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No prob....easy to make mistakes on here......!!!!

Outer diameter  =

10  + 2 (8)  + 2(6)  =

10 + 16 + 12  =

38 ft

2x^2  - 10x +  13  = 0

2(x^2 - 5x + 25/4)  + 13  - 50/4  =  0

2 ( x - 5/2)^2    +  2/4  =  0

2 ( x - 5/2)^2    =  -  1/2     divide  both sides  by 2

(x - 5/2)^2  = -1/4                take  both roots

x - 5/2 =   ±1/2 i

x = 5/2 ±1/2 i

a * b  =   (5/2)(1/2)  =   5/4

Oops it hought it was divide by 5 to get remainder of 3.

n = 29  =  3(8)  + 5

Now I have to repost it because mods are probably gonna lock this thread since there is an "answer" already.

I wrote that answer... Anyway, this question was not answered there, sooooo...

Hello Melody,

Are there restrictions that there is one ball per box?

If there is a restriction, then yes, 3!=six(6) ways.

If there are no restrictions, ball one can go in the red, white, or blue box...this also happens for ball two and ball three...

Then, there are 3^3=27 ways.

Remember that the choices are independent.

We need at least two three's and three two's...

We have to add one more three and two more two..

 However, 2*3*2*2 is not a perfect cube but 3*3*2*2

We need three  3's and two 2's..

3^3*2^2=27*4=108-smallest positive integer.

Thanks!

Im pretty sure its 108...

EDITED FROM MISTAKE

23

there are two primes between 20 and 30- 23 and 29. 23 gives a remainder of 3, while 29 gives a remainder of 4.

Hi Tertre,

I would like you to think of a simplified problem.

3 balls numbered 1,2 and 3

3 boxes Red, white and blue

By my logic there will be 3!=6 possibilities

By yours, there will be 3^3 = 27 possibilities.

Now draw up a table with the headings, red, white and blue and see if you can work out which of ours is correct.

See if you can find more than 6 solutions   ;)

Nothing is shown, Paresh....

Rock-n-Bowl:  Let R represent the number of games bowled; then the cost will be 2.00 + 3.50R

Strikz:             Let S represent the number of games bowled; then the cost will be 4.50 + 3.00S

If the same amount of money is spent:  2.00 + 3.50R  =  4.50 + 3.00S

Rearranging:                                          3.50R - 3.00S  =  2.50

At 50 cents more per game bowled (3.50 - 3.00), there would have to be 5 games bowled to make the 2.50 difference.

The radius of the outer ring is 5' + 8' + 6'  =  19'.

The circumference of the outer ring is:  C  =  2·pi·r  =  2·pi·19  =  119.38'.

762  * 94  =  71628    ????

thxx

If 30 students had an average of 72, then their total points were 30 x 72  =  2160.

If 6 students had an average of 78, then their total points were 6 x 78  =  468.

Adding the points of both groups:  2160 + 468  =  2628 points

2628 divided by 36 gives an average of 73.

As an percentage, it is 73%.

If you let  x₁ = 0   x₂ = 2pi/3   x₃ = -2pi/3  x₄ = 4pi/3  x₅ = -4pi/3  x₆ = 2pi  x₇ = 8pi/3  x₈ = -8pi/3  x₉ = 4pi

the the sum of cos(3x_i) becomes 9.

yes thank u

Super Savers price   =   $9  off the list price  $39.96

Super Savers price   =   $39.96  -  $9

Super Savers price   =   $30.96

Penny Wise price   =   25%  off the list price  $39.96

Penny Wise price   =   $39.96  -  25% of $39.96

Penny Wise price   =   $39.96  -  0.25  *  $39.96

Penny Wise price   =   $39.96  -  $9.99

Penny Wise price   =   $29.97

Notice that in the first case, we took off $9 from the original price, but in the second case, we took off $9.99 from the original price. At this point, can you tell how much cheaper the second store price is from the first?

Adding  the terms  we  get

5x + 40

So

[5x + 40 ]  / 5  =    24     multiply both sides  by  5

5x +  40   =  120        subtract  40 from both sides

5x =  80     divide both sides by 5

x = 16

By the rational root theorem, we can see that one(1) is root.

Now, create a synthetic division chart.

-1 |_1__1___-3____1_

This leaves us with the polynomial: x^2 + 2x - 1=0

Here, we can use the quadratic formula to get: \(x_1=-1+\sqrt{2}, x_2=-1-\sqrt{2}\).

Thus, the roots of the equation p(x)=x^3+x^2-3x+1 are \(x_1=1, x_2=-1+\sqrt{2}, x_3=-1-\sqrt{2}\),

THANKS!