All Answers 358483 Answers

((9.109e-31)*(1.602e-19)^4)/(72*(8.854e-12)^2*(6.626e-34)^2) 

where is the zero?

You are dividing by e to high negative powers, these are tiny numbers and, with rounding, the calc sees them as zero.

If you want to simplify you may need to do some of it by hand.

\(\frac{(9.109e^{-31})*(1.602e^{-19})^4}{72*(8.854e^{-12})^2*(6.626e^{-34})^2}\\ =\frac{9.109e^{-31}*1.602^4e^{-76}}{72*8.854^2e^{-24}*6.626^2e^{-68}}\\ =\frac{9.109*1.602^4e^{24}e^{68}}{72*8.854^2*6.626^2*e^{31}e^{76}}\\ =\frac{9.109*1.602^4}{72*8.854^2*6.626^2*e^{15}}\\ etc\)

An example

please

first line you set a=b

thus (a-b)=0

4th line you divide by (a-b), i.e. you divide by 0.  This is undefined.

You don't have to do any of that.  They've given you the equation

s(t) = 9000 - 600t

So as in the other problem we have t as the horizontal axis, and in this case s(t) is the vertical axis.

For the vertical intercept set t=0, and evaluate s(0)

For the horizontal intercept set s(t)=0 and solve for t.

It is quite easy.

Just relax. Because it is a weekend, there aren't many prople online to help you. Don't sound desperate!!. Do the best that you can and your teacher will show you where your mistake is. That's how you learn, by making mistakes and learning from them. Good luck.

Here is my answer

Hallo

Hi, Thanks for you answer, 

However I did not find -15 but onlny 15 for the slope of 100-15x 

How did you find the b : A(t) = 150000 - 300t ?? 

Best, 

Thalys 

(a). y = 100 - 15x    slope: -15

(b). A(t) = 150000 - 300t  slope:-300

The same probability as OBTAINING two tails!!!!!!!!!!!!!!!!!!!!.

YOU AIRHEAD!!. BECAUSE WE RECORD YOU IP ADDRESS, YOU COULD HAVE COPS KNOCKING ON YOUR PARENTS' DOOR AT 2:00AM!!. SMARTEN UP.

Please don't spam... For your own good.

Simplify the following:
(6 c d^2)^2/(24 c^5 d^4)

Multiply each exponent in 6 c d^2 by 2:
6^2 c^2 d^(2×2)/(24 c^5 d^4)

2×2  =  4:
(6^2 c^2 d^4)/(24 c^5 d^4)

(6^2 c^2 d^4)/(24 c^5 d^4) = d^4/d^4×(6^2 c^2)/(24 c^5) = (6^2 c^2)/(24 c^5):
(6^2 c^2)/(24 c^5)

Combine powers. (6^2 c^2)/(24 c^5) = (6^2 c^(2-5))/24:
(6^2 c^2-5)/24

2-5 = -3:
(6^2 c^-3)/24

6^2 = 36:
36/(24 c^3)

The gcd of 36 and 24 is 12, so 36/(c^3×24) = (12×3)/((12×2) c^3) = 12/12×3/(2 c^3) = 3/(2 c^3):
Answer: | 
| 3/(2c^3)

Did you try to use the calculator here? First do 1/3. Enter 1, then the  ÷ key, then 3 and finally press the = sign. You should get .3333333333333333.........., then press the X key, then enter 24 followed by = sign again. And that should give you the final answer. Answer?=10 - 2!!!!

I everyone i wonder if you could correct me ? 

in this linear modeling devil work ! 

A(t) = 150000 - 300t 

I did : A(0) = 150000 - 300*0 = 150000

So the vertical interecpt is ( 0,150000) 

Then A(t) = 0      

0 = 150000 - 300t 

Solve for t : 0 = 150000 - 300t ( add t to the both side ) 

300 t = 150000 ( both side isolated by the t ) 

t = 150000 / 300 : 500 

So the horizontal interect is ( 500,0 ) 

 Right ? 

Thank you, 

Best, 

Thalys 

I everyone i wonder if you could correct me ? I correct it myself 

in this linear modeling devil work ! 

A(t) = 150000 - 300t 

I did : A(0) = 150000 - 300*0 = 150000

So the vertical interecpt is ( 0,150000) 

Then A(t) = 0      

0 = 150000 - 300t 

Solve for t : 0 = 150000 - 300t ( add t to the both side ) 

300 t = 150000 ( both side isolated by the t ) 

t = 150000 / 300 : 500 

So the horizontal interect is ( 500,0 ) 

 Right ? 

Thank you, 

Best, 

Thalys 

Hi, 

I tried to work on Probleme B as asked by Rom :p 

Here is what I found if someone could correct me ?? 

Vertical Interectp : 150000 - 300* 0 = -150000 so Vertical Intercept = ( 0, -150000) 

Horiztonal Interectp : ( 147000, 0 ) 

Help, I feel like Eveyrthing's wrong :( 

I can graph anything here 

x=23/36 - (13s)/12, substituting the value of s obtained by "guest #2", we get:

x=.6389 - (-41/3)/12

x=.6389 - (-.3611)

x=1

Hi Rom, 

Thank you so much for your answer, and with your help I think I almost get it, 

The thing I have to do, is plug 0 instead of x and solve it 

then plug 0 again instead of y 

Then solve it and it will give me the point of the x and y axes than I have to plug in ? 

I try to do (a) again first, alone to see if I get the same result as you did ! 

And then work on (b) thanks so much, enjoy your day ! 

You find your GPA (in the US anyway) by setting

A=4

B=3

C=2

D=1

E or sometimes F = 0

Then take the average of your grades.

So in this case we have 2 A's, a B, and 3 C's.  6 total grades, so we sum them up and divide by 6 for the average.

4 + 4 + 3 + 2 + 2 + 2 = 17

and

17/6 = 2.83333 ...

GPAs are generally rounded to 2 digits to the right of the decimal point so your GPA is 2.83

First off you have to understand that the axes are labeled whatever they happened to be labeled so you have to be careful using terms like x-intercept and y-intercept.  In problem (b) the horizontal axis happens to be the t-axis and the vertical axis is the A axis.

Next we understand that the intercept of a given axis is then the value of the variable on the other axis is 0.

In problem (a) we find the horizontal intercept when the variable on the vertical axis, y, is 0.  We find the vertical intercept when the variable on the horizontal axis, x, is 0.

In (a) y=3x + 24

The vertical intercept is easy, just let x=0 and evaluate y.  Here we get

y=3*0 + 24 = 24

The horizontal intercept isn't quite as easy.  Here we have to set y=0 and solve for x.

0 = 3x+24

-3x = 24

x = -8

So we see the vertical intercept is at (0,24), and the horizontal intercept is at (-8, 0)

I'm going to let you work problem (b), just remember

vertical intercept: variable on horizontal axis, here t, equals 0.

horizontal intercept: variable on vertical axis, here A, equals 0.

If you have internet why dont you look it up? not trying to be rude

=3(4s+1)-1=6(7-5s-10)/4

=4(12s+3-1)=1(42-30s-60)

=48s+12-4=42-30s-60

=48s+30s=42-60-12+4

=78s=-26

=\(\frac{78s}{78}\)=\(\frac{-26}{78}\)

s=\(\frac{-1}{3}\)