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I am not sure what you need.....

8a/2 + 16/2  =  4a + 8       That is ABOUT all I can do with what you have given me

4a + 8  =  4 (a +2)      

~jc

1/3 = _/15        Here is an easy way.....WHAT did the  DenominatoR (3) get multiplied by to be 15?    the denominator (3) got multiplied by 5 !    Well....do the SAME THING to the Numerator (1)      and yo will get  5   (THAT IS THE ANSWER!)   Now you should be able to do some more of these.....try it!    Let me know if you need more help!

Well 5/9 of them voted for the Winner     5/9 x 1080 = 600 voted for the winner !

Due to conservation of energy, no energy will be lost in this collision.....the energy of the vertical and horizontal components will remain the same BUT it will be a bigger mass.

yvel = 25    xvel = 20

Kintetic energy = 1/2mv^2

the y particle energy    ye=1/2 (80)(25)^2      =  25000             The x particle energy  xe = 1/2 (75)(20)^2    =  15000

The final particle has a mass of 155      with a kinetic energy of those two original particles COMBINED = 25000 + 15000 =     40000

since Kinetic Energy = 1/2mv^2      40000 = 1/2(155)v^2    Solving for v:   v of the new particle is  22.72 m/s

A little more information you didn't ask for...ha

to find the resultant y component of the final particle's velocity      25000 = 1/2 mv^2     where m=155     then Vy = 17.960

to find the resultant x component of the final particle's velocity       15000 + 1/2 mv^2    Where m=155    then  Vx = 13.912

The resultant angle of travel will be   tan x = 17.960/13.912    or   angle x = 52.23 degrees

~jc    

Due to conservation of energy, no energy will be lost in this collision.....the vertical and horizontal components will remain the same BUT it will be a bigger mass.

yvel = 25    xvel = 20

Kintetic energy = 1/2mv^2

the y particle energy    ye=1/2 (80)(25)^2      =  25000             The x particle energy  xe = 1/2 (75)(20)^2    =  15000

The final particle has a mass of 155      with a kinetic energy of those two original particles COMBINED = 25000 + 15000 =     40000

since Kinetic Energy = 1/2mv^2      40000 = 1/2(155)v^2    Solving for v:   v of the new particle is  22.72 m/s

A little more information you didn't ask for...ha

to find the resultant y component of the final particle's velocity      25000 = 1/2 mv^2     where m=155     then Vy = 17.960

to find the resultant x component of the final particle's velocity       15000 + 1/2 mv^2    Where m=155    then  Vx = 13.912

The resultant angle of travel will be   tan x = 17.960/13.912    or   angle x = 52.23 degrees

~jc    

How many groups of 9 students are there in a school of 1080 students?

1080 divided by 9 gives an answer of 120.

On average, in each of these 120 groups 5 voted for the same person:  120 x 5  = 600.

So, 600 voted for the winning candidate.

Checking:  600 / 1080  =  5/9.

72 x 87.5  =  6300

The problem now is:  28 x 2^(6300)

Set the problem equal to x:  x  =  28 x 2^6300

Find the log of both sides:  log(x)  =  log(28 x 2^6300)

Now, use some properties of logs:

                                           log(x)  =  log(28) + log(2^6300)

                                           log(x)  =  log(28) + 6300log(2)

My calculator says that log(28) + 6300log(2)  =  1897.936 (approx)

                                           log(x)  =  1897.936

Changing back into exponential form:  x  =  10^(1897.936)  =  10^(1897 + 0,936)

which is:                                                x  =  10^1897 x 10^0.936

But, 10^0,936  =  8.63 (approx), so      x  =  10^1897 x 8.63  or  8.63 x 10^1897.

hmm... maby 4 im not quite sure.

... jk

how am i gonna express the ratio in lowest terms of consonants to vowels in each name?

 example:

Fredericton       11 letters

vowels           e,e,i,o                  4 vowels

consonants   f, r, d , r, c, t, n     7 consonants

ratio of vowels to consonents is    4 : 7     

Sometimes this is written as a fraction  4/7

and 4/7 cannot be simplified. 

Do the exponent first   72 x 87.5 = 6300

This is going to be a really big number

28 x 2^6300     

 28 x 2^6300    the 2^6300 will come back as an error or infinity on most calculators......some may come back with a scientific notation

The definition of 'those' are 'not these'

1/2   as a decimal..... just divide '2' ino the '1'       1 divided by 2 = 0.5 as a decimal

~jc

The Ratio of the height to the lenght of an Artic wolf is 2:3. if average lenght os 150cm, what is the average height in centimetres.

2/3 X 150=100cm. The average height of Arctic wolf. Because: 2/3=100/150

Height/Length = 2/3 = ?/150

2/3 = ?/150    Multiply both sides by 150

150(2/3) = ? = Height

100 cm     Cool animals those wolves...I've seen a few

~jc

How do I solve the square root of (one minus the (square root of 3)/5) ^2

Ok, that's confusing. the square root of 3 over 5 is one fraction that is being subtracted from 1 all under a square root sign.

Sqrt[ 1 - sqrt(3) / 5]^2 Did I write it properly? If yes, then the answer is:

=1 - sqrt(3)/5

How about: 1, 6, 11, 16, 21, 26 couples, and:

                   47, 39, 31, 23, 15, 7 singles.

2+2=4

If you need an explanation:

Imagine you have 2 oranges. Then add 2 more oranges to the 2 you already have. So now instead of just 2 oranges, you have 4.

21  

;)

Oh CRUD !  D'oh!    I just CAREFULLY re-read the quesstion....   I had ALL of the CDs as FIVE year CDs......jeez.    I had the right methodology at least, just the wrong inputs.      Computers do not give you correct answers if you give them the wrong data!

Way to go Melody!     ~jc

Thanx for your repeated help on this......thought I was going nutz    ....or Deez Nutz as the case may be.....    ha

~jc

See my answer here, Kawaii   ...    http://web2.0calc.com/questions/how-am-i-gonna-express-the-ratio-in-lowest-terms-of-consonants-to-vowels-in-each-name

Fredericton

7 consonants

4 vowels

So.....the ratio is :

7 / 4  

And that's in lowest terms

'Hey' Hayley !    Got a handle on those Quadratics now?

~jc

Fractions are very difficult to get the hang of, I will agree to that. :))