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Pardon, I was wrong. In engineering notation, the orders of magnitude are always used with divisible by 3 exponent.
10³; 10⁶; 10⁹ etc. So \(10 \times 10^6\)
Excuse my English, please.

aops much

Each nickel is worth 5 cents

Each dime is worth 10 cents

Each quarter is worth 25 cents

Can you figure it out, now????

In scientific notation, the orders of magnitude are always used with divisible by 3 exponent.
10³; 10⁶; 10⁹ etc. So \(10 \times 10^6\)
Excuse my English, please.

So you can see how much money you have!!. Suppose somebody leaves you an inheritance, and they stipulate that you should recieve an annual payment of $100,000 for your natural life. Now, you don't really know how much money you have. But, if you can find out what interest rate you get on your Trust Fund, then you can easily figure out how much money you have. So, if you knew you were getting 6% annual interest on your Fund, then you would divide your $100,000 by 6% =100,000 / .06 =$1,666,667.00.

That would be the PV of your Perpetual Annuity.

Note that the question asks for  y= (-2x^3)/(x^3+5)  not  y= (-2x^3)/(x^2+5)........!!!!!

visa att talet 101o-1 är delbart med 9.

1009 är inte delbart med nio,

eftersom 

summan av siffrorna är inte delbart med nio.

hälsningar

asinus :- )  !

1 x 10⁷

yo yo ima youtuber

y = -1/x^2

Notice that, as x increases without bound in both directions, y approaches 0

Here's the graph to show this : https://www.desmos.com/calculator/buda5boeaz

How do I write 10^4* 10^-3*10^6 in scientific notation?

\(10^{4}\times 10^{-3}\times 10^{6} \) = \(10^7 \) = \(10 \times 10^6\)

Circle A has a radius of (x+4) units. A large circle, B has ra dius of (x+5) units. use the formila A = π × r2 to write an expression for the difference in the areas of the circles. leave your answer in terms of PI. then use 3.14 for PI to approximate to the nearest whole number the difference in the areas when x=10

Area of circle B = pi * (x + 5) ^2

Area of coircle A  = pi * ( x + 4)^2

Difference in areas  =  pi [ (x + 5)^2 - (x + 4)^2]

Difference in areas assuming pi = 3.14 and x = 10  =

3.14 [ (10 + 5)^2  - (10 + 4)^2]   =  

3.14 [ 15^2  - 14^2]  =

3.14 {225 - 196]   =

3.14 [ 29 ]  ≈  91.06 square units  =  91 sqare units [to the nearest whole number]

How could the graph of y=(-2x^3)/(x^2+5) possible have the same end behavior as the graph of y=-2???

You're a hero.

Thanks!

Take the tangent inverse.......this is denonted as "arctan" or as tan^-1  on your calculator

So we have

tan^-1 (0.56) =  θ ≈   29.25°

y= (-2x^3)/(x^3+5)

I assume that you are referring to the "end" behavior.

Since the higest power on x in both numerator and denominator is the same, the end behavior will be determined by the ratio of the coefficients on these highest powers.

So we have    y =  -2 / 1   = -2

Thus.......as x increases without bound in both directions, the function approaches  y = -2

Here's a graph that confirms this :  https://www.desmos.com/calculator/kcfoxqcmsf

Let the number of yellow b***s = Y

Then the number of red b***s =  10 - Y

And we know that   the chance of drawing a red ball on the first draw = [10 - Y] / 10

And the chance of drawing a red ball on the second draw [without rplacement]  = [9 -Y] / 9

So.....the chance of drawing a red ball on both draws is given as :

[ 10 - Y] / 10 * [9 - Y] / 9  = 1/15     simplify

[90 - 19Y + Y^2] / 90  = 1/15     multiply both sides by 90

Y^2 - 19Y + 90 = 90/15

Y^2 - 19Y + 90  = 6     subtract 6 from both sides

Y^2 - 19Y + 84 = 0    factor

(Y - 12)(Y - 7)  = 0     ans setting each factor to 0, we have that  Y = 12  [impossible]   or Y  = 7

So.....the number of red ones = 10 - Y   = 10 - 7   = 3

Proof :    (3/10) (2/9)  =  6/90   = 1/15

Are of a semi-circle =   (1/2)*pi * (D/2)^2      where D is the diameter...so we have

50 *pi  = (1/2)*pi * (D/2)^2     divide both sides by pi, multiply both sides by 2

100 = D^2 / 4      multiply both sides by 4

400  = D^2        take the square root of both sides

20  = D

Probability that they both spin a "1" =  (1/10)(1/10)  = 1/100

Probability that they both spin a "2" =  (2/10)(2/10)  = 4/100

Probability that they botrh spin a "3"  = (3/10)(3/10)  =  9/100

Probability that they both spin  a "4" = (4/10)(4/10)  = 16/100

Summing these.....the total probability  is  [1 + 4 + 9 + 16] / 100  =  30 / 100  =  3 / 10

Thanks to Alan for spotting my typo.....the correct answer should be....

  [6435 + 5005 + 3003 + 1365 + 455 + 105 + 15 + 1 ] / 32768   = 1/2   !!!!

Let the original denominator  = A....so we know that

[ 2 + 5 ] / [ A + 5]  = 1/2     cross-multiply

2 [2 + 5]  = A + 5   simplify

2[7]  = A + 5

14  = A + 5     subtract 5 from both sides

9 = A

So......the original fraction  was 2/9

Scruffy23:

You are all confused. Look carefully at the question which says " consists of two letters followed by three digits". Example: AA111, if repeats are allowed. So, starting from the left: You can choose A out of 26 letters. The same with the second A from the left. Then, starting with 1, you have 10 choices from 0 - 9 to choose from. The same with the second and third 1's. So, as CPhill calculated, you have a total of: 26 x 26 x10 x10 x10 =676,000!!.

2(-6)+4(-5)2=-52

why does this help u at all lol

that doesn't really makes sense because 8187/16384 is slightly less than one half (ok then its 0.49969482421875) so the probability of guessing at least half of the questions correct is around 0.5? it may seem ok at first but... but... but... but...

FIZZLE CRACK BANG BOOM sorry actually your right in my answer i was using the same anology as a coin toss heads in a row but this is not the same thing steve doesn't have to get them correct in a row to win he just has to them correct. sorry, sometimes my brain dissolves into molten goop it just took some time for it to solidify again.

125 / 175 =  

[5 * 25] / [ 7 * 25] =

5 / 7 ≈

0.7143  ≈

71.43 %