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Acceleration is change in velocity divided by change in time

(15 m/s-35 m/s) / 4 s = -5 m/s²

v=at

7850 m/s = 29 m/s²   *t                 solve for t=270.7 sec

you are given   m    and  h      and you want  m/h    just divide  m/h     3/5 m  /  1/4 h

1 - Multiply the "Ticket Price" by "Number Sold" in each category. Then add the four totals together.

2 - Add up all the tickets sold under "Number Sold"

3 - Divide the total in (1) above by the total in (2) above.

4 - If you don't make any mistakes, you should get: $4.10 - the average ticket price.

$12.50 / (2/3) =

$12.50 x (3/2) =

$37.50 / 2        = $18.75 cost of 1 pound of candy.

Can you write your question in "plaintext"? I can't read it !.

That's some cool stuff!

thx so much

thank you rom.

Rate or Speed = Distance / Time

                          =  (3/5) / (1/4)

                          = (3/5) x (4/1)

                          = 12 / 5

                          = 2.4 miles per hour.

7x-2x=0.6+0.15

5x=0.75

Can you solve from here?
 

You are very welcome!

:P

Here's something that you need to know to solve this problem: It's a Cyclic Quadrilateral.

Cyclic Quadrilaterals are basically quadrilaterals that can be inscribed in a circle.

In Cyclic Quadrilateral LMNP, angle L + angle N = 180, and angle M + angle P = 180. That's just the property of one.

Angle M = arc LP + arc NP / 2, or 123 degrees.

So angle P = 180-123 = 57 degrees.

You are very welcome!

:P

x-5-(2-x) = -3

You can use the distributive property on the -(2-x) so that -1*2 = -2 and -1*-x=x, so -(2-x) = -2+x

x-5-2+x = -3

2x-7=-3

Can you solve it from here?

You are very welcome!

:P

i do not know this one sorry

Did you want the angle EA or the "Length of arc EA"? They are 2 different things.

The length of EA, as a segment of the circumference, was not the question. 

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it was the mesure of the arc, Not the length.

Masterx4020: On the first question: Did you want the angle EA or the "Length of arc EA"? They are 2 different things.

Thank you everyone who helped me. I understand it now. I have another question I am struggleing with and it is this one.

IT wants me to find angle LPN. How do I Get the angles on inside the quadraltiral? Thanks again.

We can see that it goes down by 2 each time.

We can write an equation.

-2x+12 is the equation where x is the place of the number (so if x = 1, then it will be the 1st number)

Then -2(20)+12 = -28, or answer C

when you add up the rest of the arcs it goes past 360 degreees  

I don't think so, MasterX4020.  Let's add them up.

AB   +   BC   +   CD   +   DE   +   EA 

38^o  +   52^o  +   90^o  +   38^o  +  142^o  =  360^o                                              

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I'm not sure about this, because i'm not sure if DA and EB are diameters of the circle or not. If they are, then I can answer.

However, if we assume that EB is the diameter...

Arc EB is 180 degrees (the arc that goes through points D and C).

All together, then angle DOC (where O is the center) + angle BOC + angle EOD = 180

We already have 90+52 which is 142

180-142 = 38

So EOD is 38 degrees.

Now, arc AD is 180 degrees (again assuming that AD is the diameter)

So simply do 180-38 which is 142

So arc EA is 142.

You are very welcome!

:P

180° - 90°-52° = 38°

52+90+38 = 180

142+38 = 180

line BE is 180

when you do the math the angle of 52+90+38=180

so..

The same goes for AD 52+90+38=180

There for 142+38=180

So...

180+180=360

agreeded with guest

I did that but when you add up the rest of the arcs it goes past 360 degreees. I don't think it is suppose to do so.