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8695 is my answer

The Newton method is quite the complicated method if you don't have an advance knowledge of Maths. However, given that you have asked, I will try my best to teach you the Newton Method.

Now then let is get started. The Newton's Method uses a very repetitive method of approaching a root:

$${\sqrt{}}$$

The root that you wish to solve or locate will depend what your initial number will be. In this example I will use the most commonly used pronumeral to replace a number. The equation you are looking for is indicated below: 

$$x_n_+_1=(x_n)-f(x_n)/f'(x_n)$$

Looks complicated right?

I'll try to walk you through.

In the equation $$x_n$$ is the value of the $$x$$ value. $$f(x_n)$$ is the same $$x_n$$.

I am very bad at wording... Please excuse me.. I never exceled at Engrish.

$$f'(x_n)$$ is the slope or as known as the derivative, at

$$x_n. x_n_+_1$$

represents the next x-value that you are trying to find.

$$f'(x_n)$$ the derivative represents $$f(x)/dx (dx = delta-x)$$. Therefore, the term $$f(x)/f'(x)$$ represents a value of dx.

Right now.. I am diving into the unknown now... Hopefully, I still know what I am doing >_<

$$\frac{f(x)}{f'(x)}=\frac{f(x)}{f(x)/dx}=dx$$

...and that is all I remember from this method. Anyone could help me out? :P

27.50 dollars

Well, if d = $4.75 then she will have $(56 - 6*4.75) left

$${\mathtt{56}}{\mathtt{\,-\,}}{\mathtt{6}}{\mathtt{\,\times\,}}{\mathtt{4.75}} = {\frac{{\mathtt{55}}}{{\mathtt{2}}}} = {\mathtt{27.5}}$$

She has $27.5 dollars left.

First draw a graph to see the likely value.

Looks like it might be x = -2.

Try x=2

 -2+6 = 4

0.5^-2 = 1/2^-2 = 2² = 4

So x = 2.

If you prefer a numerical approach rewrite the equation as 2^x = 1/(x+6)

Take log₂ of both sides

x = log2(1/(x+6))  ...(1)

Make an initial guess for x, say x = -1.  Plug this into the right-hand side of equation (1) to get a new estimate for x. Plug this new value into the right-hand side of equation (1) to get yet another estimate, and so on.  Repeat until you converge on a unique value.  In this case the process will converge on the number -2 in 9 or 10 iterations. 

no unit was given and the answer came from partial fraction.

There still are.  Click on the word Scientific at the right of the input line to see them.

Your equation represents a line, and where a line intercepts the y axis (if it does), x =0.

So, letting x =0 in your equation, we have

4y = 12   

So...... y = 3

And there's the point of intersection with the y axis.......(0,3)

We can set this up as a proportion problem.

1.8/15 = x/20       So taking the cross- product, we have

20 * 1.8 = 15 * x    Divide by 15 on each side

20 * 1.8 / 15 =  2.4 hours

So

(2.4 - 1.8) = .6 hrs. = (.6 * 60minutes) =  36 minutes

its 1000 cuz is is 650 x20

becuase its 1-(1)=2 it does not make sence

4 gallons x $29 each = $116

Is the 12 being raised to the power of "x" or the power of (x-2) ??

Thank you Alan!

Just put this into the on-site calculator.......it'll give you your answer...

yeah totally thanks 

If 5/7 are boys, than 2/7 must be girls.

Let x be the total number of students.

Then 2/7 of x = 300     or, in math terms

(2/7)x = 300        Multiply both sides by the reciprocal of (2/7) ⇒ (7/2)

x = 300(7/2) = 1050 = total students

Then.... the total students - the number of girls = the number of boys

So 1050 - 300 = 750      And that's the number of boys.

Note something else......if 2 parts of the 7 are girls = 300, then there must be 150 students in each "part"  

Then, since the boys are 5 "parts", then 5(150) = 750 !!!

Does that make sense??

thankx for the anwer and good explanation !

thanks alan

can a hacker do this or is it just a random user??

Start by multiplying out the brackets on both sides of the equation:

0.3(6 + p) = 0.4(8 - p) 

0.3*6 +0.3*p = 0.4*8 -0.4*p

1.8 + 0.3*p = 3.2 - 0.4*p

Add 0.4*p to both sides and subtract 1.8 from both sides

0.3*p + 0.4*p = 3.2 - 1.8

Collect similar terms

0.7*p = 1.4

Divide both sides by 0.7

p = 1.4/0.7

p = 2

Start by letting the speed of the slower train be s km/hr. The speed of the other train is therefore s + 5 km/hr

Their relative speed (that is the speed of one as seen by the other) is the sum of these two; namely: 2s + 5 km/hr.

After two hours they will have travelled closer to each other by a distance (2s + 5)*2 km (because distance = speed*time).  Since they started 340km apart and are now only 30km apart, the combined distance they have travelled is 340 - 30 = 310 km.  So, we must have:

(2s + 5)*2 = 310

2s + 5 = 155

2s = 150

s = 75 km/hr

And the faster train's speed is 75+ 5 = 80 km/hr

(Edited to correct silly mistake!)

Ok.........the total distance traveled by both trains is 340km - 30 km = 310km

Let the speed of the slower train be x

So the speed of the faster train is x + 5

So the rate of the first train (x) times the time it has traveled (2 hrs) = some distance

And the rate of the second train (x+5) times the time it has traveled (2 hrs) = some distance

And the distances combined is 310km

So

x(2) + (x+5)(2) = 310

2x + 2x + 10 = 310       Subtract 10 from both sides

4x = 300       Divide by 4

x = 75km/hr     And that's the rate of the slower train

And the faster train is traveling 5km/hr faster = 80km/hr

No it is not Zegroes,

His thumb is worth 5 points - these a 1 point downs.  Someone is not being nice!