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AC = 24 + 70  

I don't know how to write in LaTeX in web2.0calc.com, so I'm going to try without it.

Set variables for the number of dimes and the number of quarters. The number of dimes can be d, and the number of quarters can be q. We already know there are TWICE the amount of dimes than quarters. So, we can say d=2q. since they have cost, we must multiply d or 2q by 10, and q by 25. My work is below:

20q+25q=630(in cents!!!!!) 45q=630(I used a calculator to do 630/45) q=14. 2q=28.

Check: 20(14)+25(14)=630(I used a calculator to do 25•14) 280+350=630. 630=630.

So, Jack has 28 dimes. :)

Kumar bought 5 posters and 11 cards with 1/3 of his money. The cost of each poster was 3 times the cost of each card. He bought some more posters with 3/4 of his remaining money.

(a) What was the greatest number of cards Kumar could buy with 1/3 of his money?

(b) How many posters did Kumar buy in all?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1 card = x          1 poster = 3x

5(3x) + 11x = 26x

a)    With 1/3 of his money, Kumar could've bought 26 cards.

b)    He bought 18 posters    

He will have  1 1/4  -  3/4  =  ....  gallons of yellow paint left.

He will have  1 1/5  -  3/4  =  ....  gallons of green paint left.

He will have  7/8  -  3/4  =  ....  gallons of blue paint left.

Find each difference and add those three answers together.

The four-person subcommitte could have:

2 boys and 2 girls:  ₁₀C₂ x ₁₀C₂

1 boy and 3 girls:  ₁₀C₁ x ₁₀C₃

Find each of the two products and add them togehter.

For two adjacent numbers to have a odd sum, one of the numbers must be odd and the other must be even.

So, the numbers must be arranged as:  O - E - O - E - O - E - O - E - O

There are 5 choices for the first odd number.

There are 4 choices for the first even number.

There are 4 choices for the second odd number.

There are 3 choices for the second even number.

There are 3 choices for the third odd number.

There are 2 choices for the third even number.

There are 2 choices for the fourth odd number.

There is 1 choice for the fourth (and last) even number.

There is 1 choice for the fifth (and last) odd number.

Multiplying these choices together: 5 x 4 x 4 x 3 x 3 x 2 x 2 x 1 x 1 choices.

What is 40% of 120% of x?

Hello Guest!

40% of 120% of x are

\(40\%\times 120\%\times x=\frac{40}{100}\times \frac{120}{100} \times x =\color{blue}\frac{´48}{100}\times x \) 

are 48% of x.

  !

[5 + 4 - 1] C [4 -1] ==8 C 3 ==56 ways - with no restrictions.

((10^2006 - 1) / 9) / 11==1.01010101 E+2004

So, the quotient is: 2006 - 1 ==2005 digits long.

Let x = number of brownies sold.

      y = number of cookies sold.

 : x/y = 3/5

 =>   5x - 3y = 0 -------- 1

Let $p be the price of each piece of cookies.

 Given that, each piece of bro is sold for $1

 more than each piece of cookie.

 : The price of each piece of brownie is $(8+1)

Eric collected $154 for all brownies and cookies sold.

  : (8+1)x + Py = 154 -------- 2

Also, Eric collected $44 more from the sale of brownies than the sale of cookies.

  :     (p+1)x = 44 + py

Substituting (p+1) x = 44+py in equation 2 we, get

              44 + py + py = 154

              =>   2py = 110

              =>   py = 55 ------ 3

 From equation 1, y = 5/3x.

  : Substituting value y = 5/3x in equation 3, we get

              P(5/3x) = 55 => px = \({55 * 3 \over 5} = 33{}{}\)

             => px * 33 -----4

 Substituting values of px = 33 of py = 55 in

 equation 2, we have

     (P+1)x + Py = 154

    => Px + x + Py = 154 

    => 33 + x + 55 = 154   =>  x = 154 - 33 - 55

                                         => x = 66

  Substituting  x = 66 in equation 1, we have

     5x - 3y = 0   =>  5(66)- 3y = 0 =>  3y = 330

                                                     => y = 110

    Substituting  x = 66 in equation 4, we have

         px = 33  =>  p (66) = 33 =>  P=0.5

: Each piece of cookie is sold at $0.5 and each piece of brownie is sold at $1.5

The number of cookie sold = y = 110.

The number of brownies sold is x = 66.

:  66 pieces of brownies were sold.

I did answer it ....Obviously you would take option 1

Find all integers n such that n^3 = (n - 1)^3 + 37.     

I found two by brute force, i.e., n = 4 and n = –3  

check n = 4 

n³ = (n – 1)³ + 37   

4³ = 3³ + 37  

64 = 27 + 37  

You can check n = –3 yourself, if you like.   

_.

7?????

Yes, can you solve it?

Is this question written correctly?    Obviously you would take option 1     option 2 has a smaller and smaller salary everyday.....option 1 has the same salary everyday.

3/8ths are women

x = total number

5/8 x   =   30 + 3/8 x

2/8 x = 30

x = 120 people at wedding                   3/8 * 120 = 45 women

    5/4 = 45/ g       g = girls

     45 * 4/5 = g = 36 girls                      45 women  - 36 girls  = 9   more women than girls at the wedding

Here is my attempt:

The minute hand is pointing at 2, which is 10 minutes after the hour.

The hour hand must point to a spot  after 2 + 5 =7 AM  {The Sun is rising in the East means that it is still AM}

At 7: 10 does not work because the angle between the hands ==155 degree. The angle must be < 90 (acute)

At 8:10 the angle ==~185 degress {No good!}

At 9:10 the angle==145 degrees {No good!}

At 10:10 the angle==115 degrees {No good!}

At 11:10 AM the angle==85 degrees, which is < 90. {This looks like plausible answer}!!

AC = 24.

[AEF] = 31/57.

If an arc of 45 degrees on circle A has the same length as an arc of 20 degrees on circle B, then what is the ratio of the area of circle A to the area of circle B? Express your answer as a common fraction.

Circle A:        r = 4       arc length = pi

Circle B:       20 / pi = 360 / x          x = 18pi          radius R = 9

A / B = (4²pi) / (9²pi)      = 16 / 81         

The length of one side of a triangle is 3 feet less than twice the length of its second side. The third side is 2/3 of the sum of the lengths of the first 2 sides. Find the length of all three sides if the perimeter is 6.5 feet.

x + (2x - 3) + 2/3(x + 2x - 3) = 6.5

x = 2.3

a = 2.3           b = 1.6            c = 2.6

The length of one side of a triangle is 3 feet less than twice the length of its second side. The third side is 2/3 of the sum of the lengths of the first 3 sides. Find the length of all  * two *  sides if the perimeter is 6.5

Sides a +b + c = 6.5

a = 2b-3

b

c = 2/3 (b + 2b-3)   

2b-3     +   b    +  2/3 (b   +   2b-3)     = 6.5       first solve for 'b'     then a = 2b-3         etc......

Not a very specific f/u question, Guest !    What is the prob?

Diagram?

First thing....graph the points

   then you should be able to find the perimeter easily: