Do you really think so? It can easily be done as well, since the code I wrote can easily sum them up.
And the sum of 50,412 lucky numbers =27,336,542,310 mod 13 =12
CU: Here is the computer code in question:
a=1;b=0;c=0;d=0;e=0;f=0;p=0; cycle:if(a+b+c==d+e+f, goto loop, goto next); loop:print a*100000+b*10000+c*1000+d*100+e*10+f,", ",;p=p+1; next:f++;if(f<10, goto cycle, 0);f=0;e++;if(e<10, goto cycle, 0);f=0;e=0;d++;if(d<10, goto cycle,0);f=0;e=0;d=0;c++;if(c<10, goto cycle,0);f=0;e=0;d=0;c=0;b++;if(b<10, goto cycle,0);f=0;e=0;d=0;c=0;b=0;a++;if(a<10, goto cycle,0);print"Total = ",p