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First, distribute the 8 across what is in the parentheses, then subtract 56 from both sides, then divide both sides by -8 to get positive y:

\(8(7-y) = -24\qquad\qquad\text{The original question}\\ 8\times 7 - 8\times y = -24\qquad\text{Distribute the 8 across the inside of the parentheses}\\ 56-8y=-24\qquad\qquad\quad\text{Simplify}\\ -8y=-80\qquad\qquad\qquad\text{Subtract 56 from both sides}\\ y=-10\qquad\qquad\qquad\qquad\text{Divide by -8 on both sides}\)

So, your solution is y = -10

19. If you have 9 apples and add 10 more, you will have 19 apples:

\(o\ o\ o\ o\ o\ o\ o\ o\ o\ o + o\ o\ o\ o\ o\ o\ o\ o\ o = \\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o\ o \)

Press "2nd" key first, then "asin", which is the same as arcsine. Press = key to get your answer.

6 / (4/5) =6 x 5/4 =30/4 = 7 number of boards that are 4/5 foot long

6 - (7*4/5) =

6 - 5.6 =0.4 foot left over. Or 0.4 x 10/10 =4/10 =2/5 of a foot left over.

please help

f(x)  =  x² - 2x - 5

When x = 1:  f(1))  =  1² - 2(1) - 5  =  1 - 2 - 5  =  -6   --->  one endpoint is (1, -6).

When x = 4:  f(4))  =  4² - 2(4) - 5  =  16 - 8 - 5  =  3   --->  one endpoint is (4, 3).

The line through the endpoints  (1, -6)  and  (4, 3)  has slope:  m  =  (3 - -6) / (4 - 1)  =  9/3  =  3.

The Mean Value Theorem states that there is at least one point on the function  f(x)  =  x² - 2x - 5  in the open interval  (1, 4)  that has the same slope (m = 3).

1500 = 2^2 * 3 * 5^3 =10sqrt(15)

5x - 8 = 5 + 4x - 12

Step 1) Group the like terms.

5x - 4x = 5 - 12 + 8

Step 2) Add/Subtract the like terms.

x = 1 

The first derivative of  1  is  0.

The first derivative of  sin(x)  is  cos(x).

The first derivative of  1 - sin(x)  =  0 - cos(x)  =  -cos(x).

Working with only the numerator:  (factoring out  3^{2012 )}

3²⁰¹²·3³ + 3²⁰¹²·3² + 3²⁰¹²·3  =  3²⁰¹²·(3³ + 3² + 3)  =   3²⁰¹²·(27 + 9 + 3)  =  3²⁰¹²·(39)

Working with only the denominator:

3²⁰¹²·3² - 3²⁰¹²·3¹ - 3²⁰¹²  =  3²⁰¹²·(3² - 3¹ - 1)  =   3²⁰¹²·(9 - 3 - 1)  =  3²⁰¹²·(5)

Combining:  3²⁰¹²·(39)  /  3²⁰¹²·(5)  =  39 / 5

JQFFMW:

Did you check to see if the equation balances??!!.

12-8*6=36

x=6

12-8x=36

-8x = 36 - 12

-8x= 24 divide both sides by -8

x= - 3

floor(x/650) where the outcome is 13?

8450<=x<9100

v=n+10t work out the value of v when u= 10 and t= -7

v=n+10t

v=10 + (10*-7)

v=10 + (-70)

v= - 60

What does this equal out to? Log0.71 (0.87)

Log(0.87) / Log(0.71) =0.4066161

Simplify the following:
(x^12 y^3)/(x^2 y^3)

(x^12 y^3)/(x^2 y^3) = y^3/y^3×x^12/x^2 = x^12/x^2:
x^12/x^2

Combine powers. x^12/x^2 = x^(12-2):
x^12-2

12-2 = 10:
Answer: |x^10

I solved it for you

:

=0

Maybe you hate maths because you have no confidence when dealing with it.

You probably find it very difficult and demoralising. 

A really good private tutor could help you but not everyone has access to one of those :(

-3x^-4y^0

Simplify the following:
(-3 x)^(-4 y^0)

y^0 = 1:
(-3 x)^(-41)

Multiply each exponent in -3 x by -4:
(1)/((-3)^4 x^4)

(-3)^4 = (-1)^4×3^4 = 1×3^4:
1/(3^4 x^4)

3^4 = (3^2)^2:
1/((3^2)^2 x^4)

3^2 = 9:
1/(9^2 x^4)

9^2 = 81:
Answer: |1/(81x^4)

Solve for x over the real numbers:
e^(-x)+e^x = 8 (e^x-e^(-x))

8 (e^x-e^(-x)) = 8 e^x-8 e^(-x):
e^(-x)+e^x = 8 e^x-8 e^(-x)

Multiply both sides by e^x:
1+e^(2 x) = 8 e^(2 x)-8

Subtract 1+8 e^(2 x) from both sides:
-7 e^(2 x) = -9

Divide both sides by -7:
e^(2 x) = 9/7

Take the natural logarithm of both sides:
2 x = log(9/7)

Divide both sides by 2:
Answer: |x = 1/2 log(9/7)

C = -6/5 ≈ -1.20000 and D = -3/10 ≈ -0.300000

C = 6/5 ≈ 1.20000 and D = 3/10 ≈ 0.300000

Solve for a:
7 (log(a)+log(c)) = log(b)

Divide both sides by 7:
log(a)+log(c) = (log(b))/7

Subtract log(c) from both sides:
log(a) = (log(b))/7-log(c)

(log(b))/7-log(c) = log(b^(1/7))+log(1/c) = log(b^(1/7))+log(1/c) = log(b^(1/7)/c):
log(a) = log(b^(1/7)/c)

Cancel logarithms by taking exp of both sides:
Answer: |a = b^(1/7)/c

Use the trig identity

\(\displaystyle \cos^{2}(x)=(1/2)(1+\cos(2x))\),

Therafter it's a routine equation of the type

a.cos(theta) - b.sin(theta) = c.

(Write it as Rcos(theta + alpha) = c and calculate R and alpha ).