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do you know how many months are in a year?

divide by it

She has to pay the $ 4999 in 9 payments to avoid a penalty....   so   4999/9 = ?     Do you see?

Well.....the total PAYBACK   HAS to at LEAST equal the amount of the loan....plus interest....the only choice is "D"  because the other answers are all LESS than the original loan amount !

Brianna works as a customer service representative. She knows that the amount of her yearly bounus is $155,

but $2.50 is taken away for each customer complaint about her during the year.

What is her bones if there are 12 complaints about her in the year?

$155 - 12 x $2.50

= $155 - $30

= $125

The sum of two numbers is 16 and their product is 35.

Find the reciprocal of the sum of the two numbers.

\(\begin{array}{|lrcll|} \hline (1) & x+y &=& 16 \\ (2) & xy &=& 35 \\ \\ \hline \\ \dfrac{(1)}{(2)}: & \dfrac{x+y}{xy} &=& \dfrac{16}{35} \\\\ & \dfrac{x}{xy}+\dfrac{y}{xy} &=& \dfrac{16}{35} \\\\ & \mathbf{ \dfrac{1}{y}+\dfrac{1}{x}} &\mathbf{=}& \mathbf{\dfrac{16}{35}} \\\\ \hline \end{array}\)

Total value in Arturo's eyes is 4+5+3 =12

45 snickers = 45 x .04 = 1.8

30MW        =30 x .05  = 1.5

75 R           =75 x .03 = 2.25       Total = 5.55    

  Arturo will obviously think this is a little short of 1/2  the value (which would be 6.00)

Your question states the sum of the numbers is 16....the reciprocal of this sum is 1/16

Did you mean to ask for the SUM of the RECIPROCALS of these numbers? (As Tertre calculated?{though Tertre used 13 instead of 16} )      ( I think the answer will be 16/35......tertre must have used '16' in calculations )

Total value   $7       any combo that totals 3.50 is a 'fair' 1/2

50 Snickers = .50

50 MW =2.0

50 R =  1.0                Total = 3.50

There are a 'buh-jillion' ways to split this to obtain 3.50 value....this is just ONE!

Another example:

100 S = 1.0

50 MW = 2.0

25 R = .50          Total 3.50

Each S=.01    Each MW=.04     Each R=.05

TOTAL VALUE    100x.01 + 100x.04 + 100x.05 = 10

25 S = .25    25 MW=1.0   65 R = 3.0    

                        Total value of Jane's division = 4.25 (in Salvadore's eyes) ....A little LESS than half! 

Let A represent the total amount of money

      r represent the registration fee.

There were 124 new members. Since 50 had their initial registration fee waived, 74 paid the registration fee.

--->     Amount earned at registration:  A = 74·r

Assuming that no-one dropped out, 6 months later:

Let m represent the monthly fee

--->   Total amount earned for the first 6 months:  A  =  74·r + 124·m·6

$ 18     4   slices of P   and 4 slices of  V

If he thinks veggie is three times more valuable than pepperoni

  then  4V(3) + 4P = 18  

     Each V = 3.375     P= 1.125  (in his sick mind)

         1/2 V + 1/2 P = 2.25

3x+2y=-1, x=2y=5, adding both cancels out y, so we are left with: 4x=-1+5, 4x=4, x=1.

Plugging the value of x in the second equation to solve y, we have 1-2y=5, -2y=4, y=-2.

Check for the first equation: 3(1)+2(-2)=3-4=-1.

Substitute   x = 1   in to any of the equations ....then you can find 'y'....

Thank you. No i am still unsure of how to carry out the rest of the problem. 

Welcome! 

Add the two equations together to get:

4x = 4       so x = 1     can you get the rest from this?

We have 3x+2y=−13x+2y=−1 and x−2y=5.

Simplifying the first equation: 3x+2y=-13x+2y, 16x=0y, so 16x=-1, and x=-1/16.

Plugging the value of x in our second equation: \(\frac{-1}{16}-2y=5, -2y=\frac{81}{16}, 2y=\frac{-81}{16}, y=\frac{-81}{32}.\)

We can set up two equations!
1.5c+4a=734 and c+a=281.

We multiply the second equation by 4 but leave the first equation as it is. 

So, 1.5c+4a=734, 4c+4a=1124

Subtract, 1.5c-4c=734-1124, -2.5c=-390, 2.5c=390, c=\(\boxed{156}\)children and 281-156=\(\boxed{125}\) adults. 

Let F= registration fee

People who paid the fee = (124-50) = 74

74F = total fees collected

Thank you so much

Let  c= # children     then   281-c = # Adults

     1.5 c = money from child tix           4(281-c) = money from adult tix

1.5 c  + 4(281-c) = 734

1.5 c =1124 - 4c = 734

-2.5c = -390

c=156 children

281-c = 125 Adults

Good job, Rick! You should absolutely round to the nearest hundredth place. The context of this problem deals with money, and the smallest modern currency only comes in denominations of cents. Fitting this context requires you to round. 

The reciprocal of the sum of the two numbers can be written as \(\frac{1}{x}+\frac{1}{y}\)

We have \(x+y=16, \) and \(xy=35\) , so we can find the LCM of \(x\) and \(y\) .

So, we have: \(\frac{x}{xy}+\frac{y}{xy}\) . Adding both fractions, we get,\(\frac{x+y}{xy}\) and plugging in the values we finally attain: \(\boxed{\frac{16}{35}}\) .