All Answers 356019 Answers

9 1/3 x 5/28 + 7

28/3 x 5/28 + 7

5/3 + 7 =

[5 + 21] /3 =

26 / 3 =8 2/3

1/4=x/4.5+x

1/4 =5.5x / 4.5

1/4 =1.2222...x

1/4 =1 2/9x

1/4 =11/9x divide both sides by 11/9

x =1/4 x 9/11

x =9/44

Why math

Hello Guest!

if the triangle is a right angle triangle, no other angles are given, and only one side is given, how do we have find the other side. No other angles are given and nothing else is given. How do we approach this question?

triangle A B C

Given:

γ = 90°

a = 1 m

You have only two sizes.
To describe a triangle, you need 3 sizes

.
Greeting asinus : -)    !

If y varies directly with x, and y is 4 when x = 1/2, what is the constant of variation?

y = c * x

4 = 8 * (1/2)

The constant of variation is 8.    !

√24 x √80/19

\(\frac {\sqrt {24}\times \sqrt{80}}{19}\)= \( \frac{\sqrt{24\times {80}}}{19}\)= \(\frac{\sqrt{2^7\times 3 \times 5}}{19}\)

= \(\frac{2^3}{19}\times\sqrt{2\times 3\times 5}\)

= \({\color{blue}\frac{8}{19}\times\sqrt{30}}\)     !

what is 6 to the fifth power

\({\color{blue}6^5=7776}\)   !

how can i get 4+7*3^2-2+5*6 to equal 25?

\({\color{black}4+7\times 3^{2}-2+5\times 6 =95}\) 

\({\color{blue}4+7\times 3^{2}-2-5\times 6 =25}\)   !
 

What is 3 to the power of 7

\({\color{blue}3^7=2187}\)  !

  365!/(365^365)= 1.454955215618703403371401590385 x 10^-157

• http://keisan.casio.com/calculator

Sorry Asinus, but that graph is misleading and your conclusion is incorrect.

For small values of x the function behaves as 1/x and the graph will be much as shown.

For large values of x though the 1/x term becomes insignificant and the function behaves as the 

sqrt (x)/32 term and this will tend to infinity as x tends to infinity.

It follows that the function must have a minimum at some point.

To find the minimum, put the first derivative of f (x) equal to zero, (it's at x = 16).

Further, the curve is concave up to begin with but then switches to concave down.

To find the point at which the concavity changes, put the second derivative equal to zero, (it occurs at approximately x = 40.3).

HaHaHaHa Well it’s good to have one troll around again.  

When E.F. Gnome talks, people listen. HaHaHaHaHa that is really good!

The guest is not a troll. He says he’s a banker, but really, he’s a mutant gnome. Most gnomes stand around giving the place an odd look.  This one talks though. When E.F. Gnome talks, people listen, but all they ever hear is blarney.   

It’s great to have trolls back again.  

top to bottom for how it was solved,

go to very bottom for answers

if x + x + x = 30

~ 3x=30

----  x = 10

if x + 2y + 2y = 18​

~ 10 + 2y + 2y=18

~      (2y + 2y) = 4y

~~ 10 + 4y = 18

~~ -10          -10

~~~  4y = 8

~~~ divide both sides by 4

~~~~ y = 2

- check    10 + (2*2) + (2*2) = 18

--  10 + 4 + 4 = 18

--- 18 = 18   

----  y = 2

if 2y - 2z = 2

~ (2*2) - 2z = 2

~~ 4 - 2z = 2

~~ -4          -4

~~~  -2z = 2

~~~  divide both by 2

~~~~ -z = 1

~~~~ *-1  *-1

~~~~~ z = -1

----  z = -1

how much is ' y + x * z '​

      x = 10,   y = 2,   z = -1

~ 2 + 10 * -1

~ PEMDAS

~ 2 + (10*-1)

~~ 2 + (10 * -1)

~~~ 2 + ( -10 )

~~~~ ( -8 )

---- ---- ---- ---- ----    -8 

 4x^2 - 24x + 27  =   (2x -  9) (2x - 3)

1)Find a formula for Sn, the sum of the first n terms of the series:

a) √3 + 3 + 3√3 + 9 +...
b) 12 + 6 + 3 + 3/2 +...

2) A geometric sequence has partial sums S1=3 and S2=4

a) state the first term U1 
b) Calculate the common ratio r
c) Calculate the fifth term U5 of the series 

1 (a)   S_n =  √3 [ 1 - √3ⁿ ] / [ 1 - √3]       note, this series will have an infinite sum

1 (b)   S_n = 12/ [ 1 - 1/2ⁿ]  / [ 1 - 1/2]  =    24 [ 1 - 1/2ⁿ ]     ....note that.....as n  grows larger, the series sum converges to 24

2 (a)  The first term  = 3

2 (b)  The common ratio  is 1/3

2 (c)   The 5th term is given by    3(1/3)^[5-1]  = 3(1/3)^4  = 3/81  = 1/27

I believe the person that posted it made a mistake in stating the question. Here is exactly the same question posed in Feb. 2015:

Feb 17, 2015 10:43 AM+5    

Two trains, each traveling at 60 kph [1 kilometer/minute] are on parallel tracks heading toward one another. One train is one-half kilometer long and the other train is two-thirds kilometer long. The fronts of the two trains pass the same point A at the same time. How many seconds does it take for the two trains to completely pass each other?

Of course, you can only go by what you are given!!!.

The problem actually states that one train is 1/2 km long and the other is 2/3 as long  =  1/3 km........?????

CPhill: You made a slight mistake in combining the lengths of the 2 trains: one is 1/2km long, and the other 2/3km long. Their combined length=1/2 + 2/3 =1 1/6 km, not 5/6km. Thereby, the final answer will be (1 1/6) / (1/30) =35 seconds.

2x^2+3x-20/ x^2+6x+8 {nl} Factorisation

\(2x^2+3x-20 =0\)

a          b          c

\(x = {-3 \pm \sqrt{3^2-4*2*(-20)} \over 2*2}\)

\(x=-\frac{3}{4}\pm\sqrt{169}\)

\({\color{blue}x1=12.25 \ \ \ x2=-13.75}\)

\(x^2+6x+8\)

          p         q

\(x=-\frac{p}{2}\pm\sqrt{\frac{p^2}{4}-q}\)

\(x=-3\pm\sqrt{9-8}\)

 \( \( {\color{blue}\frac{2x^2+3x-20}{x^2+6x+8}}\) = \({\color{blue}\frac{(x-12.25)\times(x+13.75)}{(x+2)\times(x+4)}}\)\)

 \( {\color{blue}\frac{2x^2+3x-20}{x^2+6x+8}}\) = \({\color{blue}\frac{(x-12.25)\times(x+13.75)}{(x+2)\times(x+4)}}\)

The ages of three sisters are consecutive odd integers. The sum of the youngest and oldest sister is twelve less than six times the middle sister. how old is each sister?

Let the ages   =   x , x + 2  and x + 4

And we know that

x + [ x + 4 ] + 12  = 6[ x + 2]     simplify

2x + 16  = 6x + 12         subtract 2x, 12 from each side

4  = 4x     divide both sides by 4

1 = x      this si the youngest sister's age

And the other two are 3 and 5, respectively