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You need to calculate the value that, when multiplied by 2/3, will result in 4.

4 ÷ 2/3  = 4 x 3/2 = 12/2 = 6

So:  (x^2/3)⁶ = x⁴

Since y = x^2/3  --->   y⁶  =  (x^2/3)⁶  =  x⁴   

I believe that you also need to know the standard deviation of the population (at least the standard deviation of the sample) in order to do the calculation:

Formula:  E  =  z_{α/2 · σ / √n}

where:  z represents the z-score when α = .90, σ represents the standard deviation, and n represents the number in the sample.

I am not sure what the calculator thinks X08 is.   It has basically just ignored it.

Hi anon, thanks for getting involved :)

2*3=3*2

and

c*27=27*c

It makes no difference what side the c is on   :)

You are right   c*27 cannot equal c*5  UNLESS c=0.  

If c=0 then you get 0=0 which is true :)

It could be that you have got it wrong

because if c on the left is equal to the c on the right (they are both c), then you are pretty much asking if 5 is equal to 27 (not correct of course)

what is a five digit number contains the digits 1,4,5,6 and 7 but not in that order. arrange these digits so that the resulting number divisible by 4. In how many ways can this be done?

A number is divisable by 4 if the last 2 digits are divisable by 4.

I think the only 2 digit numbers that can be made that are divisable by 4 are 16, 56, 64 and 76  (4 possibilities)

If the last 2 digits are 16 then there are 3! ways ways that the others can be ordered.  That is 6 ways.

The same applies for each of the other final pairs .

So I believe that there are   4*6 = 24 possibilities.

Thanks anon, you are right.  You have answered the question that was asked correctly :)    

However I suspect that the asker had a differen question in mind.  

Anon, If this is not the question that you wanted answered then please try to clarify your question.  

The ONLY answer is c=0

log10 is equal to 1                           (because 10 to the power of 1 equals 10)

so 10*log10 is equal to 10*1=10

the result in the brackets is 4            (you can do this using calculator)

So, the final result is 40                    (10*log10*(10*92/10-10*88/10) = 10*4 = 40)

$$\\\frac{1/3}{8}=\frac{x}{2}\\\\
\frac{2/3}{8}=x\\\\
x=\frac{2/3}{8}\\\\$$

$${\frac{\left({\frac{{\mathtt{2}}}{{\mathtt{3}}}}\right)}{{\mathtt{8}}}} = {\frac{{\mathtt{1}}}{{\mathtt{12}}}} = {\mathtt{0.083\: \!333\: \!333\: \!333\: \!333\: \!3}}$$    

1/12 of a cup

Your question does not make sense.  Perhaps you mean something like this?

$$\\\displaystyle\lim_{ X\rightarrow 0} \frac{1-cos4X+Xsin3X}{X*X}\\\\$$

What is the smallest number that can be divided by 5, 7 and 11, leaving a remainder of 4 in each case?

$$x= 4+z\cdot 385 \qquad z \in Z$$

Here's my 2 cents worth :

(8/2) * (6 + 3)  =

(4)  * ( 9)   =

36

nice job pulling that operation off, rubenhh

also,

Welcome to the Official Forums for web2.0calc.com, Rubenhh!!!

hmmmm,thx to the sneek peek torturey of 8th grade math and after scouting many 8th grade challenger bases, ive finally discovered the rule

Q:What's the rule for raising a number to a negative exponent?

A: It's the same rule for raising a number to a positive exponent, except, instead of whole numbers, you deal with fractions with negative exponents, and the numerators always 1 and the denomenator is always the positive exponent

for example

9^-1

9^1=9

but since its a fraction, its 1/9

lets say 3^-3

it is the same as 3*3*3=27, except becuz its fractions, its 1/27

If something is raised to a neg power you simply swap it to the other side of the fraction line and change the neg sign to a pos sign.

Just be careful - only the terms with the neg power can be swapped to the other side :))

See if this helps.

$$\\\dfrac{(2-2i)^6(\sqrt{3}+1)^3}{(\sqrt{3}+i)^4}\\\\\\
\dfrac{(2-2i)^6(\sqrt{3}+1)^3(\sqrt{3}-i)^4}{(\sqrt{3}+i)^4(\sqrt{3}-i)^4}\\\\\\
\dfrac{2^6(1-i)^6(\sqrt{3}+1)^3(\sqrt{3}-i)^4}{\{(\sqrt{3}+i)(\sqrt{3}-i)\}^4}\\\\\\
\dfrac{2^6(1-i)^6(\sqrt{3}+1)^3(\sqrt{3}-i)^4}{(3--1)^4}\\\\\\
\dfrac{2^6(1-i)^6(\sqrt{3}+1)^3(\sqrt{3}-i)^4}{(4)^4}\\\\\\
\dfrac{2^6(1-i)^6(\sqrt{3}+1)^3(\sqrt{3}-i)^4}{(2)^8}\\\\\\$$

$$\\\dfrac{(1-i)^6(\sqrt{3}+1)^3(\sqrt{3}-i)^4}{4}\\\\\\$$

The rest is just painful expansion.  Maybe you do not need to go any further.

(1-i)^6 will work out the easiest.  Use binomial expansions. 

If you need help expanding I suggest you ask for it.   :) 

I am glad that you are back TR  

your class average on a test was a 70 with a standard deviation of 3 points.What percent of the class fell between 67 and 76 points 

I am going to split this into 2 parts.  Below the mean and above the mean.

70-3=67           so 67 is one standard deviation below the mean

between -1 and +1 SD  from the mean lie 64% of all scores.  Half of this is 34%

70+2*3=76      and 76 is 2 standard deviations above the mean.

between -2 and +2 SD  from the mean lie 95% of all scores.  Half of this is 47.5%

Total prob of lying in desired region = 34+47.5 = 81.5%    approximately.

I do not understand your question :/

36 from 2,3,6,8?

36=3*12

so

36=3*(8+6-2)

there is another answer :)

Welcome back TR  :))

Thanks for that correct answer :))

$$\\3\div 2\frac{ 5}{8}\\\\
=3\div \frac{2*8+ 5}{8}\\\\
=3\div \frac{21}{8}\\\\
=3\times \frac{8}{21}\\\\
=1\times \frac{8}{7}\\\\
=\frac{8}{7}\\\\
=1\frac{1}{7}\\\\$$

Perhaps you should get 2 jobs.

One in a crematorium and one in a abbortoir.

Then both your nasal callings could be satisfied. :/

its good to be back

3 / 2 5/8

first, lets put these fractions improper3*8/8=24/8

2*8=16+5=21/8

now its: $${\frac{{\frac{{\frac{{\mathtt{24}}}{{\mathtt{8}}}}}{{\mathtt{21}}}}}{{\mathtt{8}}}}$$

now, lets do the recipicult to the numerator and denomenator of the second fraction, in this case, 21/8

now we converted this division situation to a multiplication situation

$${\frac{{\frac{{\mathtt{24}}}{{\mathtt{8}}}}{\mathtt{\,\times\,}}{\mathtt{8}}}{{\mathtt{21}}}}$$

cross cancel both 8s on both fractions cuz they cross

which leads to this after cross canceling:

$${\frac{{\frac{{\mathtt{24}}}{{\mathtt{1}}}}{\mathtt{\,\times\,}}{\mathtt{1}}}{{\mathtt{21}}}}$$

now multiply, which should equal:

$${\frac{{\mathtt{24}}}{{\mathtt{21}}}}$$=1 3/21=1 1/7

overall, 3 divided by 2 5/8=1 1/7

-7*1 = -7

A negative multiplied by a positive will stay negative.