All Answers 358600 Answers

XD yep that is true XD

XD I play fortnite lololololol but I dont play battle royale.

Roblox is fun too i played that when I was in 6th grade

Oh, the good old days of my childhood. BUt im still in childhood lol. THe old people on this forum are jealous we have so much life ahead of us.

Call the pounds of fish sold,  F

So...the pounds of chicken sold  =  pounds of fish sold + 20% more  =  F  + .20F   ....so we have

F + .20F =  3600

1.20F  = 3600       divide both sides by 1.20

F  =  3000

Remember that  the sine is positive in the first quadrant  and in the second quadrant

And we have the identity that  sin (180° - A)   =   sin 180°cos A - sin Acos180° =

0*cosA  - sinA*(-1)   =  sin A

So.....

sin  (180° - 75°)  =   sin (105°)  =  sin (75°)

I understand why b is an answer, but could you explain why c is?

arcsin (0.9659)  = b.  75°±360°    and  c. 105°±360°k

I think it's just it's contental location....

why does America have so much natural disasters XD

in these problems, remember PEMDAS
 

P  - Paranthesis

E  - Exponents

M  - Multiplication

D  - Division

A   - Addition

S   - Subtraction

So your mistakes was that mn⁰ had no paranthesis around "mn". So using PEMDAS, you first calculate n⁰. Then multiply that with m.

Thanks a mill I was getting that wrong

Asuuming that n is not  = 0......n⁰  = 1

So

mn⁰  = m * (1)   = m

EVACUATE NO the day before (hint: the tornado was at 3 am) was sunny without a cloud in the sky

I see that's intresting, I'm surpirsed youd idn't evacuate though that's still very risky... 

well not really because the house was made in 1936 and has a brick innercoat because the house was made in world war 2

also a wood outer coat

EF - 4 are you sure? were talking 166 - 200 MPH wind's they rip traditional house's of there foundation and collapse them and apratment building's loose about two to 3 story's... and you slept? XD I mean if it's on your house that house is goign to completly rip apart... I would say your lucky to be alive... 

also not to mention's the counter varible's of the other tornado in porximaty and debri's flying....

EF 4 and a EF 2 both in the same are at the same time the one on top of the house was EF 4

What level of catagory was it EF - 0 through EF - 5 ?

agreed but try geogia sunny and warm and a lot of dry days with evening showers and I slept through a tornado a year ago and it was right on top of the house LITERALY

You should try florida ;) plenty of hurricane's.... and let's say there a whole more exciting than a thuderstorm...

I feel so jealous! Here in Illinois, nothing happens! Everybody in my class gets EXCITED if there is a THUNDERSTORM! It's so boring here the weather is ALWAYS cloudy and the air is cold.

California seems like such an exciting place, that's why a lot of my friends dream of going to California lol.

A lot of people in our class actually WANT earthquakes and tornadoes because nothing EVER happens.

XD (I thought you were on my side) XD anderson say's I'm to old all the time, I would perfer to be in my youth, I frankly don't want to get old, It's a tough world outside your parent's house XD

Thanks Tiggsy    

Tommarvoloriddle, This is not the kind of crowd you want to hang out with... I doubt to a highly degree that's it's even diffrent people... It's jsut the same guest trying to gain "Fake" support, for his disgusting article's.. He's quick to make fun of people that have done absolutly nothoing... Fortuntalty his pretty bad at making name's because I know soem 8 year old's that can make clean joke name's that bring humor better than his... 

What this guest relie's on for his humor is Inapprorptiate language, and immoral text about past event's and thing's that never even happeend.

3)
Find \(f(k)\) such that: \(\sum \limits_{k=1}^n f(k) = n^3\).

\(\begin{array}{|rcll|} \hline \sum \limits_{k=1}^n f(k) &=& n^3 \\ \underbrace{\sum \limits_{k=1}^{n-1} f(k) }_{=(n-1)^3} + f(n) &=& n^3 \\\\ (n-1)^3 + f(n) &=& n^3 \\ f(n) &=& n^3-(n-1)^3 \\\\ \mathbf{ f(k) } &=& \mathbf{k^3-(k-1)^3} \\ \hline \end{array}\)

Let u, v and w be vectors satisfying

\(u*v=3, u*w=4, v*w=5\).

Then what are 

\((u+2v)*w, (w-u)*v, (3v-2w)*u\)

equal to?

\(\begin{array}{|rcll|} \hline && \mathbf{ (u+2v)*w} \\ &=& u*w+2v*w \\ &=& 4+ 2*5 \\ &=& \mathbf{14} \\ \hline && \mathbf{(w-u)*v} \\ &=& w*v-u*v \\ &=& 5 -3 \\ &=& \mathbf{2} \\ \hline && \mathbf{(3v-2w)*u} \\ &=& 3v*u-2w*u \\ &=& 3*3-2*4 \\ &=& \mathbf{1} \\ \hline \end{array}\)