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It appears that the  months of  March -  July  may fit the bill.....[  HAHAHA!!..."fit the bill"...."chicken".....get it   ????  ]....OK....nevermind....

So...we have   

[ 21 + 23  + 22 + 24 + 15 ] / 5  =

105 / 5  =

21  per month

I. because its a voluntary survey

II. becase its a voluntary survey

IV. because 10 ppl can't represent the entire 200

Here are the constraints

y  ≥  x  + 100

x + 2y  ≤ 1400

And  we seek to maximize this

14x + 22y - 900

Here's the graph of the constraints :  https://www.desmos.com/calculator/rjxwpnzj24

a.  We have only one vertex at  (400,500)

b.  This point is a corner point.....the profit max occurs here

So....the max profit  is  14(400) + 22(500)  - 900  = $ 15700

2x + 2y  + z   =  -5   ⇒  -4x - 4y  - 2z  =  10    (1)

3x +  4y   + 2z  = 0    (2)

x + 3y  + 2z  =   1     (3)

Add (1)  and (2)  giving

-x  =  10     ⇒   x  = -10

Add  (1)  and (3)  giving

-3x - y = 11       sub for x

-3(-10) - y  = 11

30  -  y   = 11

y  =  19

So using (3)  to find z, we have

-10  + 3(19)  + 2z   = 1

-10  +  57  +  2z  = 1

47  +  2z  =  1

2z  =  -46

z  =  -23

So......{x,y,z}   =  {-10, 19, -23}

4x^2 - 9x  - 9  = 0       factor as

(4x + 3) (x - 3)   =  0

Setting each factor to 0 and solving for x gives that  x  = -3/4   or  x  = 3

3x^2  + 14x   +  8

We can write this as

3x^2   +  12x   +  2x  +  8            factor by grouping

3x(x + 4)  +  2(x + 4)             take out the GCF  =  x + 4

(x + 4) (3x + 2)

y  =  35x  - 7

The slope of this line  = 35

So.....the slope of a parallel line has the same slope ....so....

y  = 35 (x - 15)  +  8

y = 35x  - 525  + 8

y  =  35x  -  517

Let A  =  length of one side

A  =  sqrt   [ (1 - 4)^2  + (5 - 3)^2 ]  =  sqrt [ (-3)^2  + 2^2 ]  = sqrt [13]

Let  B  =  length of perpendicular side

B  = sqrt [ (4 - 0)^2  +  ( 3 -  -3)^2 ]  =  sqrt [ 4^2  + 6^2]  =  sqrt [ 52]  = sqrt [ 4 * 13]  =

2*sqrt [13]

So.....the area  =  A * B  =  sqrt [13] * 2 sqrt [13]  = 2 * 13  =  26 units^2 

8^(2x)  =  4096

Note that   8  = 2^3       and  4096  =  2^12

So

(2^3)^(2x)   =  2^12

2^(6x)  =  2^12         solve for the exponents

6x  = 12       divide both sides by 6

x  = 2

We can use synthetic division here to find the remaining polynomial

3 [ 2    -9      11      - 6  ]

            6       -9        6

   __________________

    2     -3       2        0

So.....the remaining polynomial  is    2x^2  - 3x   +  2

Sorry.....i'm not great at probability....maybe someone else can help.....

A spinner is divided into five equal sections labeled 1, 2, 3, 4, and 5. Another spinner is divided into two equal sections labeled A and B. Nigel will spin each spinner one time.

How many of the possible outcomes have a number less than 3 or an A?

We have 10  possible outcomes   =  Number Outcomes  * Letter Outcomes  =  5 * 2  = 10

So.....the ones we are interested in are

Outcomes < 3   =  2

Outcomes  = A  =  5

So.......outcomes < 3 or outcomes  = A     =  2  +  5    =   7  

An experiment involves selecting a numbered chip, some black and some white, from a bag of chips. The probability of selecting a black chip with an odd number is 1/4 . The probability of selecting a black chip is 2/3

.

What is the probability of selecting a chip with an odd number given that the chip is black?

(Answer as a simplified fraction please)

Let P(Black)  =  2/3

Let P(Black and Odd)  = 1/4

And  we are trying to find P( Black and Odd I Black)

So....

P( Black and Odd I  Black)  =  P( Black and Odd)  / P(Black)  = 

(1/4)  / (2/3)  = 

(1/4) * (3/2)   =

3/8

no problem

Alright :) thanks again

yep i have email pm me and i will give it to you

That's not one of the answer choices.

1/5

2/7

9/350

6/35

Probably should have included that in the post.

Ok cool thank you thank you so much.., do you have an email.., could i email you.. or i might can type it up in here i thnk

yep no problem

So you can help me with it!? :)

yea i read a lot i read literally everything

Could you help me!? Do you know the book The Night Thoreau Spent in jail??

P(Two Black Beads)  =  P(Black Bead on First Draw)  * P(Black Bead on Second Draw)  

So we have

(3/35)   =  (3/10)   * P(Black Bead on Second Draw)

Multiply both sides by (10/3)

(10/3)(3/35)  =  P(Black Bead on Second Draw)  =

10/35

We can confirm this

Let  A  = P(Black Bead on first Draw)  =  3/10

Let B  = P(Black Bead on the Second Draw)

Let  P(A and B)  =  3/35

So

P(B / A)  =  P(A and B)  / P(A)   =   (3/35)  / (3/10)  =  (3/35)(10/3)  =  10/35

i am 

for the top one

70% is most likley

Assuming that  the number cube has the possible outcomes of1,2,3,4,5 or 6.....the probability of rolling a number >  4     =  [  2 favorable outcomes ] / [6 possible outcomes ]  =  2/6  = 1/3

And the probability of spinning an even number = 

[ 6 favorable outcomes] / [ 12 possible outcomes] =

6/12   =   1/2 

So....the probability  =  P(first event) * P(second event)  =  (1/3) * (1/2)   =  1/6

Thank you, kind sir.