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To buy 2 pairs of jeans from the first option it would cost 35$ + 35/2$ = 52.5$ 

The second option gives you a 20% discount from 38$, which 1 pair of jeans would now be 30.4$. To buy the second pair you multiply 30.4$ by 2, costing 60.8$, but then you have to subtract 10$ because the purchase over 50$ is a 10$ discount. So to buy 2 pairs of jeans from the second option would cost 50.8$

The second option is 1.7$ cheaper than the first option, so the second option is a better buy.

 da jeans r expensive $$$

Isosceles triangle ABC has AC = BC = 4.

Using the rules of tangents, AT is perpendicular to a leg of triangle ABC. AC = 4 and AT = 3, so using the pythagorean theorem we can get length of segment CT.

CT = \(\sqrt{4^2 - 3^2}\) = \(\sqrt{7}\)

Segment BT = BC - TC = \(4 - \sqrt{7}\)

Then we can use the pythagorean theorem to get AB.

AB = \(\sqrt{3^2 + (4 - \sqrt{7})^2}\) 

AB = \(2\sqrt{8 - 2\sqrt{7}}\)

pro maths 

We don't need to directly find the roots of the first equation.

We can multiply the first equation by 2 to get the second equation.

This yields: \(2x^2 + 16x + 8 = 0\) ,

so A + B = 24.

Step 1 is to make this a little more clear:

\(27a = 42x + 17\) 

Since the smallest value of x must be 0, then the base equation would be 27a = 17. 27 is 3^3, meaning that the sum of the digits of the number must be divisible by 3. But because 42 has a digit sum of 6 which is divisible by 3, but 17 has a digit sum of 8, then no matter how many values of x you try and input, or how many 42's you add to the 17, you will always get a number that has a digit sum that isn't divisible by 3. Therefore you can't get 'a' to be a whole number. 

But 'a' could be 17/27, and 27/59.

17/27 + 27/59 = 1732 / 1593.

First we can label some of the variables. 

a = 2 because it is the coefficient of \(x^2\).

\(2(x - h)^2 + k\)  and we can now foil \((x - h)^2\)

We foil it into \(x^2 + h^2 + 2xh\) and we have to multiply that by 2. We can see now that 4hx = 6x in the expression in the question getting: 

\(h = 1.5\)

This is valid because we are not given the value of variable k.

First we have to turn the equation to a standard quadratic equation: we get

\(x^2 + 10x + 7 = 0\)

Now we can apply the quadratic formula. x = \(-b {+\over} \sqrt{b^2 - 4ac}\over2a\) where a is the coefficient of x^2, b is the coefficient of x, and c is the constant.

Plugging in the values, we get x = \(-10 {+\over} 6\sqrt{2}\over2\) for our two solutions of x. 

Since the problem is asking for the smaller value, we take the subtraction operation in the equation above, getting:

x = \(-5 - 3\sqrt{2}\)

First label the dimensions of the rectangle, let the width of the rectangle be \(w\) and the length of the rectangle be \(l\).

Now to write some equations:

\(wl = 2017\)

\((w - 1)(l - 1) = 1917\) 

Now we will foil equation 2.

\(wl - w - l + 1 = 1917 \)

Substitution:

\(2017 - w - l + 1 = 1917 \)

Now we can get:

\(w + l = 101\)

Since we are looking for \((w + 1)(l + 1)\)because we want the dimensions increased by 1, we can factor that binomial to get:

\(wl + w + l + 1\) which is what we are looking for.

Now we can substitute:

2017 + 101 + 1 = 2119 = Answer

What is your solution to this problem? I'm curious.

First we must simplify this equation. 

We subtract (14x + 9) from both sides of the equation to get the quadratic \(ax^2 + 6x - 2\) = 0

Then we apply the quadratic formula \(-b {+\over} \sqrt{b^2 - 4ac}\over2a\) where a is the coefficient of x^2, b is the coefficient of x, and c is the constant.

Plugging it in, we get -3 + or - \(\sqrt{11}\), the nonzero constant (for which 'a' has one solution) will most likely be the positive solution. 

\(a = \sqrt{11} - 3\)

\(x = \)\({1\over2 + {1\over x + 2}}\)

This is what the equation looks like, now to simplify:

First you multiply the numerator and denominator by (x + 2):

It should look like: x = \({x + 2\over 2x + 4 + 1}\) 

Then you multiply both sides of the equation by \(2x + 5\) to get \(2x^2 + 5x = x + 2\).

Now you subtract (x + 2) from both sides to end up with quadratic: \(2x^2 + 4x - 2 = 0\)

Next you use the quadratic formula x = \(-b {+\over} \sqrt{b^2 - 4ac}\over2a\) where a is the coefficient of x^2, b is the coefficient of x, and c is the constant. Plugging it in, we find that x = \(2\sqrt{2} - 2\), or x = \(-2\sqrt{2} - 2\)

We know that the interior angle sum of quadrilateral ABCD = 360degrees.

Because we also know that angles A, B, C, D all form an arithmetic sequence, we can set a variable 'x' for the difference between the angles.

∠A = (72 - x)degrees

∠B = 72degrees

∠C = (72 + x)degrees

∠D = (72 + 2x)degrees

Angles A + B + C + D = 360degrees = 4(72) - x + x + 2x = 288 + 2x.

360 - 288 = 2x, x = 36degrees.

Since we are calculating for the degree measure of angle D, then m∠D = 72 + 2x = 144degrees.

The answer to your questions is 144 degrees.