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(log^4(x))/(log(2) log(3) log(4) log(5)) = (log(120) log^3(x))/(log^2(2) log(5) log(9)), solve for x

x = 1   and   x = 120

y=x^2+12x+5

Use -b/2a and x= -12/2(1)=-6.

Thus, y=(-6)^2+12(-6)+5=-31, and that is the minimum value for y.

.44 * .12 = .0528      5.28%      5% rounded

a = adult tix              value =    $3 a

c = child tix =  350-a      value = $ 2 (350-a)      summed = $ 950

3a     +       2(350-a)      =    950       solve for 'a' , the number of adult tix, then  350 - a = child tix

Maximum will occur at    t =      -b/2a        a = -25    b = 75 

-b/2a   =  75/50 =   1  1/2 sec

Let's suppose the number of adult tickets sold are x, and the number of child tickets sold is y. 

If 350 tickets were sold, we can say that for our first equation, x + y = 350. 

Since $950 was collected, we can say that our second equation will be 3x + 2y = 950.

Here are our two equations: x + y = 350

                                             and

                                             3x + 2y = 950.

Since x + y = 350, we know that x = 350 - y.

Plugging this into the second equation, we will get 3 ( 350 - y ) + 2y = 950.

Expanding, we get 1050 - 3y + 2y = 950.

We can then combine the ys together, to get 1050 - y = 950. 

Subracting 1050 from each side, we'll get -y = -100.

Finally, flip the negative signs into positive signs, and we'll get y = 100, which means that the number of child tickets sold is 100.

All you have to do now is plug the number of child tickets into the first equation, solve, and then you will get the number of adult tickets sold. 

I hope this helps, good luck. 

\(\text{Note that the maximum of } -x^2 \text{is at x=0. Thus, the maximum if 0+5=5.}\)

Simplify

 \(3log_9(18)+log_3(\sqrt{\frac{8}{27}})-log_{\frac{1}{27}}(81)-log_{\sqrt{3}}(2\sqrt{2}) \)

Hello SpongeBobRules24!

\(3log_9(18)+log_3(\sqrt{\frac{8}{27}})-log_{\frac{1}{27}}(81)-log_{\sqrt{3}}(2\sqrt{2}) \)

\(=3\cdot a+b-c-d=6.04158747083\)

\(9^a=18\)                           \(a=2.631\)

\(3^b=\sqrt{\frac{2^3}{3^3}}=(\frac{2}{3})^{\frac{3}{2}}\)        \(b=-0.5536\)

\((\frac{1}{27})^c=81\)                      \(c=-\frac{4}{3}\)

\((\sqrt{3})^d=3\sqrt{2}\)                 \(d=2.6309\)

\(3log_9(18)+log_3(\sqrt{\frac{8}{27}})-log_{\frac{1}{27}}(81)-log_{\sqrt{3}}(2\sqrt{2}) = 6.04158747083\)

  !

The chance that Howie chooses a Kit Kat is \(\frac{4}{8} = \frac{1}{2}\)The chance Ellen chooses a Hershey is \(\frac{1}{7}\)Multiplying the two probabilities, we get \(\frac{1}{14}\)

If there is a 56% chance of being a boy, then there is a 44% chance of being a girl. Out of those girls, 12% of them hav a chance to be premature. So 44% times 12%=5.28%. That rounded to the nearest whole number is

6 %

3 + 2/3 cheese < 2 cheese

3 < 4/3 cheese

cheese> 9/4      the smallest whole number would be  3 cheese      then     5  cherry    total 8

8.

5 cherry danishes and 3 cheese danishes.

See this very similar question and answer:  https://web2.0calc.com/questions/please-help_84974

Assuming ONE year investment

x = 8% amount

12 000 - x = 6% amount

.08 (x)  + .06(12000-x) = 872        solve for 'x' the 8% amount     then 6% amount = 12000-x

Cool! 

Thanks! I'll try that

It worked, thanks!

Cool! What do you play (if you don't mind me asking)?

Angle B

It is given as 30 degrees

Angle C

By law of sines:

\(\frac{sin(30^\circ)}{50\sqrt{3}}=\frac{sin(C^\circ)}{150}\)

asin(150*(sin(30)/(50*sqrt(3))) = 60

Solving, we get angle C = 60 degrees.

Angle A

Since all angles in a triangle add to 180, angle A is 180 - 30 - 60 = 90.

BC

To solve for BC, try all of these methods (you may have different results depending on the method)

 - Pythagorean theorem

 - 30 - 60 - 90 triangle

 - Law of sines

 - Law of cosines

The answer is all the different values of BC added up.

plz help Question 3

y = mx + b     you are givem m, slope = -3

y = -3x + b     subst in the given point

-2 = -3(5) + b    so b = 13

y = -3 x + 13

Bevan =152.4 cm
Jim =152.4 + 0.75 =153.15 cm
L = logan
L+5.08 =1.2 * 152.4, solve for L
L =889 / 5 =177.8 cm

[F + D*7] + [F + D*11] =246,  [F + D*9] + [F + D*13] =298, solve for F, D
F = 6 - This is the first term
D = 13 - This is the common difference.
35th term =[6 + 13*(35 - 1)]
                 =[6 + (13*34)]
                 =[6 + 442]
                 =448 - This is the value of the 35th term.