All Answers 358501 Answers

4.79 × 10-3=0.00479

351/460 as a simplified fraction

Cannot be simplified any further.

(-11/5)-5/2=-47/10, But if

-1 1/5 - 5/2=-37/10

=  (1/2x + 5) ( 1/2x + 5)  =  1/4 x^2 + 5x + 25       IF  1/2x   means  1/2 (x)

= (1/(2x) + 5 ) (1/(2x) +5) = 1/(4x^2)  + 10/(2x) + 25  =  1/(4x^2)  + 5/x +25      IF  1/(2x)  is what you meant

21 is the most best answer

I think it is 5296734275

The number 42 is, in The Hitchhiker's Guide to the Galaxy by Douglas Adams, "The Answer to the Ultimate Question of Life, the Universe, and Everything", calculated by an enormous supercomputer over a period of 7.5 million years. Unfortunately, no one knows what the question is.

or    101010  in Binary

I Think its 4

If you assume that the word "two" is a typo, and have the problem that the sum of the first five terms is 3798 while the sum to infinity is 4374:

The formula for the sum of the first five terms of a geometric series is:  Sum = a(r⁵ - 1) / (r - 1).

The formula for the sum of an infinite geometric series is:  InfSum  = a/(1 - r)  with |r| < 1.

We have:  a(r⁵ - 1) / (r - 1)  =  3798     and     a/(1 - r)  =  4374

Since  a/(1 - r)  =  4374  --->   a/(r - 1)  =  -4374

Since  a(r⁵ - 1) / (r - 1)  =  3798   --->   [1/(r - 1)] x (r⁵ - 1)  =  3798   --->   -4374 x (r⁵ - 1)  =  3798

   --->   r⁵ - 1  =  -3798/4374   --->   r⁵  =  1 - 3798/4374   --->   r⁵  =  576/4374  =  32/243   --->   r  =  2/3

Knowing that r = 2/3:     a/(1 - r)  =  4374   --->   a/(1 - 2/3)  =  4374   --->   a/(1/3)  =  4374   --->   a  =  1458

To find the sum of the first seven terms:  Sum = a(r⁷ - 1) / (r - 1)   =  1458( (2/3)⁷ - 1 ) / ( 2/3 - 1 )  =  4188

-4^2  +  -2^2  =   16  + 4  = 20

The interest is only for ONE MONTH, not an entire year, so:  (1/12 of a year)

(417.74 x .156)/12

5.43

I have not yet learned L'Hospitals rule.Is there another method for this?

6a -4 + 26

6a = 30

a= 5

-3/4   x  -3   =   9/4  =  2 1/4

-3/ (4 x -3)  =   -3/-12 = 1/4

That's the question exactly as it is written.The only thing i forgot to mention is that the thing to prove is slightly different.Prove that f (which is constant) has a root at (α,β).And the equation I have posted has no real roots.If it's still unclear,just tell me whichever you think is the right solution.I really need this answer.Thanks.

what is negative 3 over 4 times negative 3?

You mean: -3/(4*-3)=1/4

 what is (1/2x+5)^2

=(x/2+5)^2

Domain [0, 16]

Range [98*(0), 98*(16)  ]   =  [0, 1568 ]

45/3.141592653=14.323945......

Hallo guest!

x^2 - 5x + 9= 0   from the quadratic formula, we have that the solutions are....

x = [5 + i*sqrt(11)] 2  and  [5 - i*sqrt(11)]/ 2   so

[ (5 + i*sqrt(11))/2  - 1] * [ (5 + i*sqrt(11))/2  - 1]  =

[ 3 + i*sqrt(11)] /2 *  [ 3 - i*sqrt(11)]/2 =

[ 9 - i^2 *(11)]/4  =

[9 - (-1)(11)]/ 4 =

20 / 4=

5

If a and b are the solutions to the equation x^2 - 5x + 9= 0, what is the value of (a - 1)(b - 1)?

(1/2 (5-i sqrt(11))-1)* (1/2 (5+i sqrt(11))-1)=5

Find one pair of real numbers, (x,y), such that x + y = 6 and x^3 + y^3 = 144.

x=5.2361....  and y=.7639.....

x + y = 6 and x^3 + y^3 = 144

Notice that   y = 6 - x   and subtituting this into the second equation, we have

x^3  + [6 - x]^3 = 144  simpify

x^3  -x^3+18 x^2-108 x+216  = 144

18x^2 - 108x + 216 = 144  subtract 144 from each side

18x^2 - 108x +72  = 0    divide through by 18

x^2 - 6x + 4 = 0    and using the Quadratic Formula, the solutions for this are...x =3 +sqrt(5) and x = 3 - sqrt(5)

So..if we choose that x = 3 + sqrt(5), then y =  6  - [3 + sqrt(5)] = 3 - sqrt(5) 

Setting each linear term to 0, we have

3x + 5 = 0       so, x = -5/3

and

2x - 9 = 0    so, x = 9/2

And  9/2  + (-5/3)   =   27/6 + (-10/6)  = 17/6