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Let us set the original deposit to be x, then we have:

(1.08^2)x - 2(.08x) + x =160

1.1664x - .16x + x =160

1.1664x - 1.16x =160

.0064x=160

x=160/.0064

x=25,000. Being the original deposit.

The sum of the first two five terms of a geometric series is 3798

Which is it???...two, five  [or maybe twenty five  ???]

Ending digit patterns for  all five digits raised to any positive powers:

Power 1   2   3  4 

1 =      1   1   1  1 

2 =      2   4   8  6 

3 =      3   9   7  1 

4 =      4   6   4  6  

5 =      5   5   5  5 

And these patterns repeat  for every group of 4 powers, i.e., [5 - 8], [9 - 12], etc.

Notice that the ending digit sum for the odd powers end in 5

So the ending  digit sums for all odd powers end in 5......and all such numbers are multiples of 5

Thank you for you answer, then

If the average balance is 417.74, 

If the annual rate is 15.6%, what is the interest on the card for the billing period ? 

It would be : I : P*R*T so It would be 

417.74 * 0.156 * t = 12 ? 

Best, 

Thank you for your answer, I am still confused about it :(

thanks for the help, i didnt see that aha :).

CPhill: Minor correction. Your first value of x=7/2 not 2/7

The domain  is [0, 17].......0 representing an empty tank and 17 representing a full tank

The range is [0, 544]    .....0 representing the miles traveled on an empty tank.......and 544 the distance traveled om a full tank

The average balance will be:

(456 (8 days) + (456+112) (12 days) + (456 + 112 -342) (11 days))  / 31 days       (August has 31 days)

417.74

Notice that we can write this as the sum of 50 subtractions, thusly:

[100 - 99] + [98 - 97] + [96 - 95]  +.......+ [4 - 3] + [2 -1]  =

1 + 1 + 1 + .......+ 1  + 1       and we will have summed 1 fifty times....so.......

50(1)  = 50

Ooops...I mean stat from the RIGHT   ....I am NOT dyslexic, but I am left handed

I would start from the left ...each set of two numbers equals 1     2-1   4-3   etc    there are 50 sets of these numbers , so 50 is the answer

lim((g(x)*sin(2x)+e^(2*x)-1)/x),x->0,lim g(x)=5,x->0

So we have

lim[(5*sin(2x) + e^(2x) - 1) /x] , x ⇒ 0      using L'Hospital's Rule we have

lim [(10cos(2x)  + 2e^(2x)] / 1. x⇒ 0   =

10*cos(0) + 2e^(0)   =  10 + 2 =  12

I think that you need to clarify the question.

The phrase 'that f has got a root at (\(\alpha,\beta\))' implies that f is a function of two variables, while the equation suggests that it is a function of a single variable.

x(2x-7)-4x+14=0   simplify

2x^2 - 7x - 4x + 14 = 0

2x^2 - 11x + 14 = 0   factor

(2x  - 7  )    (x - 2)  = 0     and setting each factor equal to 0, we have

x = 2/7    and x = 2

5x1 000 000?

5 X 1,000,000=5,000,000.

Find x: x(2x-7)-4x+14=0

x=2 and x=7/2

Thanks Alan for correcting me. I know now.

75% of £400

75% means: 75/100=.75, then just multiply as follows:

.75 X 400=300 Pounds.

tan2x = sin2x /cos2x =  [2sinxcosx]/[cos^2x - sin^2x]  = [2(.6)(.8)] / [ (.8)^2 -(.6)^2]  = 2[.48]/[.28] = .96/.28 = .48/.14 = .24/.7 = 24/7

Use:  22500/x = 358

Rearrange to get x = 22500/358 ≈   62.85 kg

(-6)^(1/2) = (-1)^(1/2)*6^(1/2) = i*6^(1/2)

So the real part of 7 - (-6)^(1/2) is just 7 and the imaginary part is -6^(1/2)

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Put the argument in brackets and then raise to the power  tan(x)^(-2)  

That's if you want 1/tan(x)^2.

You can type the following into the calculator here:

and get the following response

The problem statement is:

 How compressed is a spring with a constant of 500 N/m if a force of 40 N is applied to it?

The answer below it seems to have invented numbers that don't relate to those in the question!!

To answer the question use Hooke's law:  Force = spring constant*extension, so

extension = 40/500 = 0.08m

This is marked as incorrect in the answer box because there is another piece of information that specifies the answer is to be given to the nearest tenth, so extension ≈ 0.1

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When you say "How do i enter the x^2 -2 -8y=0 solve for x". Do you mean how to enter it in the onsite calculator here? If that's so, I don't think this calculator can solve symbolic algebra. I maybe wrong, but it's unlikely.