All Answers 358087 Answers

Subtract 3x from both sides of the second equation:

y = 5 - 3x

Substitute this into the first equation:

x + 2(5 - 3x) = 5

or

x + 10 - 6x = 5

-5x = -5

x = 1

Substitute this back into the equation for y

y = 5 - 3*1

y = 2

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Here's one possible interpretation:

Of course this is just one possibility.  As far as the information provided in the question is concerned, T could be anywhere on a circle of radius 35cm centred on P!

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I actually give you kudos for asking the same crappy question differently.

Okay.....

Ieda bakes... 73 Cupcakes.

Melody eats 5.

$${\mathtt{73}}{\mathtt{\,-\,}}{\mathtt{5}} = {\mathtt{68}}$$

So Ieda is left with 68 Cupcakes now.

Now you say that, Ieda then divides them into 13 containers equally...? Okay... 

So... Providing it must be equal in all containers, you will have some leftovers.

$${\frac{{\mathtt{73}}}{{\mathtt{13}}}} = {\mathtt{5.615\: \!384\: \!615\: \!384\: \!615\: \!4}}$$

So.... Now rounding that to the last full number... 5 Cupcakes per Container.

So... $${\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{13}} = {\mathtt{65}}$$

So Ieda has 65 cupcakes that is packed away equally. And we have 3 left.

.....More for Melody to eat....

$${\mathtt{4\,587\,878\,788}}{\mathtt{\,\times\,}}{\mathtt{453\,453}} = {\mathtt{2\,080\,387\,400\,054\,964}}$$

Do you wish for it to be Exact or Approximate?

You are going to need to state what T is.

I vote for all problems that are posted on this site, goes through a 1+1 and 2+2 Captcha. I mean... Seriously.....

You will need a numerical method to find the values of y (in radians) that satisfy this equation.  The following graphs should enable you to get good guesses with which to start:

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In general (x^a)^b = x^(a*b) so

$$(x^\frac{1}{2})^a=x^1$$

$$x^{\frac{a}{2}}=x^1$$

We must have a/2 = 1, so a = 2

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This can be written as:

$$\frac{2}{\sqrt{x}}=3$$

Multiply both sides by the √x and divide both side by 3:

$$\frac{2}{3}=\sqrt{x}$$

Square both sides:

$$x=\frac{4}{9}$$

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$$2yy^{\frac{1}{3}}=0.0002$$

This can be written as:

$$2y^{1\frac{1}{3}}=0.0002$$

Divide both sides by 2

$$y^{1\frac{1}{3}}=0.0001$$

Take log₁₀ of both sides and use the fact that log(x^a) = a*log(x):

$$1\frac{1}{3}\log{y}=\log{10^{-4}}$$

as 0.0001 = 10^-4

Now log(10^-4) is just -4, so

$$1\frac{1}{3}\log{y}=-4$$

or:

$$\frac{4}{3}\log{y}=-4$$

Multiply both sides by 3/4:

$$\log{y}=-3$$

So: y = 10^-3 or y = 0.001

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Assuming d/E is the same as D/E then the equation can be written as:

0.15*(D/E) + 0.15 = 0.2175 +0.06*(D/E)

Subtract 0.06(D/E) from both sides:

0.09*(D/E) + 0.15 = 0.2175

Subtract 0.15 from both sides:

0.09*(D/E) = 0.0675

Divide both sides by 0.09:

D/E = 0.75

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in other words......pie is a food to stop the rats running in your stomach!

and in practical words...pie is the formula to stop the rats running in your teachers head!

ok fine!im editing the answer!no more jokes here!

pie is 22/7 or 3.14, we use it to find the circumference of a cirlce or wherever its required!

A pie is a baked dish which is usually made of a pastry dough casing that covers or completely contains a filling of various sweet or savoury ingredients.

Pies are defined by their crusts. A filled pie (also single-crust or bottom-crust), has pastry lining the baking dish, and the filling is placed on top of the pastry but left open. A top-crust pie, which may also be called a cobbler, has the filling in the bottom of the dish and is covered with a pastry or other covering before baking. A two-crust pie has the filling completely enclosed in the pastry shell.Shortcrust pastry is a typical kind of pastry used for pie crusts, but many things can be used, including baking powder biscuits,mashed potatoes, and crumbs.

Pies can be a variety of sizes, ranging from bite-size to ones designed for multiple servings.

-WIKIPEDIA

thats a good answer heureka . i'd give you a point because i was really struggling to get the answer to this.....Thanks!

(i just wanted to win mod's 3 points.....)

Half of a certain number is subtracted from 26 and the result is then tripled, and the answer is 18. Find the number.

$$\left(26-\frac{x}{2}\right)*3=18 \quad | \quad :3\\\\
26-\frac{x}{2}=6 \quad | \quad -6 + \frac{x}{2}\\\\
\frac{x}{2}=20 \quad | \quad *2\\\\
x=40$$

The number is 40

i have no idea wat she is talking about? lol

-2x + 2 = -7x + 17

-2x + 7x + 2 = -7x + 7x + 17

5x + 2 = 17

5x + 2 - 2 = 17 - 2

5x = 15

x = 3

-17 = 2w + 7 - 5w

-17 = -3w + 7

-7 -17 = -3w + 7 - 7

-24 = -3w

8 = w

Well...it SEEMED pretty convincing, Melody....!!!!

I still gave you points........!!!!

You came to the right place.

This is a calculator site.

How lucky are you?

Never mind my older post. 

According to Wolfram Alpha there are 506 days since 20th Sept 2013. If you take 30 tablets on a routine basis, the calculation should be like this:

506/30 = 16 "and something".    This means that you have used 16 packages and is taking tablets from your 17th. 

16 * 30 = 480     This means that there are a total of 480 pills in 16 packages.

506 - 480 = 26      This means that you have taken 26 tablets from your 17th (and last) package. 

30 - 26 = 4      This means that there should be 4 tablets left

This should hold if you took one tablet 20th Sept 2013, and none thus far today. 

NB: I might have done an error somewhere in my calculation, that I don't know about. Maybe CPhill or Melody or someone could calculate this/control my calculation. 

When one take tablets over several months, one might easily forget a tablet once or twice. For some medications it is very important to not miss a tablet. For others, it doesn't really matter. Ask your doctor if you are in doubt!

BUMMER!      LOL    :D

Thanks Bertie :))