Ane even function is one where f(x)=f(-x)
When you graph is it will be symmetrical about the y axis.
$$f(x)=x^2$$ is an example of an even function because f(x)=f(-x) eg f(3)=9 f(-3)=9
There is more than one graph that will fit this description.
but here is one of them.
Perhaps one of the other mathematicians can tell me what the equation of a graph like this might be?
I really have no idea.
Hi DragonSlayer554,
compare
Solve on the interval [0,2pi): 4cscx+6=-2
$$\\ 4 \csc{(x)}+6=-2 \quad | \quad -6 \\ 4 \csc{(x)}=-8 \quad | \quad :2 \\ \csc{(x)}=-2 \quad | \quad \csc{(x)} = \frac{1}{\sin{(x)}} \\ \frac{1}{ \sin{(x)} } = -2 \\ \sin{(x)} = -\frac{1}{2}$$
$$x_1 = \sin^{-1}{(-\frac{1}{2} )} \\ x_1 = - \sin^{-1}{(\frac{1}{2} )} \\ x_1 = -30 \ensurement{^{\circ}} + 360 \ensurement{^{\circ}} = 330 \ensurement{^{\circ}}$$
$$x_2 = 180 \ensurement{^{\circ}} - (-30 \ensurement{^{\circ}} ) = 210 \ensurement{^{\circ}}$$
The cook needs 5x1/2=5/2= 2 and 1/2 cups of water because 10 persons are 5 couples.
Let me see.
Okay lets choose the people one at a time SO order does count.
The number of ways that the 23 people can all have different birthdays is 365C23 I think
The total number of ways 23 people can have birthdays = 365^23
The chance of finding 2 or more with the same birthday would be 1-(365C23)/(365^23)
$${\mathtt{1}}{\mathtt{\,-\,}}{\frac{{\left({\frac{{\mathtt{365}}{!}}{({\mathtt{365}}{\mathtt{\,-\,}}{\mathtt{23}}){!}}}\right)}}{{{\mathtt{365}}}^{{\mathtt{23}}}}} = {\mathtt{0.507\: \!297\: \!234\: \!323\: \!985\: \!4}}$$
which is slightly more than a 50% chance.
Now to my mathematician colleagues. I think that this is correct but can this be done using combinations instead of Permutations?
I canot think of a way
DragonSlayer your in 6th grade and look at that question and I'm in 8th , yet haven't seen anything like that in Geography!
$${{\left({{\mathtt{9}}}^{{\mathtt{9}}}\right)}}^{{\mathtt{9}}} = {\mathtt{196\,627\,050\,475\,552\,913\,618\,075\,908\,526\,912\,116\,283\,103\,450\,944\,214\,766\,927\,315\,415\,537\,966\,391\,196\,809}}$$
A good answer. Thanks Coolkille98
4-6i /1-i +-4+10i / -7+3i
Where do you want the brackets to go?
This is how it should be interpreted when there are no brackets.
$$\\4-(6i /1)-i +-4+(10i / -7)+3i\\\\ 4-6i-4+\frac{-10i}{7}+3i\\\\ -3i+\frac{-10i}{7}\\\\ \frac{-21i}{7}+\frac{-10i}{7}\\\\ \frac{-31i}{7}\\\\$$
No Cooltj
$$10^8$$ only has 8 zeros
this is a very good answer.
Thanks Cooltj
Find the cube root of 8*7*9*49*3
$$\sqrt[3]{8*7*9*49*3} = \sqrt[3]{2^33^37^3} = 2*3*7 = 42$$
3/4y-2/3x=12. Find the x and y intercept
$$\begin{array}{rcl} \dfrac{3}{4}y-\dfrac{2}{3}x &=& 12 \quad | \quad :12 \\ \\ \dfrac{1}{16}y-\dfrac{1}{18}x &=& 1 \\ \\ \dfrac{y}{16}+\dfrac{x}{-18} &=& 1 \end{array}$$
$$\small{ \text{ y-intercept is 16 and x-intercept is -18 } }$$
25 daL to kiloliters
$$25\ daL * \left( \dfrac{10^1} {1\ da} \right) * \left( \dfrac{1\ k} {10^3} \right) =25 * \left( \dfrac{10} {10^3} \right) kL = \dfrac{25} {100} kL =0.25\ kL$$
Is this correct?
TOTES MC GOATS
im kinda in a hurry
yes your correct and thank you too
Ok thank you very much.
so far it seems right let me finish looking
...............................ok XD
6th grade geography.
ok. Will do.
