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There is nothing to solve becasue there is no equal sign

you can simplify it though :/

1/2(b) - b/1

\(1/2(b) - b/1\\ =\frac{1}{2}b-\frac{b}{1}\\ =\frac{b}{2}-\frac{2b}{2}\\ =-\frac{b}{2}\)

Solve(a^2+b^2)=c^2,c^2=3^2

So we have that

a^2 + b^2  = 3^2

a^2 + b^2   =  9

The solution is all the points (a,b)  that lie on a circle with a radius of 3

The area of the square is 81 square units.

81 un²  =  (side length)²

  9 un   =   side length

The two points divide the side length into 3 congruent parts.

So, each piece will be  9/3  =  3  units long.  Now we know...

radius of each quarter circle  =  3 un             and...

        length of straight piece  =  3 un

On the shape's perimeter...there are  4  quarter circles, and there are 4  straight pieces.  So...

perimeter  =  4[ circumference of quarter circle ]  +  4[ length of straight piece ]

                 =  4[ (2π * radius)/4 ]  +  4[ length of straight piece ]

                 =  [ 2π * radius ] + 4[ length of straight piece ]

                 =  [ 2π * 3 ] + 4[ 3 ]

                 =  6π + 12

                 ≈  30.8 un

{14,4*0,89*(1*0,8988882*(4733)/(2,60)+1*(4733/2/2,60+(27069/14)-1))}=internal server error! (please try again later)

f(x)  =  5x - 12

                                   Let's say...

y  =  5x - 12

                                   Now solve this equation for  x  .

y + 12  =  5x

(y + 12) / 5  =  x

                                   To get the inverse function, swap  x  and  y  . Instead of  " y "  I put   " f^-1(x) "

f^-1(x)  =  (x + 12) / 5

And we want to find what  x  value makes...

f^-1(x)  =  f(x + 1)

                                                       That is...

(x + 12) / 5  =  5(x + 1) - 12

                                                       Multiply both sides by  5  .

x + 12  =  25(x + 1) - 60

x + 12  =  25x + 25 - 60

                                                       Subtract  25x  from both sides and subtract  12  from both sides.

x - 25x  =  -12 + 25 - 60

-24x  =  -47

x  =  47/24

\(13.4=\frac{x}{52}\)

                               Solve this equation for  x  by multiplying both sides by  52  .

13.4 * 52  =  x

696.8  =  x

                              So...

\(13.4=\frac{696.8}{52}\)

Non-sequitur

/ˈnɒn ˈsɛkwɪtə/

noun1.

a statement having little or no relevance to what preceded it.

12^360 = 3.2007265854670794258595942798697 x 10^388

9/13 = .692 ≈ .7  (rounded)

Both triangles are under the same height...so their areas will be to each other as their bases

And since angle BAC is bisected,   bases BD and CD will have the same relationship as their adjacent sides....i.e., 16/24....so  the areas of triangles ABD and ACD  wii have the same ratio......that is :

area ABD /area of ACD  =  16 / 24  =  2 / 3

Here's a pic :

GingerAle's LaTex in a box

\begin{array}{|lll|} \hline &(h-16t^2) - (h-16(t+1.6)^2) &=& 182ft&\\

&-16t^2+16 (t+1.6)^2&=&182\\ &51.2t+40.96&=&182\\

&51.2t&=&141.04\\

&t&=&2.7546875\\ \text { }\\

&16(2.7546875)^2 &=& 121.4 \text{ft above observation floor. }\\

&\dfrac{121.4}{13}& =& 9.3 \text{ Floors above observation floor. }\\

&14+9 &=& 23 \text { The bucket fell from the }23^{rd} \text {floor }\\

\hline \end{array}

\(\begin{array}{|lll|} \hline &(h-16t^2) - (h-16(t+1.6)^2) &=& 182ft&\\ &-16t^2+16 (t+1.6)^2&=&182\\ &51.2t+40.96&=&182\\ &51.2t&=&141.04\\ &t&=&2.7546875\\ \text { }\\ &16(2.7546875)^2 &=& 121.4 \text{ft above observation floor. }\\ &\dfrac{121.4}{13}& =& 9.3 \text{ Floors above observation floor. }\\ &14+9 &=& 23 \text { The bucket fell from the }23^{rd} \text {floor }\\ \hline \end{array}\)

5.020202020202 = 5+0.020202020202

let

x=0.020202020202

100x=2.0202020202

subtract

100x-x = 2.0202020202 - 0.020202020202

99x  =  2

x= 2/99

\(5.020202020202=5\frac{2}{99}\)

\(\int x^x dx\)

I suspect this is a deliberately awkward question!  None of the integrals listed have results in terms of standard mathematical functions ( except possibly for the ln(x) one; but even there the result is in terms of the imaginary error function, hardly a common function!).  There are solutions in terms of series - see WolframAlpha.

Please post one question at a time and try using words like 'please help me understand', 

rather than 'give me the answers'.  A little politeness can get you a long way in life.

It's a quadratic in t.  

Rewrite it as  1/2at² +v₀t+x₀-x=0   

Multiply by 2/a:    t² +(2v₀/a)t +2(x₀-x)/a = 0

Use the quadratic formula:

t = { -(2v₀/a) + sqrt[ (2v₀/a)² - 4*2(x₀-x)/a) ] }/2    → { -v₀ + sqrt[ v₀² - 2a(x0-x) ] }/a

(Because t is almost certainly time here, we don't need to look at the other solution)

"Hi Can you show steps in solving this problem:

solve(1/x+1/y=3/4, x^2/y+y^2/x=9)"

As follows:

.

If (1.33)sin(25) = (1.5)sin(theta), what is theta?

1.33 x 0.42261826..... = 1.5sin(theta)

0.5620823.... = 1.5sin(theta)   divide both sides by 1.5

Sin(theta) =0.5620823 / 1.5

Sin(theta) = 0.37472152541.....

Theta = Sin^-1(0.37472152541)

Theta = 22 Degrees.

If we just look at the shape of the water, we see also a rectangular prism....

The cross sectional area of this prism is also  42 cm²  .

And...

volume of prism  =  (area of cross section) * (height)

                                                                                          Plug in the information from the problem.

1680 cm³  =  (42 cm²) * (height)

                                                                                          Divide both sides by  42 cm²  .

40 cm  =  height

I assume you mean \(\frac{8}{3}-\sqrt{6}\)

\(\frac{8}{3}-\sqrt{6}\)

\(\frac{8}{3}-\frac{3\sqrt{6}}{3}\)

Exact answer:

\(\frac{8-3\times\sqrt{6}}{3}\)

Approximate answer:

\(\frac{8-3\times\sqrt{6}}{3}\)

\(\frac{8-3\times2.4494897427831781}{3}\)

\(\frac{8-7.3484692283495343}{3}\)

\(\frac{0.6515307716504657}{3}\)

\(0.2171769238834885667\)

To find out how many hours Kylie needs to work to earn $357, you need to first find out how much she earns in one hour. Since she made $68 for 4 hours of work, to find out how much she earns in one hour, take $68 and divide that amount by 4 and when you do that you get $17 for one hour of work.  To find the number of hours she needs to work to earn $357, take $357 and divide it by how much she earns in one hour which is $17 and when you do that you get 21 hours.  It will take 21 hours for Kylie to earn $357.

4h - $68

1h - $17

357 dived 17 = 21 hours

The unknown starting height of the bucket’s fall is (h). The bucket falls (16t^2) feet in (t) seconds.  The man observes the bucket passing floor 14 at unknown time (t), and it continues to fall for (13ft*14) = 182ft in 1.6s

\(\begin{array}{|lll|} \hline &(h-16t^2) - (h-16(t+1.6)^2) &=& 182ft&\\ &-16t^2+16 (t+1.6)^2&=&182\\ &51.2t+40.96&=&182\\ &51.2t&=&141.04\\ &t&=&2.7546875\\ \text { }\\ &16(2.7546875)^2 &=& 121.4 \text{ft above observation floor. }\\ &\dfrac{121.4}{13}& =& 9.3 \text{ Floors above observation floor. }\\ &14+9 &=& 23 \text { The bucket fell from the }23^{rd} \text {floor }\\ \hline \end{array} \)

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Lancelot Link says the best place to watch an opera is from the rafters or a chandelier, but you need a good pair of opera glasses to read their lips. It helps to know Italian, too.

I do not understand how you got to \(sin(\Theta)=1.33sin(\Theta)/(-0.1135188)\); however, this is how I would sove this equation.

\(1.33\times sin(25) = 1.5\times sin(\Theta)\)

\(1.33\times -0.132351750098 ≈ 1.5\times sin(\Theta)\)

\(-0.17602782763034 ≈ 1.5\times sin(\Theta)\)

\(\frac{-0.17602782763034}{1.5} ≈ \frac{1.5\times sin(\Theta)}{1.5}\)

\(\frac{-0.17602782763034}{1.5} ≈ \frac{1\times sin(\Theta)}{1}\)

\(\frac{-0.17602782763034}{1.5} ≈ 1\times sin(\Theta)\)

\(\frac{-0.17602782763034}{1.5} ≈ sin(\Theta)\)

\(-0.1173518850868933 ≈ sin(\Theta)\)

\({sin}^{-1}(-0.1173518850868933) ≈ {sin}^{-1}[sin(\Theta)]\)

\(-0.11762291934 ≈\Theta\)

\(\Theta≈-0.11762291934\)