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-4  =  (9/5)C + 32      subtract 32 from both sides

-36  = (9/5)C    multiply both sides by 5/9

-36 (5/9)  =  -20

[ -9 - 7 + 32 + 5 ]  / 4  =  

[ 21] / 4  = 5.25 ≈   +5 per month

102 * .05   =   $5.10

.92 * 42   = 38.64  ≈  39 questions

50  =  (9/5)C + 32     subtract 32 from each side

18 = (9/5)C      multiply both sides by 5/9

(5/9)(18) = C  =  10

A. true

A basketball team’s score was 94 points. If you doubled the opposing team’s score and subtracted 40, you would also have 94 points. What was the visiting team’s score? (Guess and check or creating a table may work well here.)

Not sure what the first statement  has to do with this.....but  I get that

2S - 40  = 94      add 40 to both sides

2S  = 134           divide both sides by 2

S = 67  =  the visiting team's score

Good Stuff is giving away free pens to each of the first 500 people who come in the store today. In the first hour, they gave away 30% of the pens. How many is this?

500 * .30   =  150

Benjamin is treating his friends to a meal at Chez Food. The meals added up to $149.45. An automatic gratuity of 20% was tacked onto his bill - what is the amount of the tip?

149.45 (.20)  = $29.89

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Answered here : https://web2.0calc.com/questions/geometry-help_92

900/3  = $300

870/3  = $290

So   since  $875   is between  870  and 900.....we might guess that the answer is between 290 and 300

But 292 * 3   ends in a "6"....so this isn't correct

So  $291.67  appears to be correct

Good Morning Guest!

\(\frac{10.5}{8+6}=\frac{\overline{PR}}{8}\\ \overline{PR}=\frac{10.5\cdot 8}{8+6}\)

\(\overline{PR}=6\)

  !

Thank you! Rom

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No CU: it says "Let n be number of ordered "quadruples", or "sets of four", but not "pairs".

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That is right.... but Not the answer im looking for.

From looking at it i dont think it would rationalize well so i just subbed in the trig expression straight away and attempted to simplify with identity

Yeah that ad was good... I was even considering to use it!  lol

Oh lol you plug in for BOTH

A 1 * 30 lane? I am confused, a chess board is 8 * 8

is there a picture that comes with the problem?

Good job! Guest! However the problem is asking how many ordered pairs,     EDIT: THIS IS WRONG

so we have one last step

One ordered pair can be ordered in 4! = 24 ways

So using your 39 ordered pairs,

39 * 24 = 936

OK! Here is my attempt at this: I have used the first 17 odd numbers that sum up to 42. This is a partition problem summing up 4 odd numbers to equal 42. I have NOT considered the permutations of any one sum. For example: 1 + 3 + 5 + 33 =42 is considered as "one ordered quadruple", and NOT 4! = 24 permutations.

1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33

1 - 33 + 5 + 3 + 1 = 42
2 - 31 + 7 + 3 + 1 = 42
3 - 29 + 9 + 3 + 1 = 42
4 - 29 + 7 + 5 + 1 = 42
5 - 27 + 11 + 3 + 1 = 42
6 - 27 + 9 + 5 + 1 = 42
7 - 27 + 7 + 5 + 3 = 42
8 - 25 + 13 + 3 + 1 = 42
9 - 25 + 11 + 5 + 1 = 42
10 - 25 + 9 + 7 + 1 = 42
11 - 25 + 9 + 5 + 3 = 42
12 - 23 + 15 + 3 + 1 = 42
13 - 23 + 13 + 5 + 1 = 42
14 - 23 + 11 + 7 + 1 = 42
15 - 23 + 11 + 5 + 3 = 42
16 - 23 + 9 + 7 + 3 = 42
17 - 21 + 17 + 3 + 1 = 42
18 - 21 + 15 + 5 + 1 = 42
19 - 21 + 13 + 7 + 1 = 42
20 - 21 + 13 + 5 + 3 = 42
21 - 21 + 11 + 9 + 1 = 42
22 - 21 + 11 + 7 + 3 = 42
23 - 21 + 9 + 7 + 5 = 42
24 - 19 + 17 + 5 + 1 = 42
25 - 19 + 15 + 7 + 1 = 42
26 - 19 + 13 + 9 + 1 = 42
27 - 19 + 13 + 7 + 3 = 42
28 - 19 + 11 + 9 + 3 = 42
29 - 19 + 11 + 7 + 5 = 42
30 - 17 + 17 + 5 + 3 = 42
31 - 17 + 15 + 9 + 1 = 42
32 - 17 + 15 + 7 + 3 = 42
33 - 17 + 13 + 11 + 1 = 42
34 - 17 + 13 + 9 + 3 = 42
35 - 17 + 13 + 7 + 5 = 42
36 - 17 + 11 + 9 + 5 = 42
37 - 15 + 13 + 11 + 3 = 42
38 - 15 + 13 + 9 + 5 = 42
39 - 15 + 11 + 9 + 7 = 42

2 ways

1) Get the exponents equal to eachother

2) Brute force, convert to a real number

for example 5.32 * 10⁸ = 532000000

You add n to one

so "none"

Here is a start of a list for you

1 3 5 33

1 3 7 31

1 3 9 29

1 3 11 27

Good luck! 

I have never done calculus or integration or anything, but just a suggestion

Will rationalizing the denominator help?