that 40.5/45=90%

Therefore the 1st payment is 10%=$3,245 X 10%=$324.50

The 2nd payment is 90% of $3245 X 90%            =$2,920.5

Just ask one question at a time please.

Also

The colons have not meaning.   

5^2*5^3

   5^4

I'll do the first one

\(\frac{5^2*5^3}{5^4}=\frac{5^{2+3}}{5^4}=\frac{5^{5}}{5^4}=5^{5-4}=5^1=5\)

What is 3/7 x 4/5?

Use this online calculator:http://www.calculatorsoup.com/calculators/math/fractions.php

34*75 = 2550 True!.

We have a table so 

Find the probabilty the priece of Jewerly is a gold earring or is a silver ring.   0.07+0.09 = 0.16

Do I have to add only .07 + .09       YES

Do i have to add all the earrings columns + the silver colums ? Without double the .15 ? 

NO then you would get a whole heap of other jewellry as well.

Solve for b:
y = (5 b)/8+10

y = (5 b)/8+10 is equivalent to (5 b)/8+10 = y:
(5 b)/8+10 = y

Subtract 10 from both sides:
(5 b)/8 = y-10

Multiply both sides by 8/5:
Answer: | 
| b = (8y)/5-16

Go online and use this calculator:http://www.calculatorsoup.com/calculators/math/decimal-to-fraction-calculator.php

what is 3.65 copies of 9?

9/(3.65)=2.46.....etc.

what is 3.65 copies of 9?

Just multiply them with a calculator :)

Since 19 is a PRIME number, then their LCM must be:

19 X 2 X 7=266

Their ages LAST YEAR would, of course, be 1 year less:

71 -1=70 Petra's age

35 - 1=34 Pedro's age.

The ages of Garry,Gerry and Greggy are consecutive odd integers. Gary is the oldest while Greggy is the youngest . Three years from now, Gary's age will be 8 less than twice Greggy's age. What are their present ages?

Let Gary's age 3 years from now be G

Let Greggy's age 3 years from now be g, then we have:

2g - G=8

There are many solutions to this, but only ONE that meets above conditions, namely,

Greggy's age=12 - 3=9 years, today

Garry's age   =16 - 3=13 years, today

Gerry's age               =11 years, today

So, 9, 11, 13 are their ages today.

I think she is saying that ABC has a right angle at B. Legs AB and CB are extended past point B to points D and E, respectively, such that <EAC=<ACD=90*. Prove that EB * BD = AB * BC.

why does "hi" have a frowning face...?

You expandthe brackets if there are any and add the like terms together. :)

Mean is average.

So add them all together and divide by 5

That is an excellent answer guest.   

the mean of five numbers is 8. four numbers are 7,11,12 & 4. what is the fifth number?

I would have solved this little equation.

\(\frac{7+11+12+14+x}{5}=8\)

If twice the present age of Pedro is decreased from Petra's age 5 years ago, the result is 4. Nine times Pedro's age 3 years ago exceeds 4 times Petra's present age by 4. WHat were their ages last year?

Let pedro's age today be P

Let Petra's age today be T

2P - (T - 5)=4

9 (P-3) - 4T=4

Solve the following system:
{5+2 P-T = 4 |     (equation 1)
9 (P-3)-4 T = 4 |     (equation 2)
Express the system in standard form:
{2 P-T = -1 |     (equation 1)
9 P-4 T = 31 |     (equation 2)
Swap equation 1 with equation 2:
{9 P-4 T = 31 |     (equation 1)
2 P-T = -1 |     (equation 2)
Subtract 2/9 × (equation 1) from equation 2:
{9 P-4 T = 31 |     (equation 1)
0 P-T/9 = (-71)/9 |     (equation 2)
Multiply equation 2 by -9:
{9 P-4 T = 31 |     (equation 1)
0 P+T = 71 |     (equation 2)
Add 4 × (equation 2) to equation 1:
{9 P+0 T = 315 |     (equation 1)
0 P+T = 71 |     (equation 2)
Divide equation 1 by 9:
{P+0 T = 35 |     (equation 1)
0 P+T = 71 |     (equation 2)
Collect results:
Answer: | 
| {P = 35 Pedro's age today
T = 71 Petra's age today

a- 17 X 4=68 sum of the 4 terms. If mean is 15, then,

15 X 5=75, therefore the 5th term must be:

75 - 68=7 the 5th term

Select the statement(s) and number line(s) that can represent the inequality. Circle all that apply.
 
A. The solution set is {6, ∞} for x ∈ R.
 
B. The solution set is {6, 7, 8, …} for x ∈ N.
 
C. 6 ≤ x
 
D. The value of a number substituted for x is greater than 6. For x ∈ R
 
E. For x ∈ N

\(12+\frac{11x}{6}\le5+3x \)

​​

I am not going to just give you the answer on a silver platter.

I want you to simplify this inequality.

It is easiest to start by subtractin 5 from both sides and then

multiplying both sides by 6 to get rid of the brackets.

You do that please and show me your working. (the best you can)

Posts can be hard to find so if you want my attention start by typing. "Help more please Melody. :)"

the mean of five numbers is 8. four numbers are 7,11,12 & 4. what is the fifth number?

8 X 5=40 the sum of 5 terms

40 - (7+11+12+4)=6 which is your 5th number.

How can I get 'n' from 0.8^n=0.1

Certainly I can. :)

\(0.8^n=0.1\\ log(0.8^n)=log(0.1)\\ nlog(0.8)=log(10^{-1})\\ nlog(0.8)=-1*log(10)\\ nlog(0.8)=-1*1\\ nlog(0.8)=-1\\ n=-1 \div log(0.8)\\ -----\\ \mbox{or the short way}\\ 0.8^n=0.1\\ log(0.8^n)=log(0.1)\\ nlog(0.8)=log(0.1)\\ n=log(0.1)\div log(0.8) \)

log(0.1)/log(0.8) = 10.3188511585161722

Please tell me is 78x573-56+938-509! > 903859504995789539? 

I can see with a cursory glance that it is not.   :)