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The only way to find out is to post a specific question!

Here's the first one answered for you.  Let's see if you can use this to help you answer the others.

Two hundred and nine thousand one hundred divided by two hundred and four!

Good try Guest, but the question specifies that the perimeters are the same, not the areas!

Perimeter of square:  4x

Perimeter of rectangle: 2*(2x-4) + 2*(x-6) = 4x - 8 + 2x - 12 = 6x - 20

So 4x = 6x - 20

2x = 20

x = 10 cm

Perimeter of square = 4*10 = 40 cm

Perimeter of rectangle = 6*10 - 20 = 60 - 20 = 40 cm

Just type it into the calculator exactly as you have written it:  1/3

Assuming equal monthly payments with no interest:

16000 / (5 x 12) = 16000/60 = 266.67/month

1,2,3,6,9,18

2.99792584 x 10^8  m/s

8m

8m / (2.99792584 x 10^8 m/s) = 2.66851276 x 10^8 s

1.2 / 2, we multiply both sides by 10 and we get 12/20, divide both sides by 2 and you get 6/10, again we divide by 2 and we get: 3/5, which is your final answer.

Since  v=ir     120 = .0958 (ohms)       Ohms = 120/.0958 = 1252.6 ohms

1/3=.333333333333333333333333.........and so on.

What is the interest rate charged by the car dealer?

-25/4 + 4/4=-21/4=-5 1/4

Let the width of the rectangle be x,

So the height of the rectangle=2x, then we have:

x * 2x=18 sq.inches

2x^2=18

x^2=18/2=9

x=Sqrt(9)=3 inches, being the width of the rectangle.

2 X 3=6 inches, being the length of the rectangle, so that:

3 X 6=18 square inches being the area of the rectangle.

(2 X 6) / 4=12/4=3

i need help soving this linear equation please. Can ypu also include the steps of the solution. Thanks.

159b + 3.3c = 1000mg

2.3b + 0.6c = 18mg

\(\small{ \begin{array}{lrcl} (1) & 159\cdot b + 3.3\cdot c &=& 1000 \\ (2) & 2.3\cdot b + 0.6\cdot c &=& 18 \\ \\ \hline \\ (2) & 2.3\cdot b + 0.6\cdot c &=& 18 \qquad | \qquad -2.3\cdot b\\ & 0.6\cdot c &=& 18 - 2.3\cdot b \qquad | \qquad : 0.6\\ & c &=& \frac{ 18 - 2.3\cdot b } { 0.6 } \\ & c &=& 30 - \frac{ 2.3 } { 0.6 }\cdot b \\ \\ \hline \\ c \text{ into } (1) & 159\cdot b + 3.3\cdot c &=& 1000 \\ & 159\cdot b + 3.3\cdot ( 30 - \frac{ 2.3 } { 0.6 }\cdot b ) &=& 1000 \\ & 159\cdot b + 3.3\cdot 30 - 3.3 \cdot \frac{ 2.3 } { 0.6 }\cdot b &=& 1000 \\ & 159\cdot b - 3.3 \cdot \frac{ 2.3 } { 0.6 }\cdot b + 3.3\cdot 30 &=& 1000\qquad | \qquad - 3.3\cdot 30\\ & 159\cdot b - 3.3 \cdot \frac{ 2.3 } { 0.6 }\cdot b &=& 1000 - 3.3\cdot 30\\ & 159\cdot b - 12.65\cdot b &=& 1000 - 99\\ & 159\cdot b - 12.65\cdot b &=& 901\\ & b\cdot (159 - 12.65) &=& 901\\ & b\cdot 146.35 &=& 901\\ & b &=& \frac{901} {146.35}\\ & \mathbf{b} & {=} & \mathbf{6.15647420567} \\ \\ \hline \\ & c &=& 30 - \frac{ 2.3 } { 0.6 }\cdot b \\ & c &=& 30 - \frac{ 2.3 } { 0.6 }\cdot\frac{901} {146.35} \\ & c &=& 30 - 23.5998177884 \\ & \mathbf{c} & {=} & \mathbf{6.40018221159} \\ \\ \hline \\ (1) & 159\cdot b + 3.3\cdot c &=& 1000 \\ & 159\cdot 6.15647420567 + 3.3 \cdot 6.40018221159 &=& 1000 \qquad \text{okay!} \\\\ (2) & 2.3\cdot b + 0.6\cdot c &=& 18 \\ & 2.3 \cdot 6.15647420567 + 0.6 \cdot 6.40018221159 &=& 18 \qquad \text{okay!} \end{array} }\)

a square and rectangle have the same perimeter. the length of the rectangle is 4 cm less than twice the side of the square, and the width of the rectangle is 6 cm less than the side of the square. find the perimeter of each figure.

 Let x be the side of the square,

 then length of the rectangle is: 2x - 4,

The width of the rectangle is: x - 6,

So, we have: (2x - 4) X (x -6)=x^2,

x = 2 (4+sqrt(10))=14.32455 cm, being the side of the square.

14.32455 X 2 -4=24.6491cm, being the length of the rectangle

14.32455 - 6=8.32455cm, being the width of the rectangle, so we have.

24.6481 X 8.32455=14.32455^2

205.19=205.19cm^2, so that the areas of the square and the rectangle are EQUAL.

Ah, thanks for that. I didn't understand that that was all I had to do. Lol!

What is the value of "theta"?

His milage is: distance travelled/number of gallons that his tank holds. So if he used up n gallons, then

we have: m/n= miles per gallons that his truck does. The $84 cost doesn't help us because we don't know how many gallons can his tank hold. If we knew, then we just divide $84/number of gallons. That would give us the cost of gas per gallons, and therfore would kmow how poor milage was his truck doing.

(2.99792458 x 10^8), it takes light 1/(2.99792456 X 10^8) of a second to cover 1 meter.

Therefore it takes (2.99792458 X 10^8)/8=1/37,474,057.25 of one second to travel the distance of 8 meters. Or, written in scientific notation=2.6685 X 10^-8 seconds

I assume that you want to show that the base of the triangle [ or top of the trapezoid] is parallel to the bottom side of the trapezoid.

Since the base angle of the triangle and the trapezoid are congruent, these are corresponding angles cut by a transversal formed by the side of the trapezoid and the side of the triangle. And lines cut by a transversal such that  their corresponding angles are equal are themselves parallel.

dorry i changed it its. [3X(6+6)-]2 

Using the info given, this question is unsolvable. You can't ask someone to solve for x if x isn't part of the equation.