All Answers 358348 Answers

Very nice, sportzkid28....!!!

5 pts. from me.......

Just try the calculator here and see what you get.

Let the amount Dale has = D

Jane has $6 less =  D - 6

Chau has 4 times more = 4D

So we have

D + [ D - 6] + 4D = 126     simplify the left side

6D - 6 = 126     add 6 to both sides

6D = 132   divide both sides by 6

D = $22  ....this is what Dale has

Jane has $22 - $6  = $16

And Chau has 4* ($22)   = $88

The 2 negatives cross out themselves so then toy are just adding. Your answer is 10.

V  = sqrt ( 2 * 9.8 * 10.5)  =  sqrt (205.8)  = about 14.3 m/s   [rounded to the nearest tenth ]

In 2008, the total trade between the United States and Japan was $2.04 x 1011. The total trade between the U.S. and Australia was $3.28 x 1010. How many times greater was the trade with Japan than the trade with Australia?

  ($2.04 x 1011) / ( $3.28 x 1010)= 6 9/41 - is the trade with Japan greater than with Australia.

[2.04 x 10¹¹] / [ 3.28 x 10 ¹⁰ ]  =

[2.04 / 3.28  ] * [ 10 ¹¹ / 10 ¹⁰ ] =

about  0.622 * 10  = 

about 6.22  times  [ rounded]

what is 1/9 times z minus 5 equals 7/18

1/9z - 5=7/18

1/9z=7/18  +5

1/9z=5 7/18

1/9z=97/18 multiply both sides by 9

z=873/18=48 1/2

\(\dfrac 1 9 z - 5 = \dfrac {7}{18} \\ \dfrac 1 9 z = \dfrac 7{18}+5 = \dfrac{7}{18}+\dfrac{90}{18} =\dfrac{97}{18}\\ z = 9\times \dfrac{97}{18} = \dfrac{97}{2}\\ z=\dfrac{97}{2}\)

Ok I'll take a stab at this.

VT ratio of 700 means that you are reading 1/700 of the actual voltage.

CT ratio of 200 means you are reading 1/200 of the actual current

V = (700)117 = 81900V

A = 200(2.5) = 500A

VA=81900 x 500 VA = 40950 kVA

\(kWatts = PF \times kVA = 0.89 \times 40950 ~kVA = 36445.5~ kWatts\\ kVAR = \sqrt{1-PF^2} \times kVA = 0.46 40950 ~kVA = 18671.6~ kVAR\)

You will learn in school how to solve simultaneous equations in due course.

Go to this link and you will what a matrix is:https://www.mathsisfun.com/algebra/matrix-multiplying.html

whats a negative number ?

A negative number is any number with - sign in front of it: such as -3, -123, -1/2, -.25...........etc.

8[-n+(-p)]=8(-n-p)=-8n-8p

(-5)^3=-125

can some one please tell me what 6 9/16 simplified

=105/16

5x plus 10y devise by 69

(5x + 10y) / 69=5(x +2y) / 9

What is $80 subtract 4/5

$80 - (4/5 X$80)=$16

Without more information, all I can tell you is it is equal to:

2x + 10,000

I'm assuming you are asking for the VOLUME of a cylinder

r = radius   h = HEIGHT

pi r^2 = the AREA of the cross section of the cylinder

When the AREA is multiplied by the HEIGHT it results in the VOLUME of the cylinder

pi r^2 h    = VOLUME of a cylinder

Simplify the following:
2/5-6/7

Put 2/5-6/7 over the common denominator 35. 2/5-6/7  =  (7×2)/35+(5 (-6))/35:
(7×2)/35+(5 (-6))/35

7×2  =  14:
14/35+(5 (-6))/35

5 (-6)  =  -30:
14/35+-30/35

14/35-(30)/35  =  (14-30)/35:
(14-30)/35

14-30  =  -(30-14):
-(30-14)/35

| 2 | 10
| 3 | 0
- | 1 | 4
| 1 | 6:
Answer: | 
| (-16)/35

T(h) = 15 + 0.01h

The vertical intercept is the temperature of the earth at its surface = 15 C

The horizontal intercept doesn't make much sense in this problem....this is where the temp = 0.....however, given that positve h values represent the distance below ground, in this case, the temp is 0 C at 1500 m above the surface of the earth......

See the graph, here........https://www.desmos.com/calculator/jvef1xalkw

                   x^2  - 6x

x + 2       [   x^3 − 4x^2 − 12x + 9  ] 

                  x^2  + 2x^2

                 ------------------------------------

                          - 6x^2  - 12x

                          -6x^2   - 12x

                         -----------------------

                                                  9

So...the result is   x^2 - 6x  Remainder  9 / [ x + 2 ]

You are exactly correct on your calculations of the exponents....good job!!!

You can evaluate the results you obtained with our on-site calculator......

4. Here's the graph  of 2^(x + 1).......https://www.desmos.com/calculator/qfcyl7dnde

It's just the graph of 2^x shifted to the left by one unit.....