All Answers 358087 Answers

hi guys.  

There are no number thingys BUT an explanation would go down very well :/

hi Jace,

 y=-2x-4

 y=-2*x-4

if x=0 then  y=-2*0-4=0-4=-4

if x=1 then  y=-2*1-4 = -2-4=-8

etc

Can you see how I am doing the substitution ?

Lol just checked under my the post. 

There's around 7 posts on just talking and not maths related dumb stuff.

Lol it's so ironic.

Not trying to be rude, but you just said on Melody's about talking about non related maths stuff.

If the exterior angle is 20 degrees then the interior angle must be 160 degrees

The sum of the interior angles of a polygon with n sides = (n-2)*180

Each individual internal angle in a regular polygon ((n-2)*180)/n

$$\\\frac{(n-2)*180}{ n}=160\\
(n-2)*180=160n\\
180n-360=160n\\
20n=360\\
n=18$$

18 sides

Hi Melody,

I really wanted to post something like this, but I didn't want act like I'm the boss around here...

Thanks for this post, I'm getting annoyed by this place turning like it with everyone saying hello every second...Or even if they're going offline?! What's the point.

People also take advantages of this, and like you said some bullying happens.

I have seen this a lot like Titanium, Jack Frost , Dbg4thebest... But I don't wanna name anymore....

Hey Brittany, thanks for answering but a little explanation would have been nice  :/

How do you know that Alan?  I mean without looking at the triangle.

[2nd][asin]

inverse sine is the same as arc sin

13/15 that is assuming that you do draw one item :)

That is not correct Mellie    

(-5,-6), m=-3

y=mx+b

y=-3x+b

sub in (-5,-6) ti find b

-6=-3*-5+b

-6=-15+b

9=b

y=-3x+9

Hi Mellie,

The question is a bit ambiguous so

I am going to assume that the train will arrive on the minute somtime between 1:01 and 1:59 inclusive

Well the train will be there for 10 minutes and alex could arrive anytime in 60 minutes so that would be 1/6

This logic has at least one obvious hole in it. The train could arrive arrive between 1:51 and 1:59 in which case it will not be at the station for a full 10 minutes during the hour.    

idk - needs more thought   

You do this with integration by parts 

f(x)=lnx                    g'(x)=3

f'(x)=1/x                   g(x)=3x

$$\\\boxed{\int\;f(x)g'(x)dx=f(x)g(x)-\int\;g(x)f'(x)dx}\\\\\\\\
\int\;((lnx)*3)dx\\\\
=(lnx)(3x)-\int\;(3x*\frac{1}{x})dx\\\\
=(3xlnx)-\int\;(3)dx\\\\
=(3xlnx)-3x+c\\\\
=3x(ln(x)-1)+c$$

Write this as

$$\\
1000\times x^4=x^{-\log_{10}x}\\\\
\text{Take logs of both sides and use properties of logs to get}\\\\
\log_{10}(1000)+\log_{10}(x^4)=\log_{10}(x^{-\log_{10}(x)})\\\\
3+4\log_{10}(x)=-(\log_{10}(x))^2\\\\
\text{Rearrange}\\\\
\log_{10}(x))^2+4\log_{10}(x)+3=0\\\\
\text{This is a quadratic in log(x) and factors nicely}\\\\
(log_{10}(x)+1)(log_{10}(x)+3)=0\\\\
\text{so the two solutions for x are}\\\\
log_{10}(x)=-1\quad x=10^{-1}=0.1\\
log_{10}(x)=-3\quad x = 10^{-3}=0.001$$

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You need to solve the following two equations

nCr(n,k)/nCr(n,k+1) = 3/4

nCr(n,k+1)/nCr(n,k+2) = 4/5

Unfortunately, the calculator on the home page here doesn't seem to be able to solve these simultaneously.  

The result I got using different software was n = 62 (and k = 26).

The calculator here will calculate nCr(62,26)/nCr(62,27)   and  nCr(62,27)/nCr(62,28) though.

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Now its very clear I understood this 

Thank you all. 

We must have (5*2-k*2)/(5+k) = 0.5   i.e.  (nbr green b***s*$2 + nbr purple b***s(-$2))/(total nbr b***s) = $0.5

10 - 2k = (5+k)/2

20 - 4k = 5 + k

15 = 5k

k = 3

Three purple b***s

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Yes, R is not proportional to L, which measures the length of the cylinder, because the current flows radially.

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Area = half base times height or $$\frac{b}{2}h$$

Just 2 (equal to 91 that is).

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This question only makes sense if the first row of Pascal's triangle is taken to be   1  1  (the first row is often given as just the number 1 on its own).  Given this then the sum of numbers in row n is 2ⁿ and there are n+1 numbers so the arithmetic mean is 2ⁿ/(n+1).  This equals 2048 when n = 15.

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315, try comprehending my last post.   

We all agree but we have to work with the forum that we have been given :)

Sorry guys - this is out of my hands :)

Yes there are approx 2.2 pounds in a kilogram

K=2.2P

there is your formula :)