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Make sure the exponents are the same!

For example \(2.8*10^3-1.4*10^3\)

Basically is 2800 - 1400

Since the exponents are the same, just do 2.8 - 1.4 = 1.4

\(1.4*10^3\)

Just assume its 26 letters and 10 numbers, because it says "character".

Coordinate Geometry may be useful in this.  (the following graph is not to scale)

Find slope of line FB

So we find the rise and run of EB

The rise is 7,  and the run is 5.

So the slope of FB is \(-\frac{7}{5}\)

We know that the line FB intersects the x-axis, so the x-intercept is (7,0)

We have the equation \(y=-\frac{7}{5}x+b\).      Finding the y intercept will help us find the length of DF

We solve for b by plugging in (7,0) into our above equation. 0=-(7/5)*7+b = b=(49/5)

So the y intercept is (0, 9.8)

That means that AF = 9.8, and since AD is 7,

9.8 - 7 = 2.8

\(\boxed{DF\text{ is } 2.8}\)

How long would it take to break a 200-character password      

Some important data is missing from the question.  How large is the pool of characters from which the 200 were chosen?

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....so like would the domain be {1,3,6,9} 
and range {2,4,6,8}......

Correct  !!!

This would also apply to   discrete graphs

It still didn't work

hmm i remember a couple of years ago i got something similar to this on one of my homeworks and i found a youtube video that explained it pretty well... 

let me see if i can find it 

https://www.youtube.com/watch?v=3dQLWb86U18 

it's not the same exact problem but it is very very similar to the one you need help on... 
i hope it helps you ^-^

I was still stuck

I think it was answered here 

https://web2.0calc.com/questions/please-help_34668

2)   Answered here :  https://web2.0calc.com/questions/find-a-b-c-if-the-graph-of-the-equation-y-ax-2-bx-c-is-a-parabola-with-vertex-5-3-vertical-axis-of-symmetry-and-contains-the-point

#1There are (63)=20(63)=20 possible ways for inviting the two. Also, there are (65)=6(65)=6 ways of not inviting them. Thus, there are 26 possible invitations that satisfy these criteria ((63)+(65)=26(63)+(65)=26) \(26\)

#2 use combinations for this one also

What do you have in mind to do first?

....

try drawing a chessboard first.

Let the side of the square be  =  S

Because XW = YZ.....then WZ  is parallel to AC

Triangle ABC  is right with angle ABC = 90°

So.... 

angle BZW  = angle BCA 

angle BWZ  = angle BAC

And angle ZYC  = angle WXA = angle ABC  

Triangle YCZ is similar to triangle BCA  by AA congruency

So

YC / ZY  = BC/BA

YC / S  = 4/3

YC  = (4/3)S

And triangle XAW  is similar to triangle BAC  by AA congruency

So

AX / XW  =  BA / BC

AX / S = 3 /  4

AX  = (3/4)S

And  

AX + XY +  YC  =  5

So

(3/4)S  + S  +  (4/3)S  =  5

S [ 3/4 + 4/3 + 1 ]  = 5

S [ 9/12 + 16/12 + 12/12 ] / 12  = 5

S [ 37/12]  = 5

S  =  5 (12) /37   =  60 / 37

No Problem, Thanks for the graph Melody!

....

Nope.

Since  angle ABC  = angle BDE   then  in triangle ADB,  AB  = AD  =  21 + 27  =  48

And  angle ABC  = angle BDE

And angle BDE  = angle BDE

So  by AA congruency,  triangle  DEB   is similar to triangle  DBA

So

DE / DB  =  DB/ AD

27/ DB  = DB/ 48

27 * 48  =  DB^2

1296  =  DB^2

36  =  DB

The EB  also =  36

And because  angle ABC  = angle  CAB =  angle DEB  = angle  BDE, then by AA congruency, triangle BAC is similar to triangle DEB

So 

CA / BA  = EB / DE

CA/ 48  = 36 / 27

CA / 48  =  4/3

CA  =  48 * 4  / 3    

CA =  48/3 *  4

CA  =  16 * 4

CA  =  64

Two congruent cylinders each have radius 8 inches and height 3 inches. The radius of one cylinder and the height of the other are both increased by the same nonzero number of inches. The resulting volumes are equal. How many inches is the increase? Express your answer as a common fraction.

Zwei kongruente Zylinder haben jeweils einen Radius von 8 Zoll und eine Höhe von 3 Zoll. Der Radius eines Zylinders und die Höhe des anderen Zylinders werden um die gleiche Anzahl von Zoll ungleich Null erhöht. Die resultierenden Volumina sind gleich. Wie viel Zoll ist die Zunahme? Drücken Sie Ihre Antwort als gemeinsamen Bruch aus.

\(V=h\pi r^2=h\pi r^2\\ V_2 =3''\cdot (8''+x)^2=(3''+x)\cdot (8'')^2\\ 3\cdot (64+16x+x^2)=192+64x\\ 192+48x+3x^2-192-64x=0\)

\(3x^2-16x=0\)

\(x_1=0\\ 3x_2=16\\ \color{blue}x_2=5\frac{1}{3}\)

\(5\frac{1}{3}\ inches\ is\ the\ increase.\)

  !

asinus

We have 155 six hour blocks of time

So  we can compute this

(6 * 155) mod 24  =  18

So........it will be 18 hours after 1 o'clock  =   7 o'clock

y=2.5cos(4x)cos(4x)-2.5sin(4x)sin(4x)

We can use an identity to  write this as

y  =  2.5cos (4x + 4x)   =   2.5cos(8x)

The amplitude  is  2.5

It will be wednesday as well.

Why??

Well, "Wednesday was the last day of the school year" The start of the school's new year is after 77 days.

Now let's calculate it in weeks instead of days 

77/7 (Because there are 7 days in a week) =11 weeks

We are already on wednesday...after 11 weeks it is going to be wednesday.

Assume wednesday is the 4th day of the week, 4*11=44 day ( must be also wednesday) 

Your failure to cite the source is why you now have minus 9 points.

Why do you think it’s OK to copy and paste a text without citing a source?

Doing this for a school assignment can result in failing the class –not just the assignment.