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 #1
avatar+676 
+8

Okay! This one looks really... long... Nevertheless! Lets solve it!

Alright, lets start with setting out the equation.

$$\left({\frac{\left(-{\mathtt{4}}\right)}{{{\mathtt{7}}}^{{\mathtt{2}}}}}\right){\mathtt{\,-\,}}{\frac{{\frac{{\frac{{\frac{{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{{\mathtt{5}}}^{{\mathtt{3}}}}}\right)}{{\mathtt{\,-\,}}{\mathtt{sqr64}}}}}{{\mathtt{625}}}}}{{{\mathtt{\,-\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{125}}}}\right)}^{{\mathtt{1}}}}}}{{\mathtt{3}}}}$$

I am not quite sure what you were asking... This is what I got out of your question. Perhaps this is correct?

Anyway, Indeed this is a very confusing equation

First of all, we will need to work out

$${\mathtt{\,-\,}}\left({\frac{{\mathtt{4}}}{{{\mathtt{7}}}^{{\mathtt{2}}}}}\right)$$

This will equal to -0.0816326530612245.

Then we move on. We will substitute along and make this question easier.

$${\mathtt{\,-\,}}{\frac{{\mathtt{0.081\: \!632\: \!653\: \!061\: \!224\: \!5}}}{{{\mathtt{5}}}^{{\mathtt{3}}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{4}}}{{\mathtt{6\,125}}}} = -{\mathtt{0.000\: \!653\: \!061\: \!224\: \!489\: \!8}}$$

Then we subsititute what we get as the numerator again.

$${\mathtt{\,-\,}}{\frac{{\mathtt{0.000\: \!653\: \!061\: \!224\: \!489\: \!8}}}{{\sqrt{{\frac{{\mathtt{64}}}{{\mathtt{625}}}}}}}} = {\mathtt{\,-\,}}{\frac{{\mathtt{1}}}{{\mathtt{490}}}} = -{\mathtt{0.002\: \!040\: \!816\: \!326\: \!530\: \!6}}$$

Once again we substitute!

$${\mathtt{\,-\,}}{\frac{{\frac{{\mathtt{0.002\: \!040\: \!816\: \!326\: \!530\: \!6}}}{{{\mathtt{\,-\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{125}}}}\right)}^{{\mathtt{1}}}}}}{{\mathtt{3}}}} = {\frac{{\mathtt{25}}}{{\mathtt{2\,352}}}} = {\mathtt{0.010\: \!629\: \!251\: \!700\: \!680\: \!2}}$$

Here we are!

The Answer!

Negative 4 over seven squared minus negative 2 over five cubed over the square root of negative 64 over 625 divided by the cubed root of negative 8 over 125 equals to 0.0106292517006802!

May 22, 2014
 #135
avatar+118723 
+9

@@ End of Day Wrap - Thursday 22/5/14   Sydney, Australia   Time 18:50

Good evening/day everyone,

Another busy day, especially for me and (CPhill) Chris but lots of other people produced good answers as well.  Theses answerers are Heureka, Reinout-g, Zegroes, Bertie, GoldenLeaf, Kitty<3, Alan, Isiber17, Takahiromaeda and rosala.  Thank you everyone.

Some people also showed their appreciation.  Thank you we really appreciate that.  We like getting thumbs up too!   But, if you are not completely satisfied with your answer make sure you say so!  You can also join in and ask questions about someone elses question if you want.

I would like to take this opportunity to commend Kitty<3 for her consistantly high quality answers.  Kitty is one of our younger answerers and she is a great role model for all the others.

Now for some posts that you may find interesting 

Heureka explained a bit more LaTex.  I have been using it today and it works a treat!  Thanks Heureka.

http://web2.0calc.com/questions/5-11-2-x-1

Heureka also showed us that that the Web2 calculator has a MOD button.  I didn't know that!

http://web2.0calc.com/questions/how-do-i-do-mod-on-this-calc

I'd like someone knowledgeable to comment on the last post by "Someone Who Knows Everything".  Does it make sense?  It's all too much for me.  I liked my own answer.

http://web2.0calc.com/questions/if-there-were-3-skiers-on-plane-of-17-and-4-people-on-the-plane-died-of-a-crash-what-is-the-chance-that-all-3-skiers-survive

Bertie has posted a new proof of pythagoras' Theorum - It is worth the read!!! Thanks Bertie.

http://web2.0calc.com/questions/what-is-the-pythagoras-formula#r107415

The fun continued with this one

http://web2.0calc.com/questions/help-me-please_5

Funny one (at zegroes expense)

http://web2.0calc.com/questions/what-does-x-mean

Who was fibonacci?  (I thought I'd throw in one more serious one) 

http://web2.0calc.com/questions/who-was-fibbanci

Thanks everyone, that is it for today. 

Melody.

May 22, 2014
 #3
avatar+118723 
0
May 22, 2014
 #7
avatar+118723 
+11
May 22, 2014

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