P(0 boys chosen ) = C( 15.7) / C(30,7)
P( 1 boy chosen = [ C(17,1) * C(15,6) ] / C(30,7)
P (2 boys chosen = [ C (17,2) * C(15,5) ] / C (30, 7)
So.....the probability is
[C(15,7) + C(17,1)* C(15,6) + C(17,2) *C( 15,5)] / C(30,7) ≈ 25%
The constant term will be
C(8,4) ( 6x)^4 ( 1/(3x))^4 =
70 * ( 1296 x^4) ( 1/ (81x^4) =
1120
i pretty sure the answer is 6
if im wrong im sorry
An even simpler solution
If x + y = 6
Then x + y cannot also = 4
So......these lines do not intersect....so....no solution
hope this helps <3
d. y = cot 2x
See my answer under your original post
He sold (2/3) of the apples and (4/9) of the oranges
So
(2/3) A = (4/9)O
A = (3/2)(4/9)0
A = (2/3) O
So total avaiable = A + O = (2/3)O + O = (5/3)O
So....fraction sold =
(2/3)A + (4/9)O (2/3)(2/3)O + ( 4/9)O (4/9 + 4/9) O 8/9
_____________ = ___________________ = ____________ = _______ =
(5/3) O (5/3) O (5/3) O 5/3
(8/9) * ( 3/5) = 24 / 45 = 8 / 15
No solution
Two lines, A and B, are represented by the equations given below:
Line A: x + y = 6
Line B: x + y = 4
Solve for x and y
Multiply Line A equation by -1
-x -y = -6
x + y = 4
-------------------(add both equations)
0 + 0 = -2
0=-2
We arrived at a false statement, so no solution for this system of equations
It still does not work
Hey there, Guest!
So, you click on the LaTeX button and then on the Math button, then you pick the first option where there are two bracket-like things.
And if you do it correctly, your fraction should turn out like this: \(\frac{1}{2}\).
Hope this helped! :)
( ﾟдﾟ)つ Bye
(1/2) (25/51) = 25 / 102
So, the answer choice isn't up there, but I assure you that based on the question, the answer should be 1/9.
g = 1/3 k This is given in the Q
then k gives 10 to g and they are equal
g+10 = k - 10 sub in the red equation
1/3 k + 10 = k -10
2/3 k = 20
k = 30 g = 10 originally total 40 calendars
D = ( 14.2 sin ) (41.66 ) / sin 9.68 ≈ 56.1 mi
3x + 26 = x + 20
Absolutely, but I think this way might just be the best way for small cases like this.
It is actually quite efficient if you have a system.
15/3 = 5
15/2 = 7.5
So the highest number has to be 5-7.
5: 1 option
6: 2 options
7: 4 options
You could also use complementary counting, find all numbers that add up to 15, then subtract the ones that don't work for a triangle. :))
=^._.^=
Yep.....THANX ,Chris for noting my error:
Per Chris:
we also need 5pi/4 and 7pi/4 as answers for "theta "
~EP
sec(arcsinu)=1√1−u2
Let arcsinu=A, then sinA=u and we are seeking secA
As sinA=u, cosA=√1−u2
and secA=1√1−u2
Substituting A for arcsinu,
hope this helps
B 424.0ft
sec ( arcsin (u) )
arcsin (u) = θ means that sin θ = u/1 so cos θ = sqrt ( 1 - u^2) / 1 = sqrt (1 - u^2)
sec ( arcsin (u) ) = sec θ = 1 /cos θ = 1 / sqrt (1 - u^2)
Remeber sin = opposite side / hypotenuse in rt triangles opposite side is tower attach point 145 Hypotenuse is what you seek
sin (20) = 145 / h h = 145/ (sin(20) feet = __________ ft You should finish !
Take the sqrt of both sides to get:
sin ( 2 theta) = +-1
2 theta = pi/2 3 pi /2
theta = pi/4 3pi/4
Vertical angles are equal...so....just solve this for x
We can form a triangle with two known a known base and two known base angles
We need to convert bearing to "regular" angles
The first base angle = 90 - 48° 20 min = 41° 40 min = 41.66°
The second base angle = 308° 40 min - 270 = 38° 40min= 38.66°
The other angle of the triangle = 90 - 41.66 - 38.66 = 9.68°
We can use the Law of Sines to find the distance from the ship to the rock = D
14. 2 / sin 9.68 = D / sin 41.66
5/6 ths of (1 - 3/8 - 1/4) is to 20 as 1 is to x
5/6 ( 3/8) / 20 = 1/x
15 / 960 = 1/x
x = 64 in the box
