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53/3

Let’s test it. 

How many imperial minims of sweetness are required to neutralize the bitter bite of a sarcastic troll post delivered at a volume of 2 cubic miliPotrzebie, with a mass of 0.50 ngogn, and a specific heat of 0.271828 at an average temperature of 0.25 Phlegethon?

Round your answer to the nearest sarcastic unit of imperial minim of sweetness.

Your English is fine, but CDD might be causing you some asystole, Asinus. (The question did ask for the answer in scientific notation.)

k(t)=t^2-2t Find k(-4)

\(k(t)=t^2-2t \\ k(-4)=(-4)^2-2*-4\\ k(-4)=+16--8\\ k(-4)=16+8\\ k(-4)=24\\\)

Like this:

(7/4)(17^2)(tan(180/7))^-1

\((7/4)(17^2)tan^{-1}(180/7)\\ =(7/4)(17^2)*atan(180/7)\)

This doesn't make a huge amount of sense because inverse sine is an angle - why would you multiply an angle by that other stuff?

Also, do you want the angle in degrees or radians or something else?  

(7/4)(17^2)*atan(180/7) = 44391.1709962303695       Here is an answer in degrees but it is pretty silly.  ://

Thanks for the answers!!! :^)

Thanks for the answer!

2\; \;+\; \;2\; \;=\; \;4\;h\;o\;p\;e\;i\;t\; \;h\;l\;p\;s\;!\;:\;)\;

You use present value if you are going to get a set regular value for a period of time and at the end you will have nothing left.

The present value is how much money initial money is needed if you are going to get this regular payment, it takes into account that you are going to be getting interest along the way.

So you use present value if you have 0 left at the end

and 

you use future value if you have 0 at the beginning

I did this on the calculator - I just used my keyboard for the absolute bars.

I didn't see them on the calc pad.

What do you want to do anyway?

|-6| = 6

Alan is standing 100 m due east of a landmark. Benny is standing 250 m due south of
the landmark. What is the bearing, correct to the nearest tenth of a degree, of:
a Benny from Alan b Alan from Benny?

Draw the triangle

put theta in the bottom angle - that is where Benny is.

\(tan\theta=\frac{100}{250}=0.4\\ tan^{-1}0.4=21^\circ48' \\~\\ So\;\; Alan \;\;is \;\;N\;\;21^\circ48' \;\; E\;\;of \;\;Benny\\~\\ Benny \;\;is \;\;S\;\;21^\circ48' \;\; W\;\;of \;\;Alan\\~\\ \)

Try an draw the pic yourself and if you cannot work it out ask again.

If you become a member you can make more sure of extra help by prompting me with a private message.

You can ask whatever you want. 

Someone might know the answer :)

Without using (10), show (prove) that for any whole number n and any positive y, (y^-1)^n = y^-n.

I suppose this is what your teacher wants . 

\((y^{-1})^{n} = y^{-n}\\ \begin{align} LHS&=(\frac{1}{y})^{n}\\ &=\frac{1}{y^n}\\ &=y^{-n}\\ &=RHS \end{align} \)

5-|3f+4|=20 

confused on how to solve

-|3f+4|=15

There are no real solutions to this.  The left hand side must be less than or equal to 0.

Hi Higgsb  :)

Marcelle and Jaclyn each think of a polynomial. Each of their polynomials is monic, has degree 4, and has the same positive constant term and the same coefficient of z.

Marcelle        \(z^4+az^3+bz^2+cz+k\)

Jaclyn            \(z^4+pz^3+qz^2+cz+k\)

The product of their polynomials is   \(z^8 +3z^7 +z^6 +3z^5 +4z^4 +6z^3 +2z^2 +4\)

What is the constant term of Jaclyn's polynomial?

k^2 = 4   so    k= +2 or k=-2  but k is positive so 

The constant is 2

The coefficient of z is not relevant.

1

There is no question here .

(1.16)1/3 =

is this what you mean

\(1.16^{1/3}\)

(1.16)^(1/3)  = 1.0507175744985802

20-6=14 were taken

20 - 12  = 8 were taken from the deck