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We have 90*2*2*2, because it doubles every 4 hours, and 12/4=3, so 3 two's.

Thus, the answer is \(\boxed{720}\)

THank you!

The center is ( -2, -1) and the radius is 7

So....using   (x - h)^2  + ( y - k)^2  = r^2  where   (h , k) is the center and r is  the radius, we have

( x - -2)^2  + ( y - - 1)^2  = 7^2

(x + 2) ^2  + (y + 1)^2  = 49         expand   and simplify

x^2  + 4x + 4  + y^2   + 2y  + 1  = 49

x^2 + y^2 +  4x   + 2y  +  5 = 49       subtract 49 from  both sides

x^2 + y^2  + 4x  + 2y  - 44  =  0      ⇒   Answer  "B"

Thank you!

Hello lysxsa!

The standard equation for a circle with center (a,b) and radius of c is:

\((x-a)^2+(y-b)^2=r^2\)

Using this, we can create our equation necessary to answer the question. 

Since we already know the center and the radius, we can just plug in our values. 

\((x+8)^2+(y+13)^2=13^2=169\)

I hope this helped,

Gavin

I think that's the way it is.

The directional cosine  is

-3  / sqrt  [ 7^2  + 4^2 + (-3)^2  ] =

-3 / sqrt  [ 49 + 16 + 9  ] =

-3  / sqrt [ 74 ]

Julius...I believe the answer  is  "C"....a force  of 23 N  in the SouthEast direction will bring the system  into equilibrium

We can solve this :

20 cos (theta)  = 12

cos (theta)  = 12/20

cos (theta)  =  3/5

arccos (3/5)  =  53.13°  = theta

THEYRE BOTH

S H I T T

Rate  of change  =

[ Profit in year  4  - Profit  in year 2  ]  /   [ 4 - 2 ]  =

[217.2  - 238.4  ] /  2  =   -  10.6

Profits decreased by an average of $10,600  from year 2  to year 4

We have

cos (theta)  =  dot  product  /  [ product  of the vector  magnitudes ]

cos (theta)   = 8  /  [ 4 * 5  ]

cos (theta)  = 8 / 20  =   2/5

To find theta

arccos ( 2/5)  = theta  =   66.42°

The scale factor  from the smaller figure  to the larger  is  12/ 9 =  4/3

So...the area of the larger figure  is  = 

Area  of smaller figure *  (scale factor)^2  =

27 *  ( 4/3)^2  =

27 / 9  *  16  =

3 * 16  = 

48 cm^2

Let the first vector lie along the  x axis

Its components are :

5cos 0°   =  5

5 sin 0°   =  0

For the second vector we have

So..its components are

7 cos 50°     and

7 sin 50°

So....the sum of the components  is

5 + 7 cos 50°  =  5 + 7 cos 50°    and

0 + 7 sin 50°   =   7sin 50°

So...the magnitude of the resultant  vector  is  given by     sqrt  [ (  5 + 7 cos 50°)^2  +  (  7sin 50°)^2 ]   ≈  10.91 N

This is a hexagon with an apothem  of   5sqrt(3)  cm

The area is given by  :  6 * (1/2) (side length)^2  *  sqrt (3)  / 2

We can find the side length  as   2 *  5*sqrt(3)  / sqrt(3)  = 2 * 5  = 10 cm

So....the area is

6* (1/2)  10^2 * sqrt(3)  / 2  =

3 * 100 * sqrt(3)  / 2  =

150sqrt(3)  cm^2  ≈   259.8 cm^2 

This is a 30-60-90 right triangle

The side opposite the 30 degree angle  = 5  = the base

The side opposite the 60 degree  =  sqrt(3)  *  the  side opposite the 30 degree angle  = 5*sqrt (3)....this is the height

So....tha area is   

(1/2)  base * height  = 

(1/2) 5  *  5sqrt(3)    =   

 ( sqrt (3) / 2) * 25  cm^2  ≈ 21.65 cm^2

A quarter has a diameter of  24.26  mm  ≈  .955 in

And the  height (thickness)  is 1.75 mm ≈  .0689   in

So....the volnme of one quarter  is the volume of a cylinder with a diameter of  955 in and a height of .0689 in  =

pi ( .955/2)^2  * ( .0689)    ≈  .04935 in^3

So  (theoretically), the number of quarters that would fit in the box is ≈  182.876 in^3  / .04935 in^3  ≈  3706 quarters

You need to make an open-top box from a rectangle of cardboard 9 by 13 inches by cutting a square from each corner and folding up the sides. You want the box to have the maximum possible volume. Complete the following problems showing all your work:

Unfortunately, I do not know the diameter and height of a 25-cent pieces!

Arc length  =   2pi * radius  *  (given angle  / 360)     ...so we have

Arc length =  2pi * 6  *  (45  / 360) 

Arc length  = 12 pi * (1/8) 

Arc length  =  (12/8) * pi    =   (3/2)  pi   ( inches  )

P A l B )  =   .3 / .54  =  .55

P (B  l A )   = .3 / .55  = .54

P (A )  = .55

P(B)  = .54

Drinking  coffee and drinking water are independent events because  P(A l B)  = P(A)  and P (B lA)   = P(B)

We have this:

A  = 90 * (2)^(t/4)       where A is the amount present after  t hours

So...after 12 hours, we have

A  = 90 * (2) ^(12/4)

A = 90  *  (2)^3

A = 90 * 8

A =  720 pounds  =  "A"

Its A

1. 12.3

2. Yes, yes, no, yes

See the First answer here:

https://web2.0calc.com/questions/4-11