93 - 5[14 - (2 + 4)]  working inside the parentheses we have

98 - 5 [ 14 - (6) ]     simplify inside the brackets

98 - 5 [8 ]               distribute the -5 across the 8

98 - 40

58

I assume you would like to graph this??

True, Melody........but not all zeroes do.....!!!

(The Troll can attest to this...)

Congrats, jillybean...We like having you on here with us....( Just call us party poopers....!!)

As is, there is nothing to solve.....it's like asking what 2^x "equals"....however, if you mean

$10,000.00 = $4,000(0.0225)^x      divide both sides by 4000

10000/4000 = .0225^x  simplify

2.5  = .0225^x       take the log of both sides

log 2.5 = log .0225^x   and we can write

log 2.5  = x log .0225      divide both sides by log .0225

log 2.5 / log .0225 = x = -0.2414951977666487

And that's it......!!!

The area of the base is just (1/2)(10)(20) = 100sq ft

So, the height (length) is just ...  2500cu ft / 100 sq ft = 25 ft

just enough.

There you go "All roads lead to Rome"    

It finishes in 5.   So it is divisable by 5.  So what do you think?

anon is right but it is called atan

Arc tan is the same as inverse tan.

You can also bring it up by leaving your finger on the tan button a little longer than normal   

$$\left({\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}\right){\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{12}}$$

$${\mathtt{150}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{\mathtt{62}} = {\mathtt{206}}$$

$${\mathtt{206}}{V} = {\mathtt{12}}$$

$${\mathtt{V}} = {\frac{{\mathtt{12}}}{{\mathtt{206}}}}$$ m.s-1

$${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{107}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1.1}}{\mathtt{\,\times\,}}{\mathtt{109}} = {\frac{{\mathtt{6\,549}}}{{\mathtt{10}}}} = {\mathtt{654.9}}$$

press the "2nd" button to make the inverse functions appear

I'm pretty sure it is.

What is the expression you need to evaluate???

Remember, for example,   $$\mathbf{\log_{10}(10^{-5.2})\ =\ -5.2}$$

It's the hyperbolic tangent.

(x-6)^2=7

x-6=±sqrt(7)

x=6±sqrt(7)

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x}}}}}{{solve}}{\left(\begin{array}{l}{\sqrt{{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}\right)}^{{\mathtt{2}}}}}={\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}={\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}={\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}={\mathtt{6}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\end{array}\right)}$$

9 + 10 = 19

2 - 2 = 4 :)

The minimum velocity occurs at aphelion. This value (3.7Km/s) is stated in the question.

D_perihelion = 7.735E9Km

D_aphelion = 4.425E9Km

Orbital eccentricity is the ratio of P/A (perihelion/aphelion) values. (Either distance or velocity values).

Orbital eccentricity (P/A)= (7.735E9) / (4.425E9) = 1.66

The product of eccentricity and V_aphelion gives V_ perihelion.

 (P/A)(Va)=Vp 

(1.66)(3.7Km/s) = 6.14Km/s

_7UP_

The size of the sun is 1.989E30 kg and the circumference of the moon is 6,784 miles (10,917 km)

There are 360 degrees in one revolution