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 #4
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+1
Jun 22, 2021
 #2
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Jun 22, 2021
 #17
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https://web2.0calc.com/questions/anser-this-question#r6        courtesy of Bginner      21/6/21

 

begin{eqnarray*}  \dfrac{x+1}{x-1}  &=& \frac{5}{4} \\  
\dfrac{(x+1)+(x-1)}{(x+1)-(x-1)}  &=& \dfrac{5+4}{5-4} \\ 
 \dfrac{2x}{2}  &=& \dfrac{9}{1} \\ 
 x &=& 9  \end{eqnarray*}

 

\(\begin{eqnarray*} \dfrac{x+1}{x-1} &=& \frac{5}{4} \\ \dfrac{(x+1)+(x-1)}{(x+1)-(x-1)} &=& \dfrac{5+4}{5-4} \\ \dfrac{2x}{2} &=& \dfrac{9}{1} \\ x &=& 9 \end{eqnarray*}\)

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Jun 22, 2021

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