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 #2
avatar+118723 
+3
May 22, 2014
 #4
avatar+118723 
0
May 22, 2014
 #6
avatar+130517 
+8
May 22, 2014
 #2
avatar+118723 
+5
May 22, 2014
 #1
avatar+676 
+13

Well... There isn't a easy way of doing this unless there are "Special Circumstances" but... Assuming that you don't know powers, I will briefly go through it.

Powers are simply the number of times the base number is multiplied by itself.
Confusing right..? >_<

For example. 3 to the power of 5 is equal to:

$${\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\times\,}}{\mathtt{3}} = {\mathtt{243}}$$

The Base number is 3 and the Index or the Power is 5.
This means 5 3's all multiplied together.!

Back to the question.

12 to the power of 27 is 

$${\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}}{\mathtt{\,\times\,}}{\mathtt{12}} = {\mathtt{137\,370\,551\,967\,459\,378\,662\,586\,974\,208}}$$

Nice number eh...?

But don't do it this way!

Because the Base Number (12) is the same, we can use this special method.

In terms of Indicies, multiply is the equivalent to Plus.

For example:

4 to the power of 4 Multiplied by 4 to the power of 5 is equaled to 4 to the power of 9.

Do you see what i have done here..?

Now lets go back to the question.

12 to the 27 power * 12 to the -29 power 

Using the method I told you, you can just simplify it to just... 27+(-29)

This would equal to -2

Now substitute!

12 to the power of -2.

Now lets solve it!

$${{\mathtt{12}}}^{-{\mathtt{2}}} = {\frac{{\mathtt{1}}}{{\mathtt{144}}}} = {\mathtt{0.006\: \!944\: \!444\: \!444\: \!444\: \!4}}$$

Done!

 

REMEMBER, ONLY WORKS IF THE BASE IS THE SAME AS THE OTHER BASE!

May 22, 2014
 #18
avatar+118723 
0

Thursday 22/5/14

Heureka explained a bit more LaTex.  I have been using it today and it works a treat!  Thanks Heureka.

http://web2.0calc.com/questions/5-11-2-x-1

Heureka also showed us that that the Web2 calculator has a MOD button.  I didn't know that!

http://web2.0calc.com/questions/how-do-i-do-mod-on-this-calc

I'd like someone knowledgeable to comment on the last post by "Someone Who Knows Everything".  Does it make sense?  It's all too much for me.  I liked my own answer.

http://web2.0calc.com/questions/if-there-were-3-skiers-on-plane-of-17-and-4-people-on-the-plane-died-of-a-crash-what-is-the-chance-that-all-3-skiers-survive

Bertie has posted a new proof of pythagoras' Theorum - It is woth the read!!! Thanks Bertie.

http://web2.0calc.com/questions/what-is-the-pythagoras-formula#r107415

The fun continued with this one

http://web2.0calc.com/questions/help-me-please_5

Funny one (at zegroes expense)

http://web2.0calc.com/questions/what-does-x-mean

Who was fibonacci?  (I thought I'd throw in one more serious one) 

http://web2.0calc.com/questions/who-was-fibbanci

May 22, 2014
 #2
avatar+118723 
0
May 22, 2014

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