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Oh, I just realized, Bilbous does not have much knowledge.   (No criticism intended)

Notice he (or her) has used a forward slash in front of the fraction.  That is wrong. It is a backslash.     \

The Backslash indicates that what follows is a function.  That probably does not make much sense to you but don't worry.

Just build up your knowledge a little at a time and the pace will speed up on its own.

Hi Guest,

I will try to solve this.

{CORRECTION}: I did not read that it wanted product

A is between -3, and 1

So the possibilities are -3, -2, -1, 0, 1

B is between -2 and 4

So the possibilities are -2, -1, 0, 1, 2, 3, 4

Not counting zero, A has 3 negative, B has 2 negative

Not counting zero, A has 2 positive, B has 4 positive

A and B must both be negative, or positive

A negative possibiliteis * B negative possibilities = 3/4 * 2/6 = 6/24 = 1/4

A positive possibilities * B positive possibilities = 1/4 * 4/6 = 4/24 = 1/6

1/4 + 1/6 = 3/12 + 2/12 = 5/12

If you use the LaTex box don't worry about the dollar signs.

I never add dollar signs on this site!

Here is my knowledge of LaTeX:

Usually there are dollar signs around the numbers

Function: $f(x)$

Interval: $[2, 1]$

There are backslashes and brackets for polynomials??

\[z^8 +3z^7 +z^6.\]

Fractions use: /frac {1}{2}, (1/2)

That's all I know 

Start with simple things.  Confidence and ability will grow.

Start by opening the latex box and writing

\frac{1}{2}

and you will see it is a fraction.

press ok and whammo, you have a fraction.

If you want to learn on this site you can make your own thread, headed "I'm just practicing Latex"  and use it as your practice thread.

It will be easier to keep track of if you become a member.

**  If you have specific questions you can ask on the forum.

There is "LaTex" coding thread in the sticky topics and there are a great many outside resources as well.

Difference between day 1 and day 2 was 5 student tix and 25 dollars      so each student ticket is 5 dollars

    Day 1 was 1 adult and two student for 18 dollars    so an adult costs  8 dollars .

Very clear solution. :))

Welcome to web2.0calc.

=^._.^=

Hi Guest,

I first listed the facts:

1 adult

2 student

== $18.00

1 adult 

7 student 

== $43.00

Then I created a system of equations to solve:

1a + 2s = 18

1a + 7s = 43

1a = 18-2s

Substution:

18-2s + 7s = 43

5s + 18 = 43

s = 5

If s = 5, then a = 8

1 Adult Ticket = $8.00

1 Student Ticket = $5.00

Area = 2(pi - 2)

(3/5) / 72 = (2/5) / x

x = 48

72 + 48 = 120 

   x     -   2/5 x    - 28   = 44

  3/5 x =  72

x = 120 dollars to start

( 8 + 2\(\sqrt[1/4]{4}\)  + 4 \(\sqrt[1/4]{2}\) + \(\sqrt[1/4]{8}\) )  /  7

a)

Step 1: suppose advin had x dollars at first. 

Step 2: make suitable equations that represents the actual scenario.

Step 3: find the value of x.

b) 

Total amount left= $44.

Total amount spent on books= $28+2/5 of his initial money.

Suppose advin had $x initially.

then, initial money= money left+ money spent

therefore, x=44+(28+(2/5)x ) 

x= 72+2x/5

x-2x/5 = 72

(5x-2x)/5 = 72

3x/5 = 72

x=72(5/3)

x= 120

Therefore,  Advin had total $120 at first.

Arrangel first line into y = mx + b form   where m = slope

y = -3x +8           m = - 3       perpindicular slope = - 1/m = 1/3

arrange second equation into y=mx + b form    (I'll change the 'b' in the question to 'z' to avoid confusion)

- 2x + z y = - 9

y =  2/z  x  - 9 / z         slope    2/z = 1/3       then z = 6     (this is the   'b ' you are looking for )

2x^2 + 2y^2 + 4x + 12y + 6 = 0    divide thru by 2

x^2  + 2x       + y^2 + 6y   =    -6      complete the square for x and y

(x+1)^2         +  (y+3)^2    = - 6  +1 + 9

(x+1)^2         +  (y+2)^2    =   4                        

this is a circle equation of the form     (x-h)^2   + (y-k)^2   = r ^2        center = (h,k) = ( -1,-2)    radius = 2

Let

f(x) = 3x^2 - 2 if x <= 3

f(x) = ax^2 + 7x - 4 if x > 3

Find a if the graph of y = f(x) is continuous.

Hello Guest!

\(f_1(x) = 3x^2 - 2\\ f_1(3) = 3\cdot 9 - 2=25\)

\(f_2(x) = ax^2 + 7x - 4=25\\ f_2(3) = a\cdot 9 + 7\cdot 3 - 4=25\\ 9a=25-21+4=8\)

\(a=\dfrac{8}{9}\)

 a, if the graph of y = f(x) is continuous, is \(\dfrac{8}{9}.\)

The graph of y = f(x) is \(f_1(x) = 3x^2 - 2\ |\ if\ x\ \leq 3\\ f_2(x) = \dfrac{8}{9}x^2 + 7x - 4\ |\ if\ x > 3\)

  !
 

What is the x-coordinate of the point on the x-axis that is equidistant from points A(2,0) and B(0,6)?

Hello Guest!

The distance of the point on the x-axis from the origin is x.

Then the following applies:

\(-x+2=\sqrt{x^2+6^2}\ |\ square \\ x^2-4x+4=x^2+36\\ -4x=32 \)

\(x=-8\)

The x-coordinate of the point on the x-axis is -8.

  !

midpoint = ((x1 + x2) / 2, (y1 + y2) / 2) = (1, 3)

So the answer is 1

2. a + b + c + d + e = 48.

3. The smallest possible sum is 18.

We can write -4 in exponential notation as 4e^(pi*i), so the equation is z^4 = 4e^(pi*i).

By Hamilton's Theorem, the solutions are z = 4^{1/4}*e^(pi*i/4), 4^{1/4}*e^(pi*i/4 + pi/4), 4^{1/4}*e^(pi*i/4 + 2*pi/4), and 4^{1/4}*e^(pi*i/4 + 3*pi/4).  Since 4^{1/4} = sqrt(2) and e^(pi*i/4) = (1 + i)/sqrt(2), the first solution is 1 + i.  Then the other roots work out as

4^{1/4}*e^(pi*i/4 + pi/4) = 1 - i,

4^{1/4}*e^(pi*i/4 + 2*pi/4) = -1 - i, and

4^{1/4}*e^(pi*i/4 + 3*pi/4) = -1 + i.

All integers a that work are a = 2, 12, and -24.

(a) The median term is 3

(b) k = 63.

10 x 9 x 8     x 10   = 7200            1 /7200 chance to win jackpot

You can go on these sites to get started.

answer book says you can