arc tan(-1) = x/2

-45 (~315) or 135 = x/2

x = 270  degrees    630 degrees

See here : http://web2.0calc.com/questions/how-to-solve-tanx-2-1#r1

x = 33°

z = 109°

y =  [180 - 33 - 109 ] °  =  38°

Just depends on how many digits you want to go:

Atomic weight of

N=14.0067

H= 1.00794     x 3 = 3.02382         NH3 = 17.03052  gm /mole

1.2 x 10^3/17.03052   =   70.46173575 moles

The original weight had only TWO significant digits, so I used 2 significant digits in the atomic weights....LOL

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Since the molar mass of NH3 =17.031 g/mol, then:

[1.2 x 10^3] / 17.031 =70.46... moles of NH3.

Atomic weight of

N=14

H= 1    x 3 = 3         NH3 = 17 gm /mole

1.2 x 10^3/17 = 70.59 moles

Solve for r:
20 r^3 - 20 r + 7.5 = 0

20 r^3 - 20 r + 7.5 = 20 r^3 - 20 r + 15/2:
20 r^3 - 20 r + 15/2 = 0

The left hand side factors into a product with four terms:
5/2 (2 r - 1) (4 r^2 + 2 r - 3) = 0

Multiply both sides by 2/5:
(2 r - 1) (4 r^2 + 2 r - 3) = 0

Split into two equations:
2 r - 1 = 0 or 4 r^2 + 2 r - 3 = 0

Add 1 to both sides:
2 r = 1 or 4 r^2 + 2 r - 3 = 0

Divide both sides by 2:
r = 1/2 or 4 r^2 + 2 r - 3 = 0

Divide both sides by 4:
r = 1/2 or r^2 + r/2 - 3/4 = 0

Add 3/4 to both sides:
r = 1/2 or r^2 + r/2 = 3/4

Add 1/16 to both sides:
r = 1/2 or r^2 + r/2 + 1/16 = 13/16

Write the left hand side as a square:
r = 1/2 or (r + 1/4)^2 = 13/16

Take the square root of both sides:
r = 1/2 or r + 1/4 = sqrt(13)/4 or r + 1/4 = -sqrt(13)/4

Subtract 1/4 from both sides:
r = 1/2 or r = sqrt(13)/4 - 1/4 or r + 1/4 = -sqrt(13)/4

Subtract 1/4 from both sides:
Answer: |r = 1/2               or            r = sqrt(13)/4 - 1/4               or               r = -1/4 - sqrt(13)/4

4(x-6y)  =  4x - 24y

1/2(c-8) =   (1/2)c - 4

(d+2)(-7)   =  -7d - 14

tan(x/2) = -1

tan(x) = -1      at   x =   -pi/4

So    x/2  =  -pi/4   →    x  =  -2pi/4  =  -pi/2

1/2 miles / 1/4 hours =1/2 x 4 =2 miles per hour.

Just multiply: 3 x 1 1/2 =3 x 3/2 =9/2 =4.5 cups will be needed.

Let the number of students =S
0.90S -36 =0.75(0.90S), solve for S
Solve for S:
0.9 S - 36 = 0.675 S

Subtract 0.675 S from both sides:
(0.9 S - 0.675 S) - 36 = 0.675 S - 0.675 S

0.9 S - 0.675 S = 0.225 S:
0.225 S - 36 = 0.675 S - 0.675 S

0.675 S - 0.675 S = 0:
0.225 S - 36 = 0

Add 36 to both sides:
0.225 S + (36 - 36) = 36

36 - 36 = 0:
0.225 S = 36

Divide both sides of 0.225 S = 36 by 0.225:
(0.225 S)/0.225 = 36/0.225

0.225/0.225 = 1:
S = 36/0.225

36/0.225 = 160.:
Answer: |S = 160. Number of students.

SEE ANSWER UNDER YOUR SECOND POST.

Use this formula to calculate the monthly payments on both mortgages:

PMT=PV. R.{[1 + R]^N/ [1 + R]^N - 1}

1) Using above formula, the monthly payment on the 15-year mortgage is =$1,312.33

2)..................................................................................20-year....................=$1,139.60

$1,312.33 x (15x12) =$236,219.40 Principal + interest on 15-year mortgage.

$1,139.60 x (20x12) =$273,504.00 Principal + interest on 20-year mortgage.

$273,504.00 - $236,219.40 =$37,284.60 Extra interest on the 20-year mortgage.

1 search it up

five million dumbass

840_BOOM!

√​(39y​⁹ ) =

y⁴ √​(39y​)

1+1=2 of course

A' B' has the same slope as AB

WHAT IS THE EQUATION OF THE PARABOLA WITH VERTEX(-1-5) AND FOCUS(-5,-5)?

If you meant this:

n^3 = 16 take the cubic root of both sides:

n = 16^(1/3) =2.5198......

1+1 = 2 in base 10 or 10 in base 2