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-x^2-x+1 = x^2 + x - 3

2x^2 + 2x-4 = 0

x^2 +x -4 = 0

(x-1)(x+2) = 0           x = 1 and -2                 1 - -2 = 3

The other x - intercept will be the same distance from the axis of symmetry, except on the OTHER side of the axis:

9,0

You need another equation relating x and y to have a simultaneous equation set with a unique answer....otherwise the graph below shows all of the answer to this ONE equation relating x and y :

https://www.desmos.com/calculator/nfnpwdxblq

You need to expand the brackets and then the number before xy is the coefficient. 
so it would be 

6x²+4xy+8x-9xy-6y²-12y+3x+2y+4

The xy would simplify to 

-5xy 

so the coefficient of xy is -5

hope this helps, sry the reply is so late

Rewrite the equations as:

y = -(A/B)x + 3/B and  y = -(1/3)x - 5/3

The values multiplying the x term constitute the slope.

Parallel lines have the same slope, so  A/B = 1/3  or  B = 3A

Since the first line passes through (-7, 2) we must have  2 = -(A/B)*(-7) + 3/B  or  2 = -(A/3A)*(-7) + 3/(3A)  or  2 = 7/3 + 1/A

Rearrange this last equation to find A, then find B (from B = 3A), then you can find B-A.

Perhaps this graph will help:

The ratio is 4 / 25

Guest’s answer is wrong. So it appears he didn’t learn it.

There are numerous examples of online poker-hand probability texts and examples. Google is a good starting point ...Bing is too.... so is Yahoo.... and Dogpile....

Solution for this question:

Choose the rank for the triple nCr(13,1)

Choose three suits for the triple nCr(4,3)

Choose a different rank for the pair nCr(12,1)

Choose two suits for the pair nCr(4,2)

Then

Divide this by the total number of five-card hands. nCr(52,5)

\(\hspace {7cm} \large \text{ } \dfrac{\dbinom {13}{1}\dbinom {4}{3}\dbinom {12}{1}\dbinom {4}{2}}{\dbinom {52}{5}} = \dfrac{6}{4165} \approx 0.144\% \)

GA

the initial height is given by  h(0)      so sub in t=0

and the time it hits the ground is when   h(t)=0    This is not hard either.

Math can be used to describe reality or construct useful fictions. For example, we know now that the spacetime we live in is non-Euclidian. ... The bottom line is that human beings have brains capable of counting to high numbers and manipulating them, so we use mathematics as a useful tool to describe the world around us.

13 goes 9 times into 125 with a remainder of 8.

\(125=13\times 9+8\)

  !

125 divided by 13  is 9 8/117.

As a decimal, this becomes a repeating decimal.

The orientation of the graph does not match the coordinates.

Assuming that the coordinates are correct --

Since  B = (8,-2)  and  C = (8,6)   --->   E = (8,2)

The equation of  ES:  y  =  2

Since  A = (2,-3)  and  B = (8,-2)   --->   C = (5,-2.5)

slope of AB  =  [-2 -(-3)] / [8 - (2)]  =  1/6

Since the slope of  AB  =  1/6   --->   the slope of DS  = -6

The equation of  DS:  y - (-2.5)  =  -6(x - 5)

                                     y + 2.5  =  -6x + 30

                                               y  =  -6x + 27.5

Since  y = 2   --->                   2  =  -6x + 27.5

                                              6x  =  25.5

                                                x  =  4.25

Therefore, the coordinates of S are  (4.25, 2)

The distance from S to E will be the circumference;

the distance from (4.25,2) to (8.2) is  3.75

1 1/4 + (-3 1/6)=

Hello  mathbms!

\(1\dfrac{1}{4}+(-3\dfrac{1}{6})=\dfrac{5}{4}-\dfrac{19}{6}=\dfrac{3\cdot 5-2\cdot 19}{12}=\color{blue}-\dfrac{23}{12}\)

  !

isn't it 9/10

i've got a question HUH?????

Ok fine, here are the steps for the reason how I got 35 beads in the box

Let x and y be the number of black and white beads, respectively in the box initially.number of black beads was 2/5 of number of white beads

                     =>      x=2/5y -----(i)

After 12 black and 44 white beads were 

taken out of the box then remaining.black beads are x - 12 and remaining white beads are y - 44 in the box

we are given now (x-12) = 2/3 of (y-44)

 =>        x-12 = 2/3 (y-44)

 =>        x=2/3y-88/3+12 ----(ii)

from (i)  and  (ii) => 2/5y = 2/3y + -88+36/3

=>(2/5-2/3)y=-52/3 =>\({2(3-5)\over 15}y{}{}\) = -52/3

   =>          -4/15y = -52/3 => y = 13 * 5 = 65

then x = 2/5y = 2/5 * 13 * 5 = 26 now In the box

black remaining are x-12 = 26 - 12 = 14

white remaining are y-44 = 65 - 44 = 21

So there are 14 + 21 = \([35]\) beads left in the box

Let total number of strawberries = x.

Since 3 friends divided strawberries equally therefore

each friends get x/3 strawberries.

   Because           x/3 + x/3 + x/3 = x.

Since, after they each ate 4 strawberries, the total number of strawberries left was equal to the amount each friend had at the beginning.

That is (x/3-4) + (x/3-4) (x/3-4) = x/3 (because at the beginning each friend has x/3 strawberries).

=>  3x/3 - 12 = x/3

=>  n - 12 = x/3     =>  3(n - 12) = x

=>  3n - 36 = n   =>  2n = 36   =>  n = 18

The total number of strawberries = 18

g cost    = g * 1.25

r = 2g     cost =   2g (2.75)          summed = 20.25

1.25 g    + 2.75 (2g)    = 20.25       solve for   g                ....  then r = 2g

Can a moderator help me out?

Multiply both sides by x

7 =   11/2   x       Multiply both sides by  2/11

2/11 * 7   = x      You can finish........

Of the  30  students,  2  do not take either subject; subtracting these 2 students leaves a total of 28 students.

Of these  17  take physics and  20  take math; adding these numbers together, we get 35.

Therefore,  35 - 28  =  7  students; these  7  students take both classes.

Here is a Venn:

Multiply both sides by the common denominator:  12k

(-11/k) · (12k)  =  (3/12) · (12k)

On the left-hand side, the k factor cancels; while on the right-hand side the 12 cancels:

(-11)(12)  =  3k

Then, finish.

(x-7)(x+7)      =   x^2 -49    =   x ^2 + 0x + (-49)