All Answers 358180 Answers

I don't know what C scientific notation is, but just in ordinary scientific notation we have:

$$\\1300=1.3\times 10^{3}\\\\123.45=1.2345\times 10^{2}\\\\0.00426=4.26\times 10^{-3}$$

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1 L of water has a mass of 1 kg, so the potential energy of 50 L of water 10 metres above the bucket is:

50*1*9.8*10 Joules = 4900 Joules

This is turned into the same amount of kinetic energy as it hits the bucket.

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Yep, definitely a touch of CDD on my part here!

Moment and Torque are essentially the same thing except that Torque is a movement force, while Moment is a static force.  Torque tends to be used when there is an axle or pivot to be turned around, while Moment tends to be used in essentially non-rotational situations, such as analysis of forces on a beam.

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I wanted to give you thumbs up anon but it won't let me. 

There seems to be some problems with the system tonight.   

thanks anon, that was a good start. :)

I am going to use     log base 10     because      $$log_{10}10=1$$

$$\\3^ {2n-1} < 10^ {n-1 }\\\\
Log_{10}3^ {2n-1} (2n-1)Log_{10}3<(n-1)Log_{10} 10\\\\
Log_{10}3(2n-1)<(n-1)\\\\
2nLog_{10}3-Log_{10}3 2nLog_{10}3-n n(2Log_{10}3-1)

$${\mathtt{2}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{3}}\right){\mathtt{\,-\,}}{\mathtt{1}} = -{\mathtt{0.045\: \!757\: \!490\: \!560\: \!675\: \!1}}$$    

I am going to divide by this number and since it is negative I will have to turn the sign around.

$$\\n>\frac{log_{10}(3)-1}{2log_{10}(3)-1}$$

$${\frac{\left({log}_{10}\left({\mathtt{3}}\right){\mathtt{\,-\,}}{\mathtt{1}}\right)}{\left({\mathtt{2}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{3}}\right){\mathtt{\,-\,}}{\mathtt{1}}\right)}} = {\mathtt{11.427\: \!172\: \!663\: \!391\: \!417\: \!6}}$$

$$n\ge 12 \qquad where \;\;n\in N$$ 

You can convert it to a decimal (.5) and use that, or type (1/2) and use that. Keep in mind, you want to put parentheses in the right places.

25+4=c^2

29= c^2

c= rootsquare(29)

5.385164807134504

here is my helpm you incorporate the log on the left and right and continue like so

let's assume your prism is ABC x L

so the volume is the surface of the trianle ABC by the widthof the prism

106221/10000000000000000

or

106221/10¹⁶

@@ End of Day Wrap   Sat 28/2/15    Sydney, Australia     Time 1:00 am  (Really Sun morn)     ♪ ♫

Hi all,

Our industrious answerers today were; Bertie, Alan, tanehao, labby, shafqat, will85237, TheJonyMyster, Garmoon, BlackNinja and Nauseated.   Thanks everyone.

Interest posts:

Sun 1/3/15

$${\sqrt{{\mathtt{640}}}} = {\mathtt{25.298\: \!221\: \!281\: \!347\: \!034\: \!7}}$$    that is an approximation

or

$$\sqt{640}=8\sqrt{10}$$

you can do the other one.   

thanks anon,

of course you are correct. 

It is funny, I missed that.  

The reason I missed it is that my mind went back to to computer programming days.

when

x=x^24

would have meant REPLACE x with the old value of x raised to the power of 24.

that link doesn't work Nauseated

Is this a touch of CDD I see here Alan?  There seems to be an epidemic a presen.   (woops, no t)

My computer is refusing to type t's half the time.  I think that it has CDD too!     

Now Bertie it is your responsibility to find us a new riddle!     LOL

if x=x^n then x=1

so the answer is 1

I did this a moment ago.  Do not fill the board with repeat questions.  Thank you.

If you need to repost - here are the instructions.

Please follow them as it makes the forum better for everyone.

$$\\\frac{12^x}{48^{2x}}\\\\
=\frac{12^x}{(12*4)^{2x}}\\\\
=\frac{12^x}{12^{2x}*4^{2x}}\\\\
=\frac{1}{12^x*4^{2x}}\\\\
=\frac{1}{3^x*4^{x}*4^{2x}}\\\\
=\frac{1}{3^x*4^{3x}}\\\\
=\frac{1}{3^x*64^x}}\\\\
=\frac{1}{192^x}}\\\\$$

Maybe I have CDD           I have probably done this the long way and there might be errors.  

us a calculator dude

Mmm

Lets see.

$$\\\dfrac{4\times 2^{1/4}\times8^{1/6}}{16^{3/4}}\\\\\\
=\dfrac{2^2\times 2^{1/4}\times(2^3)^{1/6}}{(2^4)^{3/4}}\\\\\\
=\dfrac{2^2\times 2^{1/4}\times 2^{3/6}}{2^{12/4}}\\\\\\
=\dfrac{2^2\times 2^{0.25}\times 2^{0.5}}{2^{3}}\\\\
=2^{2+0.25+0.5-3}\\\\
=2^{-0.25}\\\\
=\frac{1}{2^{1/4}}\\\\
=\frac{1}{\sqrt[4]{2}}$$

$$\\\frac{12^x}{6^x\times8^x}\\\\
=\frac{6^x\times 2^x}{6^x\times2^x\times 4^x}\\\\
=\frac{1}{ 4^x}\\\\$$

example

$$\\6\frac{3}{8}-2\frac{2}{8}\\\\
=6+\frac{3}{8}-2-\frac{2}{8}\\\\
=6-2+\frac{3}{8}-\frac{2}{8}\\\\
=4+\frac{1}{8}\\\\
=4\frac{1}{8}$$

$${\frac{{\mathtt{533}}}{{\mathtt{611}}}} = {\frac{{\mathtt{41}}}{{\mathtt{47}}}} = {\mathtt{0.872\: \!340\: \!425\: \!531\: \!914\: \!9}}$$