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find a real and imaginary parts of the complex number? 7-(-6)^(1/2)

7-i sqrt(6)

How do i enter the x^2 -2 -8y=0 solve for x

x = ±sqrt(8y+2)

x^2 + 6y = -17   →    y = -[17 + x^2] / [6]   (1)

y^2 + 4z = 1  →  [1 - y^2] /[4] = z    (2)

z^2 + 2x = 2   →  x = [2 - z^2] /  [2]     (3)

Put (1) into (2)

z = [1 - (-[17 + x^2] / [6])^2 ] / 4  simplify

z = [1 - [(289 +34x^2 + x^4)]/36] / 4

z = [36 - 289 -34x^2 -x^4]/36]/4

z = [-253 - 34x^2 -x^4]/ 144

z =   -[(x^4 + 34x^2 +253)/144]     sub this into (3)

[-[(x^4 + 34x^2 +253)/144]]^2 + 2x = 2 .....  this would be diificult to solve by hand....using a Computer Algebra System, we have that x = -1    ...so x^2 = 1

And y = -[17 +(-1)^2'/[-6]   =  -(18)/6  = -3      ...so y^2  = 9

And z = [1 - (-3)^2]/ 4 = (-8)/ 4  = -2    so z^2  = 4

So

x^2 + y^2 + z^2 =   1 + 9 + 4 = 14

I don't understand what the problem is? Just take the tan as usual except you will get a negative value, e.g., tan(-30)=-.57735.

Example 1/4=.25 X 100=25%

1/(x^2-x)-1/(x-1)=(x+6)/x

Derivative is:d/dx(1/(x^2-x)-1/(x-1) = (x+6)/x) = (1/(x-1)^2-(2 x-1)/(x^2-x)^2 = 1/x-(x+6)/x^2)

This means that

a^2 - 3 = 46   add 3 to both sides

a^2  = 49       take pos/neg roots of both sides

a = (pos/neg)(7)

Say you want to calculate your odds of winning the first prize in a lottery. The lottery has 50 numbers to choose from and you buy a ticket which allows you to pick 6 numbers of your choice. To use the "nCr" key, your enter 50 first then press that key, then enter 6 and close the bracket. Finally you press the = key and that should give you the answer. You should get: 15,890,700. Good luck. 

If there are 536 870 912 grains and each grain weight 1/7000 pound, multiply these two numbers together to get the total weight:  536 870 912  x  1/7000  =  the answer

The formula for _nC_r is:  n! / [ (n - r)! r! ]

I don't have a procedure for solving this, I just guessed, had to modify it once, and came up with:

x = -1     y = -3    z = -2

From these values, you can determine the value of x² + y² + z².

(2sqrt(6), sqrt(5)) and (-sqrt(6), sqrt(5)) 

D = sqrt [ (2sqrt(6) - -sqrt(6))^2  + (sqrt(5) - sqrt(5))^2 ] =

sqrt[(3sqrt(6))^2  + 0^2]  =

sqrt[3sqrt(6)]^2  =

3sqrt(6) = about 7.35 [rounded to hundredths]

7x - 3x  = 4x....so....

4x  =  24    divide both sides by 4

x = 6

We can  only do this when we have a right triangle and the given side is a leg and the given angle is not the right angle. The remaining angle = 90 - the given angle.

Then, we can use the Law of Sines to find the other leg since we know two angles and one side.

Once we find the other leg, we can use the Pythagorean Theorem the find the hypotenuse = sqrt(leg₁^2 + leg₂^2)

Are you copying this from some sought of book, or pasting it from a website........becoz a normal person can't really write so much...................by any chance , I mean like any how , like a mystery your mother didn't tell you , are you the father of Godzilla?and want to take some sought of revenge from me? Tbh I'm a simple person so please mister angry , spare me , I'm a cute innocent little girl you know.....

DC would be the hypotenuse of a right triangle.......and its length  is  given by :

sqrt(8^2 + 6^2) =  sqrt(100) = 10 cm =  DM + MC  = length of glue strip

I can't see where your C and D points are, but it sounds like the glue strip halves the envelope into two halfs, hence we have:

6^2 + 8^2=H^2

H^2=100

H=Sqrt(100)

H=10 cm -being the length of the glue strip.

each glue strip is 5"

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Hallo guest

so you will want to subtract 25 from both sides of the equation to get

-3x+11

then divide both sides of the equation by -3 to get

x=(-3/11)

hope this helped!

(-5)^-1 = 1/(-5)   = -1 / 5

(A+B)(A-B)=A²-B²

a²-25

whats twenty percent of 520

20% means 20/100=.20, so that we have,

.20 X 520=104 which is your answer.

Use this conversion:

rads  x   180  / pi    = degrees

For example :     convert pi/4 to degrees,,,,,,,

pi/4  x 180 / pi    =  180/4 =  45 degrees

It works for "non-pi" rads, too.......example convert 2 rads to degrees

2 X 180 / pi  ≈  114.59 degrees